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Transcript
Chapter 4
09/16/2010
© 2010 NTUST
Series Circuits
•
All circuits have three common attributes. These are:
1. A source of voltage.
R1
2. A load.
3. A complete path.
R2
VS +
R3
09/16/2010
© 2010 NTUST
Series Circuits
• A series circuit is one that has only one current path.
R1
VS
R1
R2
VS
R1
R2
R3
VS
R2
R3
R3
09/16/2010
© 2010 NTUST
Series Circuit Rule for Current
• Because there is only one path, the current everywhere is
the same. Why???
For example, the reading on the first ammeter
is 2.0 mA, What do the other meters read?
+ 2.0 mA _
R1
+ 2.0 mA _
R2
VS
_
2.0 mA +
_
2.0 mA +
09/16/2010
© 2010 NTUST
Series Circuits
• The total resistance of resistors in series is
the sum of the individual resistors. Why??
For example, the resistors in a series circuit are 680 W,
1.5 kW, and 2.2 kW. What is the total resistance?
R1
VS
12V
680W
R2
1.5kW
4.38 kW
R3
2.2kW
09/16/2010
© 2010 NTUST
Series Circuit
• Tabulating current, resistance,
voltage and power is a useful
way to summarize parameters in
a series circuit.
R1
VS
12V
680W
R2
1.5kW
R3
2.2kW
Continuing with the previous example, complete the
parameters listed in the Table.
I1= 2.74 mA R1= 0.68 kW V1= 1.86 V
I2= 2.74 mA R2= 1.50 kW V2= 4.11 V
I3= 2.74 mA R3= 2.20 kW V3= 6.03 V
IT= 2.74 mA RT= 4.38 kW VS= 12 V
09/16/2010
P1= 5.1 mW
P2= 11.3 mW
P3= 16.5 mW
PT= 32.9 mW
© 2010 NTUST
Voltage Sources in Series
• Voltage sources in series add algebraically.
For example, the total voltage of the sources
shown is 27 V
+
9V
+
9V
What is the total voltage if one battery is
reversed? 9 V
09/16/2010
+
9V
© 2010 NTUST
Kirchhoff’s Voltage Law
• Kirchhoff’s voltage law (KVL) is generally stated as:
• The sum of all the voltage drops around a single
closed path in a circuit is equal to the total source
voltage in that closed path.
KVL applies to all circuits, but you must apply it to only
one closed path. In a series circuit, this is (of course) the
entire circuit. Why does it works for all circuite??
09/16/2010
© 2010 NTUST
Kirchhoff’s Voltage Law
R1
Notice in the series example given
earlier that the sum of the resistor
voltages is equal to the source
voltage.
I1= 2.74 mA
I2= 2.74 mA
I3= 2.74 mA
IT= 2.74 mA
R1= 0.68 kW
R2= 1.50 kW
R3= 2.20 kW
RT= 4.38 kW
VS
12V
680W
R2
1.5kW
R3
2.2kW
V1= 1.86 V P1= 5.1 mW
V2= 4.11 V P2= 11.3 mW
V3= 6.03 V P3= 16.5 mW
VS= 12 V PT= 32.9 mW
09/16/2010
© 2010 NTUST
Voltage Divider Rule
• The voltage drop across any given resistor in a series
circuit is equal to the ratio of that resistor to the total
resistance, multiplied by source voltage.
VS
Assume R1 is twice the size of
R2. What is the voltage across
R1? 8 V
12 V
R1
R2
09/16/2010
© 2010 NTUST
Voltage Divider
R1
15 kW
VS +
20 V
What is the voltage across R2?
R2
10 kW
The total resistance is 25 kW.
Applying the voltage divider formula:
Notice that 40% of the
source voltage is across
R2, which represents
40% of the total
resistance.
R 
 10 kW 
V2   2 VS  
 20 V  8.0 V
 25 kW 
 RT 
09/16/2010
© 2010 NTUST
Voltage Divider
• Voltage dividers can be set up for a variable output
using a potentiometer. In the circuit shown, the output
voltage is variable.
What is the largest output
voltage available? 5.0 V
VS +
15 V
R1
20 kW
R2
10 kW
09/16/2010
VOUT
© 2010 NTUST
Power in Series Circuits
R1
470 W
Use the voltage divider rule to
find V1 and V2. Then find the
power in R1 and R2 and PT.
