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Lecture 3 Gauss’s Law Ch. 23 • Physlet http://webphysics.davidson.edu/physletprob/ch9_problems/ ch9_2_gauss/default.html • Topics –Electric Flux –Gauss’ Law –Coulombs Law from Gauss’ Law –Isolated conductor and Electric field outside conductor –Application of Gauss’ Law –Conductor in a uniform field • Demo –Faraday Ice pail: metal cup, charge ball, teflon rod, silk, electroscope, electrometer • Elmo 1 –Problems 29 Examples of Field Lines 2 Electric Flux Electric flux is the number of Electric field lines penetrating a surface or an area. Call it . r r Electric Flux (E cos )A E A r where A An̂ 3 r r Electric Flux (E cos )A E A 1. E A So, 0 EA cos 0 EA A 2. E A r where A An̂ E 0 Let 45 Then, EA cos 45 0.707EA A E 4 Gauss’s Law - Powerful relationship between charges and electric fields through closed surfaces r qenc — E dA 0 • Gauss’s law makes it possible to find the electric field easily in highly symmetric situations. • If there is no charge inside, then the flux is 0 net 0 • Let look at an example 5 Derivation of Gauss’ Law from a point charge and using Coulombs law: Summary of steps • Start with an isolated point charge. • Choose a sphere around the charge. • Calculate net r r — E dA • Show that net qenc 0 6 Start with a point charge. Note that the electric lines of flux are radial for a point charge Choose a spherical surface to simplify the calculation of the flux E 7 • Calculate the net flux through the closed surface. Net Flux = net r r — E dA E cosdA EdA kq For a Point charge E 2 r En cos 0 1 kq EdA 2 dA r nˆ kq kq 2 dA 2 ( 4r 2 ) r r 4kq 4k 1 0 net where 0 8.85x10 qenc 0 Gauss’ Law dA 12 dA nˆdA C2 Nm2 8 Valid even when charges are not at the center Find the electric flux through a cylindrical surface in a uniform electric field E Uniform electric field Cylindrical surface choose because of symmetry No charge inside Flux should be 0 We want to calculate E dA 9 Remember E nˆ EA A nˆ E A En A 0 A 0 En E cos E nˆ A En A E cos A 10 E dA a. E cos180dA EdA ER b. E cos90dA 0 c. E cos 0dA EdA ER 2 2 What would be the flux if the cylinder were vertical ? Suppose it were any shape? 11 Flux from a. + b. + c. 0as expected Gauss’ Law net qenc 0 This result can be extended to any shape surface with any number of point charges inside and outside the surface as long as we evaluate the net flux through it. 12 Approximate Flux E A Exact Flux E dA dA nˆdA Circle means you integrate over a closed surface. 13 You should know these things 1 2 3 4 5 6 7 8 9 The electric field inside a conductor is 0. The total net charge inside a conductor is 0. It resides on the surface. Find electric field just outside the surface of a conductor. Find electric field around two parallel flat conducting planes. Find electric field of a large non-conducting sheet of charge σ. Find electric field of an infinitely long uniformly line of charge λ. Find E inside and outside of a long non-conducting solid cylinder of uniform charge density ρ. Find E for a thin cylindrical shell of surface charge density σ Find E inside and outside a solid non-conducting sphere of uniform charge density ρ. 14 1. Electric field inside a conductor is 0. Why? • Inside a conductor in electrostatic equilibrium the electric field is always zero. (averaged over many atomic volumes) • The electrons in a conductor move around so that they cancel out any electric field inside the conductor resulting from free charges anywhere including outside the conductor. This results in a net force of 0 on any particular charge inside the conductor. r F qE 15 2. The net charge inside a conductor is 0. • Any net electric charge resides on the surface of the conductor within a few angstroms (10-10 m). • Draw a Gaussian surface just inside the conductor. We know everywhere on this surface E=0. • Hence, the net flux is zero. From Gauss’s Law the net charge inside is zero. • Show Faraday ice pail demo. 16 3. Find electric field just outside the surface of a conductor • The electric field just outside a conductor has magnitude and is directed perpendicular to the surface. 