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Do Now 12/21/11 Copy HW in your planner. Cumulative Test Chapter 1-5 tomorrow Text p. 359, #4-14 even 22-36 even. Text p. 366, #16-32 even, 36 & 40. Text p. 372, #10-24 even, 30-34 even, 38, 40 In your notebook, answer the following question. Outside of the math classroom, where have you heard phrases such as “at least” or “no more than”? Give examples. How would you write the phrases mathematically? Chapter 6 Preview “Solving and Graphing Linear Inequalities” (6.1) Solve Inequalities Using Addition and Subtraction (6.2) Solve Inequalities Using Multiplication and Division (6.3) Solve Multi-Step Inequalities (6.4) Solve Compound Inequalities Winter break (6.5) Solve Absolute Value Equations (6.6) Solve Absolute Value Inequalities (6.7) Graph Linear Inequalities in Two Variables Section 6.1 “Solve Inequalities Using Addition and Subtraction” INEQUALITIES – mathematical sentence formed by placing a <, ≤, >, or ≥ between two expressions. 11 - a ≤ 121 Writing Equations with Inequalities Symbol Meaning Key phrases = Is equal to The same as < Is less than Fewer than ≤ Is less than or equal At most, no more to than > Is greater than More than ≥ Is greater than or equal to At least, no less than On a number line, the GRAPH OF AN INEQUALITY is the set of points that represent ALL SOLUTIONS of the inequality. “Less than” and “greater than” are represented with an open circle. Graph x < 8 5 6 “Less than or equal to” and “greater than or equal to” are represented with a closed circle. 8 9 7 8 9 10 11 Graph x ≥ 11 10 11 12 13 14 15 Write an inequality represented by the graph. SOLUTION The closed circle means that 8 is not a solution of the inequality. Because the arrow points to the left, all numbers less than 8 are solutions. ANSWER An inequality represented by the graph is x < 8. Write an inequality represented by the graph. SOLUTION The closed circle means that – 2.5 is a solution of the inequality. Because the arrow points to the right, all numbers greater than – 2.5 are solutions. ANSWER An inequality represented by the graph is x > – 2.5. Solving an Inequality… Isolate the variable! Get ‘m’ by itself. To get the ‘m’ by itself get rid of “adding 4.” Do the opposite. “Subtract 4.” m + 4 < 12 - 4 -4 m<8 Whatever you do to one side of the Inequality you must do the other side. 5 6 7 8 9 10 11 Solving an Inequality… Isolate the variable! Get ‘n’ by itself. To get the ‘n’ by itself get rid of “subtracting 5.” Do the opposite. “Add 5.” n-5≥ 6 + 5 +5 n ≥ 11 Whatever you do to one side of the inequality you must do the other side. 8 9 10 11 12 13 14 15 Solve x – 5 > -3.5 Graph your solution x – 5 > – 3.5 +5 +5 x > 1.5 Write original inequality. Add 5 to each side. Simplify. ANSWER The solutions are all real numbers greater than 1.5. Check by substituting a number greater than 1.5 for x in the original inequality. Solve a real-world problem LUGGAGE WEIGHTS You are checking a bag at an airport. Bags can weigh no more than 50 pounds. Your bag weighs 16.8 pounds. Find the possible weights w (in pounds) that you can add to the bag. SOLUTION Write a verbal model. Then write and solve an inequality. 16.8 + w ≤ 50 Solve a real-world problem 16.8+ w < 50 16.8 + w – 16.8 < 50 – 16.8 w ≤ 33.2 ANSWER You can add no more than 33.2 pounds. Write inequality. Subtract 16.8 from each side. Simplify. Section 6.2 “Solve Inequalities Using Multiplication and Division” INEQUALITIES – mathematical sentence formed by placing a <, ≤, >, or ≥ between two expressions. 11 - a ≤ 121 Solve 7 x 91 . Graph your solution 7x > 91 7 7 Write original inequality. Divide each side by 7. x > 13 Simplify. Graph x > 13 10 11 12 13 14 15 16 x Solve 5 Graph your solution. 4 x < 5. 