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Resistive Circuits Resistors in series Resistors in parallel Voltage divider Current divider The bridge S’01 Introduction to Engineering II ECE 194 Arizona State University 1 Electrical resistance Resistor’s obey Ohm’s Law: V=IR The voltage “drop” across a resistor is linearly proportional to the current passing through the resistor ECE 194 S’01 Introduction to Engineering II Arizona State University 2 Resistors in series R R R 1 R 2 n T RT R1 R2 ... Rn ECE 194 S’01 Introduction to Engineering II Arizona State University 3 Resistors in parallel R R R 1 R 2 n T 1 1 1 1 ... RT R1 R2 Rn ECE 194 S’01 Introduction to Engineering II Arizona State University 4 Voltage divider + R 1 v s v _ 1 + + R 2 R1 v1 iR1 vs R1 R2 v 2 _ vs iR1 iR2 R2 v2 iR2 vs R1 R2 vs i R1 R2 ECE 194 S’01 Introduction to Engineering II Arizona State University 5 Current divider + I s v I 1 R 1 I 2 R 2 v i1 R1 i2 R2 _ R2 i1 i s R1 R2 R1 R2 v is R|| is R1 R2 R1 i2 i s R1 R2 ECE 194 S’01 Introduction to Engineering II Arizona State University 6 A series-parallel connection v R 1 v s R + s R + R 2 x R + R 1 3 2 + R 3 R x v s + ( R1+ R 3 ) ( R2 + R x ) R + R + R + R 1 3 2 x ECE 194 S’01 Introduction to Engineering II Arizona State University 7 The bridge I R 1 1 I R 2 2 R2 Rx R3 R1 Am mete r v + s A I 3 B R I 3 x R The bridge is “balanced” when the ammeter reads zero x • If ammeter current = 0, I1 = I3 and I2 = Ix • The points A and B are at the same potential • So I3R3 = IxRx and I1R1 = I2R2 ECE 194 S’01 Introduction to Engineering II Arizona State University 8 Classwork #1 20 ž + 20 V 8ž 15ž 60 ž 10 ž 30 ž 18 ž 6ž 15 ž 48ž 10 ž Find the total current emitted by the voltage source ECE 194 S’01 Introduction to Engineering II Arizona State University 9