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STEADY STATE AC CIRCUIT ANALYSIS Introduction Previously we have analyzed circuits with time-independent sources – voltage and current that do not change with time DC circuit analysis In this section we will analyze circuits containing time-dependent sources – voltage and current vary with time One of the important classes of time-dependent signal is the periodic signals x(t) = x(t +nT), where n = 1,2 3, … and T is the period of the signal Introduction Typical periodic signals normally found in electrical engineering: Sawtooth wave Square wave t t Triangle wave pulse wave t t Introduction In SEE 1003 we will deal with one of the most important periodic signal of all :- sinusoidal signals Signals that has the form of sine or cosine function t Introduction In SEE 1003 we will deal with one of the most important periodic signal of all :- sinusoidal signals Signals that has the form of sine or cosine function Circuit containing sources with sinusoidal signals (sinusoidal sources) is called an AC circuit. Our analysis will be restricted to the steady state behavior of AC circuit. Why do we need to study sinusoidal AC circuit ? • Dominant waveform in the electric power industries worldwide – household and industrial appliations • ALL periodic waveforms (e.g. square, triangular, sawtooth, etc) can be represented by sinusoids • You want to pass SEE1003 ! Sinusoidal waveform Let a sinusoidal signal of a voltage is given by: v(t) = Vm sin (t) v(t) Vm 2 3 4 Vm – the amplitude or maximum value – the angular frequency (radian/second) t – the argument of the sine function t Sinusoidal waveform Let a sinusoidal signal of a voltage is given by: v(t) = Vm sin (t) The voltage can also be written as function of time: v(t) = Vm sin (t) v(t) Vm T/2 T (3/2)T 2T t Sinusoidal waveform Let a sinusoidal signal of a voltage is given by: v(t) = Vm sin (t) The voltage can also be written as function of time: v(t) = Vm sin (t) • In T seconds, the voltage goes through 1 cycle v(t) T is known as the period of the waveform Vm • In 1 second there are 1/T cycles of waveform • The number of cycles per second is the frequency f T/2 T (3/2)T 2T 1 f T t The unit for f is Hertz Sinusoidal waveform A more general expression of a sinusoidal signal is v1(t) = Vm sin (t + ) is called the phase angle, normally written in degrees Let a second voltage waveform is given by: v2(t) = Vm sin (t - ) v(t) v1(t) = Vm sin (t + ) v2(t) = Vm sin (t - ) Vm t Sinusoidal waveform v(t) v1(t) = Vm sin (t + ) v2(t) = Vm sin (t - ) Vm t Sinusoidal waveform v(t) v1(t) = Vm sin (t + ) v2(t) = Vm sin (t - ) Vm t v1 and v2 are said to be out of phase v1 is said to be leading v2 by (-) or ( + ) alternatively, v2 is said to be lagging v1 by (-) or ( + ) Sinusoidal waveform Some important relationships in sinusoidals v(t) Vm sin (t) -Vm sin (t) Vm t Sinusoidal waveform Some important relationships in sinusoidals v(t) Vm sin (t) -Vm sin (t) Vm t 180o Sinusoidal waveform Some important relationships in sinusoidals v(t) -Vm sin (t) 180o Therefore, Vmsin (t 180o) = -Vmsin (t ) t Sinusoidal waveform Some important relationships in sinusoidals Vmsin (t) = Vmsin (t 360o) Therefore, Vmsin (t + ) = Vmsin (t + 360o) Vmsin (t + ) = Vmsin (t (360o )) e.g., Vmsin (t + 250o) = Vmsin (t (360o 250o)) = Vm sin (t 110o) v(t) Vm t 250o 110o Sinusoidal waveform Some important relationships in sinusoidals It is easier to compare two sinusoidal signals if: • Both are expressed sine or cosine • Both are written with positive amplitudes • Both have the same frequency Sinusoidal waveform Average and effective value of a sinusoidal waveform An average value a periodic waveform is defined as: 1 Xav e T t T x( t )dt t e.g. for a sinusoidal