0 • Draw a small pill box that extends into the conductor. Since there is no field inside, all the flux comes out through the top. EA q 0 E 0 A 0 17 4. Find electric field around two parallel flat conducting planes. 1 E 0 E 1 0 E 2 1 0 18 6. Find the electric field for a very long wire of length L that is uniformly charged. n̂ 19 6. Find the electric field for a very long wire of q length L that is uniformly charged. L q — E dA n Gauss's Law 0 endcaps+sides En E n̂ n̂ sides — E dA E — dA E 2 rh n endcaps side h 0 E 2rh 0 2k E r̂ r 2k E r E n̂ 90 Cos90 0 E 20r 20 9. Electric field inside and outside a nonconducting solid uniformly charged sphere • Often used as a model of the nucleus. • Electron scattering experiments have shown that the charge density is constant for some radius and then suddenly drops off at about 2 3 1014 m. For the nucleus, 26 C 10 m3 Charge density per unit volume R 21 10 14 m Electric Field inside and outside a uniformly charged sphere Q= Total charge Q 4 3, rR R 3 r̂ = Z 1.6 10-19C Inside the sphere: To find the charge at a distance r<R Draw a gaussian surface of radius r By symmetry E is radial and parallel to normal at the surface. By Gauss’s Law: q — E dA n 0 3 4 r q E 4r 2 3 0 0 r E 30 r E r̂ 3 0 22 Electric Field inside and outside a uniformly charged sphere Q 4 3, rR R 3 Q= Total charge = Z 1.6 10-19C Outside the sphere: 3 4 R q E 4r 2 3 0 0 R 3 E 3 0 r 2 Same as a point charge q 23 Electric field vs. radius for a nonconducting solid sphere filled with a uniform charge distribution Er r Er Er 1 r2 24 Problem 23 -4 A charge of - 5uC is placed inside a neutral conducting shell at R/2. What is the charge on the inner and outer surface of the shell? How is it distributed? What are the field lines inside and outside the shell? 25 Problem 23 -4 26 Chapter 23 Problem 29 Elmo A long straight wire has a fixed negative charge with a linear charge density of magnitude 3.1 nC/m. The wire is to be enclosed by a coaxial, thin walled, nonconducting cylindrical shell of radius 1.8 cm. The shell is to have positive charge on its outside surface with a surface charge density that makes the net external electric field zero. Calculate the surface charge density. 27 Here is a essay question you should be able to answer based on our ideas so far 1) Suppose you put a neutral ideal conducting solid sphere in a region of space in which there is, initially, a uniform electric field. a) Describe (as specifically as possible) the electric field inside the conductor. b) Describe the distribution of charge in and on the conductor. c) Describe the electric field lines at the surface of the conductor. 28 External Electric field penetrates conductor E Free charges inside conductor move around onto the surface in such a way as to cancel out the field inside. E 29 E=0 inside conducting sphere E E 30 Orientation of electric field is perpendicular to surface E If the electric field were not perpendicular, then there would be a component of electric field along the surface causing charges to accelerate on the surface and it would not be in electrostatic equilibrium contrary to experience. 31 More questions to ask your self 2) Suppose you put some charge on an initially-neutral, solid, perfectly-conducting sphere (where the sphere is not in a pre-existing electric field). – Describe the electric field inside the conductor, – Describe the electric field at the surface of the conductor, and outside the conductor as a result of the unbalanced charge. – Describe the distribution of the charge in and on the conductor. 3) Repeat questions 1-3 for the case of a hollow perfectlyconducting spherical shell (with the interior being vacuum). 4) How would your answers to questions 1-4 change if the conductor had some shape other than spherical? 32