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OVER BOOKED? A FACEBOOK EXPERIMENT To test the claim that the average teenager uses Facebook for only 5 hours a week 2 • Own Facebook account used • Number Assignment + Random Digit Table = SRS •100 subjects • Standardized out of 594 Question friends 3 Facebook Empirical Data 1 4 4 5 5 5 6 10 10 10 10 10 10 10 11 11 12 12 12 12 12 13 14 14 14 14 14 15 15 15 15 15 15 15 15 15 16 16 16 17 17 17 17 18 18 18 19 20 20 20 20 20 21 21 22 22 22 23 24 24 24 24 25 25 25 26 27 27 27 28 28 29 29 29 29 29 29 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 35 •Empirical data is translated into appropriate graphical displays. 4 Weekly Facebook Time Boxplot Weekly Facebook Time Histogram 40 35 30 29 q1 25 Hours 40 min 20 20 median max 15 14 q3 Frequency 35 30 20 10 0 10 Hours 5 0 1 5 Facebook.com claims that the average teenager spends five hours a week using Facebook. [Using Facebook means actually using its features and not just having it open]. I believe that a teenager uses Facebook for longer than five hours a week. 𝐻𝑜 : μ = 5 hours A teenager uses Facebook an average of 5 hours a week 𝐻𝑎 : μ > 5 hours A teenager uses Facebook for longer than 5 hours a week n = 100 ∝ = 5% 6 A One Sample Mean T-Test…because the population standard deviation is unknown & a mean ≠ proportion Conditions: •The distribution is an SRS •Due to the Central Limit Theorem (CLT) the population is normal since n>40 7 𝑥−𝜇 𝑡= 𝑠 𝑛 𝑡= 20.23−5 8.32 100 t = 18.3 Using TI-83 T-test: p-value = .00000000007 * Can not sketch critical region/value because p-value is too small 8 A mean of 20 hours would occur .000007% of the time if the population mean is 5 hours. So we can safely reject 𝐻 at 𝑜 the 5% significance level. And conclude that a teenager uses Facebook for more than 5 hours a week! 9 I want to estimate the mean time a teenager spends on Facebook a week. Since we do not know 𝜎 , I will use the one sample t-interval. The data was collected via a random experiment. Due to the Central Limit Theorem (CLT) the population is normal since n>40 Confidence Interval = 95% 10 𝑥±𝑡 ∗ 𝑠 𝑛 20 ± (1.984) 8.32 100 = 18.579 to 21.881 hours I am 95% confident that the mean time a teenager spends on Facebook a week is between 18.579 to 21.881 hours 11 Strengths & Weaknesses… Standardized Question Only My FB Friends Inaccurate Answers Population Mean is National Unclear What Type of Usage Large # of Subjects 12