voltage, 1 2 Vav e Vm sin(t )d(t ) 2 Vav e 0 Sinusoidal waveform Average and effective value of a sinusoidal waveform An effective value or Root-Mean-Square (RMS) a periodic current (or voltage) is defined as: The value of the DC current (or voltage) which, flowing through a R-ohm resistor delivers the same average power as does the periodic current (or voltage) v(t) i(t) R Average power: (absorbed) Ieffec Vdc R Average power: (absorbed) P T 2 1 i R dt T 0 P I2effec R Power to be equal: 2 effec I T 1 2 R i R dt T 0 Ieffec 1 T T 2 i dt 0 Sinusoidal waveform Average and effective value of a sinusoidal waveform For a sinusoidal wave, RMS value is : Vrms Vm 2 or Irms Im 2 Phasors A phasor: A complex number used to represent a sinusoidal waveform. It contain the information about the amplitude and phase angle of the sinusoid. In steady state condition, the sinusoidal voltage or current will have the same frequency. The differences between sinusoidal waveforms are only in the magnitudes and phase angles Why used phasors ? Analysis of AC circuit will be much more easier using phasors Phasors How do we transform sinusoidal waveforms to phasors ?? Phasor is rooted in Euler’s identity: e j cos j sin Real sin e cos e j j Imaginary cos is the real part of e j sin is the imaginary part of e j Supposed v(t) = Vm cos (t + ) j( t ) This can be written as v(t) = Vme Phasors How do we transform sinusoidal waveforms to phasors ?? j( t ) v(t) = Vme Phasors How do we transform sinusoidal waveforms to phasors ?? j( t ) v(t) = Vme j( t ) = Vme j j = Vme e j j v(t) = Vme e Vm e j is the phasor transform of v(t) v(t) = Vmcos (t +) phasor transform V Vme j Phasors V Vme j Phasors V Vme j We will use these notations V Vmo Polar forms V Vm cos Vm j sin Rectangular forms Some examples …. va(t) = Vmcos (t -) i(t) = Imcos (t +) Va Vm o I Im o vx(t) = Vmsin (t +) vx(t) = Vmcos (t + - 90o) Vx Vm(o 90 o ) Phasors V Vme j We will use these notations V Vmo Polar forms V Vm cos Vm j sin Rectangular forms Phasors can be graphically represented using Phasor Diagrams Im V Vmo Vm o Re Phasors V Vme j We will use these notations V Vmo Polar forms V Vm cos Vm j sin Rectangular forms Phasors can be graphically represented using Phasor Diagrams Im V Vmo Vm sin o Re Vm cos Phasors V Vme j We will use these notations V Vmo Polar forms V Vm cos Vm j sin Rectangular forms Phasors can be graphically represented using Phasor Diagrams Draw the phasor diagram for the following phasors: V1 20125 o V2 40100 o V3 5 j5 Phasors To summarize … • va(t) = Vmcos (t -) phasor transform Va Vm o Vm cos Vm j sin • If v1(t), v2(t), v3(t), v4(t), ….vn(t) are sinusoidals of the same frequency and v(t) = v1(t) + v2(t) + v3(t) + v4(t) + ….+vn(t) , in phasors this can be written as: V = V1 + V2 + V3 +V4 + …+Vn • It is also possible to do the inverse phasor transform: V Vmo inverse phasor transform v(t) = Vmcos (t + ) Phasor Relationships for R, L and C The relationships between V and I for R, L and C are needed in order for us to do the AC circuit analysis R iR IR + VR + vR If iR = Im cos (t + i) IR Ii v R iRR vR = R (Im cos (t + i)) VR RI i Vm v vR and iR are in phase ! Phasor Relationships for R, L and C The relationships between V and I for R, L and C are needed in order for us to do the AC circuit analysis L iL IL + VL + vL IL Im i If iL = Im cos (t + i) vL L VR jLIm i diL dt vL = L (Im (-sin (t + i))) vL = L (Im cos (t + I +90o)) vL leads iL by 90o ! LIm(i 90o ) Vm v Phasor Relationships for R, L and C The relationships between V and I for R, L and C are needed in order for us to do the AC circuit analysis C ic Ic + vc + Vc If vc = Vm cos (t + v) Vc Vm v iC C Ic jCVm v dv c dt ic = C (Vm( -sin (t + v))) ic = C (Vm cos (t + v +90o)) ic leads vc by 90o ! CVm(v 90 o ) Im i