4 4 x <4 5 4 x < 20 Write original inequality. Multiply each side by 4. Simplify. ANSWER The solutions are all real numbers less than 20. Check by substituting a number less than 20 in the original inequality. Solve Inequalities When Multiplying and Dividing by a NEGATIVE” Multiplying and/or dividing each side of an inequality by a NEGATIVE number only produces an equivalent inequality IF the inequality sign is REVERSED!! m 1.6 Solve 7 m – 7 < 1.6 m – 7 – 7 > – 7 1.6 m > – 11.2 Write original inequality. Multiply each side by – 7. Reverse inequality symbol. Simplify. ANSWER The solutions are all real numbers greater than – 11.2. Check by substituting a number greater than – 11.2 in the original inequality. Solve 3x .24 –3x > 24. –3x < 24 –3 –3 x<–8 Write original inequality. Divide each side by –3. Reverse inequality symbol. Simplify. Section 6.3 “Solve Multi-Step Inequalities” The steps for solving two-step and multi-step equations can be applied to linear inequalities. Solving Multi-Step Inequalities STEP 1STEP 2STEP 3STEP 4STEP 5STEP 6- Use distributive property and combine like terms. Collect variables on one side of the inequality. “Undo” addition and/or subtraction. “Undo” multiplication and/or division. Solve for the variable. Check your work. REMEMBER!!!!! Multiplying and/or dividing each side of an inequality by a NEGATIVE number only produces an equivalent inequality IF the inequality sign is REVERSED!! Solve Solve 3x 3x–– 77<<8.8.Graph Graphyour your solution. solution. 3x – 7 < 8 3x < 15 x<5 Write original inequality. Add 7 to each side. Divide each side by 3. ANSWER The solutions are all real numbers less than 5. Check by substituting a number less than 5 in the original inequality. Solve – 0.6(x – 5) < – 15 –0.6(x – 5) <– 15 –0.6x + 3 < – 15 – 0.6x –< 12 x –> –20 Write original inequality. Distributive property Subtract 3 from each side. Divide each side by – 0.6. Reverse inequality symbol. ANSWER The solutions are all real numbers greater than equal -20. Check by substituting a number more than -20 in the original inequality. Solve 6x – 7 > 2x+17. Graph your solution. 6x – 7 > 2x+17 Write original inequality. 6x > 2x+24 Add 7 to each side. 4x > 24 Subtract 2x from each side. x>6 Divide each side by 4. ANSWER The solutions are all real numbers greater than 6. Solve: 14x + 5 < 7(2x – 3) 14x + 5 < 7(2x – 3) Write original inequality. 14x + 5 < 14x – 21 Distributive property 5 < – 21 Subtract 14x from each side. There are no solutions because 5 < – 21 is false. **HINT** If an inequality is equivalent to an inequality that is false, such as 5 < -21, then the solution of the inequality has NO SOLUTION. 12x – 1 > 6(2x – 1) 12x – 1 > 6(2x – 1) Write original inequality. 12x – 1 > 12x – 6 Distributive property –1>–6 Subtract 12x from each side. All real numbers are solutions because – 1 > – 6 is true. **HINT** If an inequality is equivalent to an inequality that is true, such as -1 > -6, then the solutions of the inequality are ALL REAL NUMBERS . Graphs of “No Solution” and “All Real Numbers” “No Solution” “All Real Numbers” Car Wash Use the sign shown. A gas station charges $.10 less per gallon of gasoline if a customer also gets a car wash. What are the possible amounts (in gallons) of gasoline that you can buy if you also get a car wash and can spend at most $20? Because you are getting a car wash, you will pay $2.09 – 2 $.10 = $1.99 per gallon of gasoline. Let g be the amount (in gallons) of gasoline that you buy. STEP 1 Write a verbal model. Then write an inequality. Price of gasoline (dollars/gallon) 1.99 • Amount of gasoline (gallons) g + + Price of car wash (dollars) 8 < < – Maximum amount (dollars) 20 STEP 2 Solve the inequality. 1.99g + 8 ≤ 20 1.99g ≤ 12 g ≤ 6.03015. . . Write inequality. Subtract 8 from each side. Divide each side by 1.99. You can buy up to slightly more than 6 gallons of gasoline. CHECK You can use a table to check the reasonableness of your answer.The table shows that you will pay $19.94 for exactly 6 gallons of gasoline. Because $19.94 is less than $20, it is reasonable to conclude that you can buy slightly more than 6 gallons of gasoline. Gasoline (gal) Total amount spent (dollars) 0 8.00 1 9.99 2 11.98 3 13.97 4 15.96 5 17.95 6 19.94 24 Homework Text p. 359, #4-14 even 22-36 even Text p. 366, #16-32 even, 36 & 40 Text p. 372, #10-24 even, 30-34 even, 38, 40