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Transcript
Algebra 2 – First Semester Review
1. Solve 16b  4  22b  8
11. 2x2 + 6x – 4 = 0.
2. Write the standard form of the equation of the
line that passes through the point (3, -5) and is
parallel to the line 6x + 2y = 8.
12.
3. Solve the inequality for x: 3x  4  5 .
13. Given the following quadratic equation, how
many and what type of solutions exist?
x  x6
Check for extraneous solutions!
y  x 2  6x  9
4.
Solve for x: | 5 – 3x | = 9
5. When solving the following linear system, what
is the value of y?
4x  3y  4
.
2x  y  7
14. In completing the square, what number must be
added to each side of the equation?
x 2  8 x  12
(x2 + 8x + ___) = 12 + ___
15. Put in vertex form: y = x2 - 4x + 9.
6. Solve the system and find x:
x - 3y + 3z = -4
2x + 3y - z = 15
4x - 3y - z = 19
For 7-12: Solve for x.
7.
x2 – 18 = 3x
8. 2x2 – 4x – 30 = 0
9.
x 2  8 x  36  0 .
10. 5x2 – 30 = –130
16. What is the equation of the parabola whose
vertex is at (3, -2) and contains the point (2, 0)?
17. The function y  16 x 2  1800 gives a
jumper’s height y in feet after x seconds for a jump
from 1800 ft. How long is a free fall if the
parachute opens at 800 ft?
19. Divide: (3x3 – 17x2 + 15x – 25) ÷ (x – 5)
20. 2 x  3 2 x 3  7 x 2  17 x  3
21. Write the polynomial in standard form with
the given zeros: 0, 5, 2
1st Semester Exam
Algebra 2
21. The graph of f ( x)  x 2 is translated 5 units to
the right and 4 units up. What is the equation of
the translated graph?
Page 2
31. Evaluate: 64
2
3
32. Which of the following is equivalent to x 3 ?
22. Graph: y = | x + 3|
33. Factor: 27x3 – 8
23. Graph: y = (x – 4)2 + 3
34. Factor: 9x2 – 42x + 49:
24. Graph : f(x) = x3 – 5x2 + 4x = 0
6 x  3 y  12

25. Graph the system of inequalities:  y  x
x  3

35. Factor completely: 2x4 – 32:
36. Simplify
26. f ( x) 
x2
5
What is f
1
?
37. (8 - 3i)(9 + 2i) =
For #27-28, Use the equation below:
Given t(n) = 2n2 – 3n + 4
27. Find t(–4) =
28. Find t(2x) =
29. Given f x   x 2 and g x  x  6 , find f(g(x)).
 2x 4 y 6
30. Simplify: 
5
 xw
4  2i
5  3i



3
38. (7 + 5i) - (-16 - 9i) =