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Chapter 3: Electrons in atoms Learning outcomes: Energy levels and shapes of orbitals Electronic configurations Ionisation energy, trends across a period The quantum mechanical model How are electrons arranged? Electrons are not evenly spread but exist in layers called shells. The arrangement of electrons in the shells is called the electron structure or electronic configuration. 1st shell n=1 Max:2 n2 2nd shell n=2 3rd shell n=3 Each shell has a maximum number of electrons that it can hold. Electrons fill the shells nearest the nucleus first. 1st shell holds a maximum of 2 electrons 2nd shell holds a maximum of 8 electrons 3rd shell holds a maximum of 18 electrons Time for a break and practice Please make check-up 1 on page Simplified electron configuration 7N 2, 5 17Cl 2, 8, 7 + 11Na 2, 8 8O 2- 2, 8 2nd shell holds a maximum of 8 electrons 1st shell holds a maximum of 2 electrons For “ion” the number of proton is NOT the same as electrons Electronic configuration This model assumes the electrons have the same location and energy Until it was discovered that electrons have different locations and energy Li Li+ + e- (1st ionisation energy: E1) Li+ Li2+ + e- (2nd ionisation energy: E2) Li2+ Li3+ + e- (3rd ionisation energy: E3) E1 ≠ E2 ≠ E3 Ionisation energy Li Li+ + e- (1st ionisation energy: E1) Li+ Li2+ + e- (2nd ionisation energy: E2) Li2+ Li3+ + e- (3rd ionisation energy: E3) Li 2,1 Which electron will be easiest to remove? E1 < E2 < E3 ΔHi1 < ΔHi2 < ΔHi3 Table 3.2 in the book on p. 35 For every element, the successive ionisation energy increases; for every next electron it is more difficult to remove We can in theory continue removing electrons until only the nucleus is left We call this sequence the “successive ionisation energy” Sometimes we find a big gap/jump in ionisation energy Example: sodium The first ionisation energy is quite low, it is likely quite far from the nucleus The 2nd to the 9th ionisation energy are in a gradual successive increase indicating these electrons are in the same shell The 10th and 11th electrons have high ionisation energies compared to the rest, they must be near the nucleus. The jump between the 9th and 10th suggests a change in shell Factors affecting the first ionization energy Nuclear charge (number of protons) the bigger nuclear charge, the higher 1st ionization energy. Atomic radius (distance effect) the bigger atomic radius, the lower 1st ionization energy. Shielding effect (number of shells) the bigger Shielding effect, the lower 1st ionization energy The first ionization energies of the first 20 elements in the periodic table is shown below: first ionisation energy (kJ per mole) Variation of first ionisation energy with atomic number for the first twenty elements 2500 2000 1500 1000 500 0 0 5 10 atomic number 15 20 Worked example The model of the atom A model is what fits logic, experimental observations and mathematical calculations Symbol Simple electronic configuration (last number is Group) 17Cl 1st shell, with a maximum of 2 electrons 2, 8, 7 2nd shell, with a maximum of 8 electrons Number of shells (=period) 3 3nd shell, with a maximum of 18 electrons Symbol Simple electronic configuration (last number is Group) Number of shells (=period) 6C 2, 4 2 10Ne 2, 8 2 11Na 2, 8, 1 3 19K 4 Where in the atom is the electron? According to quantum mechanics it is most likely to find the electron for the of the H-atom at 0.0000000000529 meter (52.9 pm) from the nucleus Shells n=2 n=1 Quantum shell Principal quantum shells (n=1, n=2 etc.) Remember for each the max number of electrons is 2n2 (so for n=2, max 8 electrons) We know from experiments and calculations these 8 electrons have different energies…. so we need a new model of the atom where we can distinguish between electron energy Subshells The quantum mechanical model Simplified model Realistic model Principal quantum shell Number of Sub-shells Name of the Sub-shell Max. number of electrons n=1 1 1s 2 n=2 2 2s 2p 2 6 n=3 3 3s 3p 3d 2 6 10 Subshells and their shapes Atomic orbital is a space around the nucleus holding 1 or 2 electrons Where in the atom are the electrons? Simple electronic configuration Complicated electronic configuration 2He 2 1s2 Principle Sub-shell quantum shell energy n=1 2 1s Number of electrons Where in the atom are the Simple electronic configurationelectrons? Complicated electronic configuration 8O 1s22s22p4 2, 6 energy n=2 n=1 4 2 2p (e<6) 2s (e<2) 2 1s (e<2) Where in the atom are the Simple electronic configurationelectrons? Complicated electronic configuration 11Na 2, 8, 1 n=3 energy n=2 n=1 1 6 2 2 3d (e<10) 3p 3s (e<6) (e<2) 2p (e<6) 2s (e<2) 1s (e<2) Where in the atom are the electrons? 4f n=4 energy n=3 n=2 n=1 4d (e<10) 4p (e<6) 3d (e<10) 4s (e<2) 3p (e<6) 3s (e<2) 2p (e<6) 2s (e<2) 1s (e<2) Subshells and atomic orbitals From simple to complicated electron configuration to noble gas electronic configuration notation Element: 8O 17Cl 19K 35Br Simple: 2, 6 2, 8, 7 Complicated: Noble gas: 1s22s22p4 [He] 2s2sp4 1s22s22p63s23p5 [Ne] 3s23p5 Note the following: Potassium: 1s22s22p63s23p64s1 The 3d subshell: 3d<4p Chromium and copper are exceptions: Cr: [Ar] 4s13d5 rather than [Ar] 4s23d4 and Cu: [Ar] 4s13d10 rather than [Ar] 4s23d9 The blocks of the periodic table Elements in Group 1 and Group 2 are in the s-block and have their outer electrons in an s subshell. Elements in Group 3 to 18 have outer electrons in a p subshell. Elements that add electrons to the d subshells are called the d-block elements. Use the electronic configuration to find the group …s2 is in group: …p1 is in group: …p3 is in group: …p6 is in group: …d3 is in group: …d7 is in group: In which period, group and block of the following electron configuration? period 1s22s22p5 1s22s22p63s23p64s23d104p2 1s22s1 1s22s22p63s2 1s22s22p63s23p64s23d5 group block RULES FOR FILLING ENERGY LEVELS Aufbau Principle “Electrons enter the lowest energy orbital first” Pauli’s Exclusion “Sub-Orbitals can hold a max. of 2 electrons provided they have opposite spin” Hund’s Rule “Orbitals of the same energy remain singly occupied before pairing up. Examples N = 1s22s22p3 O = 1s22s22p4 From simple to complicated electron configuration 2, 5 becomes 1s22s22p3 7N 8O 2- 17Cl + 19K 2, 6 becomes 1s22s22p6 2, 8, 7 becomes 1s22s22p63s23p5 2, 8, 8 becomes 1s22s22p63s23p6 Ionisation: trend across a period General increase across period Rapid decrease between last element of a period and 1st of a new period Be and B because 2s and 2p N and O The first ionization energies of the first 20 elements in the periodic table is shown below: first ionisation energy (kJ per mole) Variation of first ionisation energy with atomic number for the first twenty elements 2500 2000 1500 1000 500 0 0 5 10 atomic number 15 20 Ionisation: Trend down a group General trend decrease further away from the nucleus increased shielding despite increased nuclear charge Li = 519 kJ/mol Na = 494 kJ/mol K = 418 kJ/mol Rb = 403 kJ/mol Worked example