Applying the voltage
divider rule:
 470 W 
V1  
 20 V  11.75 V
 800 W 
 330 W 
V2  
 20 V  8.25 V
 800 W 
R2
330 W
VS +
20 V
The power dissipated by each
resistor is:
11.75 V 

P
2
 0.29 W
470 W
2
8.25 V 

P2 
 0.21 W
330 W
1
09/16/2010
}
PT =
0.5 W
© 2010 NTUST
Voltage Measurements
A
• Voltage is relative and is measured with respect
to another point in the circuit.
• Voltages that are given with respect to ground are
shown with a single subscript.
VS +
12 V
B
R2
10 kW
C
• For example, VA means the voltage at point A with
respect to ground (called reference ground). VB
means the voltage at point B with respect to ground.
VAB means the voltage between points A and B.
What are VA, VB, and VAB for the circuit shown?
VA = 12 V VB = 8 V VAB = 4 V
09/16/2010
R1
5.0 kW
© 2010 NTUST
Voltage Measurements
• Ground reference is not always at the lowest
point in a circuit. Assume the ground is moved
to B as shown.
A
VS +
12 V
What are VA, VB, and VC for the circuit?
R1
5.0 kW
B
R2
10 kW
C
VA = 4 V VB = 0 V VC = -8 V
Has VAB changed from the previous circuit?
No, it is still 4 V
09/16/2010
© 2010 NTUST
Ker Terms
Series In an electric circuit, a relationship of
components in which the components are
connected such that they provide a single path
between two points.
Kirchhoff’s A law stating that (1) the sum of the voltage
voltage law drops around a closed loop equals the source
voltage in that loop or (2) the algebraic sum of
all of the voltages (drops and source) is zero.
Voltage divider A circuit consisting of series resistors across
which one or more output voltages are taken.
09/16/2010
© 2010 NTUST
Key Terms
Reference
ground
The metal chassis that houses the assembly or
a large conductive area on a printed circuit
board is used as a common or reference point;
also called common.
Open
A circuit condition in which the current path is
broken.
Short
A circuit condition in which there is zero or an
abnormally low resistance between two points;
usually an inadvertent condition.
09/16/2010
© 2010 NTUST
Quiz
1. In a series circuit with more than one resistor, the
current is
a. larger in larger resistors
b. smaller in larger resistors
c. always the same in all resistors
d. there is not enough information to say
09/16/2010
© 2010 NTUST
Quiz
2. In a series circuit with more than one resistor, the
voltage is
a. larger across larger resistors
b. smaller across larger resistors
c. always the same across all resistors
d. there is not enough information to say
09/16/2010
© 2010 NTUST
Quiz
3. If three equal resistors are in series, the total resistance
is
a. one third the value of one resistor
b. the same as one resistor
c. three times the value of one resistor
d. there is not enough information to say
09/16/2010
© 2010 NTUST
Quiz
4. A series circuit cannot have
a. more than two resistors
b. more than one voltage source
c. more than one path
d. all of the above
09/16/2010
© 2010 NTUST
Quiz
5. In a closed loop, the algebraic sum of all voltages (both
sources and drops)
a. is zero
b. is equal to the smallest voltage in the loop
c. is equal to the largest voltage in the loop
d. depends on the source voltage
09/16/2010
© 2010 NTUST
Quiz
6. The current in the 10 kW resistor is
a. 0.5 mA
b. 2.0 mA
c. 2.4 mA
VS +
24 V
R1
10 kW
R2
2.0 kW
d. 10 mA
09/16/2010
© 2010 NTUST
Quiz
7. The output voltage from the voltage divider is
a. 2.0 V
b. 4.0 V
c. 12 V
VS +
24 V
R1
10 kW
R2
2.0 kW
d. 20 V
09/16/2010
VOUT
© 2010 NTUST
Quiz
8. The smallest output voltage available from the voltage
divider is
a. 0 V
b. 1.5 V
VS +
15 V
c. 5.0 V
R1
10 k W
R2
10 kW
d. 7.5 V
09/16/2010
VOUT
© 2010 NTUST
Quiz
9. The total power dissipated in a series circuit is equal
to the
a. power in the largest resistor
b. power in the smallest resistor
c. average of the power in all resistors
d. sum of the power in all resistors
09/16/2010
© 2010 NTUST
Quiz
10. The meaning of the voltage VAB is the voltage at
a. Point A with respect to ground
b. Point B with respect to ground
c. The average voltage between points A and B.
d. The voltage difference between points A and B.
09/16/2010
© 2010 NTUST
Quiz
Answers:
1. c
6. b
2. a
7. b
3. c
8. a
4. c
9. d
5. a
10. d
09/16/2010
© 2010 NTUST