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ENGR&204 Spring 2012 Homework 6 Due the last class of the term (before the final test) Use the cookbook! Find i for t > 0 if the circuit is in the steady state at t = 0-. Find v for t > 0 if the circuit is in the steady state at t = 0-. Find v1 for t > 0 if there is no initial stored energy. Find i for t > 0 if the circuit is in the steady state at t = 0-. A laser pulse power circuit is shown in the figure below. It is required that v(0) = 7.0 v and i(0) = 3.5 A. Find the R, the resistance required for these conditions. Assume that the switch has been closed for a long time before it is opened at t = 0. R t=0 2 20 V 1H 8 v(t) 3F i To = 0 the coil acts like a short and the capacitor acts like an open (it is fully charged). At t = 0 the circuit will reduce to: The current in the 8 ohm resistor is (7 v/8 = 0.875 A. KCL at the top node gives the current in the resistor R to be 3.5 A + 0.875 A = 4.375 A. Then KVL clockwise around the loop containing R is -20 + 4.375(R) +7 = 0. Solve for R gives 2.97 . The circuit is in the steady state before the switch closes at t = 0 s. The switch stays closed for 1.5 s and then opens. Find i(t) for t > 0 s. Use step functions to create the voltage shown. Find the step response i. (This means vg = u(t) volts)