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9.1 Radicals and Quadratic Equations By: Brian Levy Honors Geometry Period 9 Contents • Objective: Simplify radical expressions and solve quadratic equations 1. Notes on Radicals 2. Practice with solving radical expressions 3. Practice with solving quadratic equations Notes and Terms • When a number is squared it is simply multiplied by itself – Ex. To find the square of 9 ….. 9X9 = 81 • To find the inverse of squaring a number, you need to find its square root –?So, what’s a square root? Notes and Terms • A square root of a number is one of the two equal factors of that number – The square root of a positive number will be – 1. Positive (+) – 2. Negative (-) – Ex. Square root of 64 is 8…..8X8=64 – Ex. Square root of 64 is -8….(-8)X(-8)=64 Notes and Terms • This is a radical sign – It indicates that you are supposed to find the square root of a number in terms of positive value. 81 • This is a radicand 5 – It is the number or expression under the radical sign. Notes and Terms • Radical Expression is any expression having a term containing a radical sign • Square root radicals are in simplest form when: – View Structure diagram on next slide Notes and Terms Square root radicals In simplest form No fraction appears As a radical No integral radicand Has a square factor Other than 1 No radical is in the denominator Notes and Terms • Properties of Radicals (if x > 0 and y > 0) – 1. xy x y xy y – 2. x y – 3. x y x y y Notes and Terms • If you ever can’t find the square root of a number, remember this helpful table • Numbers on left • Squares on right • This is continuous 1 2 3 4 5 6 7 8 9 10 1 4 9 16 25 36 49 64 81 100 Let’s Practice • Sample 1: 72 72 6 36 2 36 2 2 Let’s Practice • S2 4 4 6 2 6 6 3 6 • S3 2 3 6 9 6 3 Let’s Practice • S4 3 18 2 3 2 2 9 9 19 50 2 10 25 2 2 2 • S5-Simply square the number outside the radical sign. Then, times it by the radicand, without squaring he radicand. 7 2 7 2 49 2 98 Let’s Practice • S6-Remember your brackets! Here’s an example –x² = 28 x 4 7 x 2 7 2 7 Let’s Practice • S7 • z² - 5z = 6 • z² - 5z – 6 =0 to to solution • (z+1) (z-6) =0 • z = -1 or z = 6 • {-1,6} We can solve this equation by using a simple form of the quadratic formula It is crucial to set your equation = to 0 and remember brackets group your final Exercises for Practice • Ex.1-Simplify 2 112 • Ex.3-Simplify 8 18 50 • Ex.2-Simplify 36 121 • Ex.4-Solve • 9x² = 64 Exercises for Practice (Additional) • The best all-around review for section 9.1 is in your 9.1 yellow radicals packet. • On page 7, you will find 30 problems consisting of radical expressions, square roots, and quadratic equations. • On page 8, you can check your work with the answers Mr. Pricci has provided. Answers • Samples S1 : 6 S2: 2 2 6 3 6 S3 : 3 S 4 : 19 2 S 5 : 98 S6 : 2 S 7 : 1,6 7 Answers • Exercises E1 : 8 7 E 2 : 10 2 6 E3 : 11 8 8 E4 : , 3 3 Works Cited Brown, Richard G., et al. Algebra: Structure and Method Book 1. Boston: Houghton Mifflin Company, 1997. Pricci, Vincent. “Radicals Notes.” Clarks Summit. 2008. Rhoad, Richard, et al. Geometry for Enjoyment and Challenge. Boston: McDougal Littell & Company, 1991.