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Lecture 31 Chapter 34 Electromagnetic Waves Review • For an RLC circuit – Voltages add up to emf E = vR + vC + vL – Maximum current given by Em I= Z – Impedance defined as Z = R + ( X L − XC ) 2 2 – Phase constant defined as X L = ωd L 1 XC = ωd C XL − XC tan φ = R Review • For RLC circuit, resonance and the max current I occurs when ωd = ω • For an ac circuit, define rms values I V I rms = V rms = 2 2 1 ωd = ω = LC E rms • Average power dissipated to thermal energy Pavg = I 2 rms R E = 2 Pavg = Erms I rms cosφ Review • Transformer – – 2 coils (primary and secondary) wound around same iron core – Transformation voltage and current are related to ratio of the number of turns in the coils NS VS = VP NP NP IS = IP NS – Equivalent resistance seen by 2 generator R eq NP R = NS EM Waves (1) • Electromagnetic waves – – Beam of light is a traveling wave of E and B fields – All waves travel through free space with same speed EM Waves (2) • Generate electromagnetic (EM) waves – – Sinusoidal current in RLC causes charge ω= and current to oscillate along rods of antenna with angular frequency ω – Changing E and B fields form EM wave that travels away from antenna at speed of light, c 1 LC EM Waves (3) • E and B fields change with time and have features: – E and B fields ⊥ to direction of wave’s travel – transverse wave – E field is ⊥ B field – Direction of wave’s travel is given by cross product r r E×B – E and B fields vary • Sinusodially • With same frequency and in phase EM Waves (4) • Write E and B fields as sinusoidal functions of position x (along path of wave) and time t E = E m sin( kx − ω t ) B = Bm sin( kx − ω t ) • Angular frequency ω and angular wave number k • E and B components cannot exist independently ω = 2πf k= 2π λ EM Waves (5) • Speed of wave is v = ω k • Using definition of ω and k, velocity is 2π k= ω = 2π f λ ω 2πf v= = = fλ k 2π / λ • In vacuum EM waves move at speed of light v = c = fλ c = 3 × 10 m / s 8 EM Waves (6) • Use Faraday’s and Maxwell’s laws of induction r r r r dΦ B dΦ E ∫ B • ds = µ 0ε 0 ∫ E • ds = − dt dt • Can prove that speed of light c is given by (proof done inEsection 34-3) 1 c= m Bm c = µ 0ε 0 c = 3 × 10 m / s 8 • Light travels at same speed regardless of what reference frame its measured in EM Waves (7) • EM waves can transport energy and deliver it to an object it falls on • Rate of energy transported per unit area is given by Poynting vector, S, and defined as r 1 r r S= E×B µ0 • SI unit is W/m2 • Direction of S gives wave’s direction of travel EM Waves (8) • Magnitude of S is given by S= 1 µ0 EB • Found relation c = Em Bm • Rewrite S in terms of E since most instruments measure E component rather than B E S = E µ0 c • Instantaneous energy flow rate is 1 S = 1 cµ 0 E 2 EM Waves (9) • Usually want time-averaged value of S also called intensity I I = S = energy / time = power avg I = [ E ] µ c 1 2 avg 0 = [ E µ c 1 area 2 m ave area ave sin 2 ( kx − ω t ) ] avg 0 • Average value over full cycle of sin 2 θ = 1 / 2 Em • Use the rms value Erms = 2 • Rewrite average S or intensity as I = 1 E 2 µ 0c rms EM Waves (10) • Find intensity, I , of point source which emits light isotropically – equal in all directions power energy / time I = S avg = = area ave area ave • Find I at distance r from source • Imagine sphere of radius r and area Power PS I = = 2 Area 4π r • I decreases with square of distance A = 4π r 2 EM Waves (11) • Checkpoint #2 – Have an E field shown in picture. A wave is transporting energy in the negative z direction. What is the direction of the B field of the wave? • Poynting vector gives r 1 r r S= E×B µ0 • Use right-hand rule to find B field Positive x direction