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9-1 Electricity Principles & Applications Eighth Edition Richard J. Fowler Chapter 9 Power in AC Circuits (student version) McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9-2 INTRODUCTION • Phase Shift • True Power • Apparent Power • Angle Theta • Power Factor McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9-3 Dear Student: This presentation is arranged in segments. Each segment is preceded by a Concept Preview slide and is followed by a Concept Review slide. When you reach a Concept Review slide, you can return to the beginning of that segment by clicking on the Repeat Segment button. This will allow you to view that segment again, if you want to. McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9-4 Concept Preview (Page 231) • In pure resistance ac circuits, there are only two power pulses per cycle. • In pure resistance ac circuits, both power pulses are positive. • In pure resistance ac circuits, current and voltage are in-phase. • In pure resistance ac circuits, use the the power formula used for dc circuits. McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9-5 Ac- Power Facts • Resistance doesn’t cause phase shift. • Reactance causes 90 of phase shift. • Theta is the angle by which the current leads or lags the voltage. • Trigonometric functions can be used to find the resistive and reactive parts of a phasor. • Apparent power calculations ignore phase shift. • It is advantageous for a system to operate with a power factor close to one. McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9-6 Power In A Resistive Ac Circuit (Page 232) P 5V 2A Note that both power pulses are positive. There are only two pulses per cycle. Voltage and current are in-phase. V I P = IV in an ac circuit containing only resistance. P = 2 A x 0.707 x 5V x 0.707 = 5 W McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9-7 Resistive-Power Quiz Power equals current times voltage in an ac circuit when the only load is ____. resistance Use ____ values of current and voltage when calculating power. rms Without phase shift, there are ____ power pulses for each cycle. two There are no ____ power pulses when current and voltage are in phase. negative An ac circuit with a 30-VP-P source and a 10-W resistor load uses ____ watts of power. McGraw-Hill 11.25 © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9-8 Concept Review • In pure resistance ac circuits, there are only two power pulses. • In pure resistance ac circuits, both power pulses are positive. • In pure resistance ac circuits, current and voltage are in-phase. • In pure resistance ac circuits, use the the power formula used for dc circuits. Repeat Segment McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9-9 Concept Preview • Capacitance causes I to lead V. • Inductance causes V to lead I. (Page 232) (Page 233) • Circuits with both R and X (reactance) cause theta to be >0 and <90. (Page 233) • It (or Vt) can be divided into its resistive and reactive parts. (Page 235) McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 10 Reactance Causes Phase Shift (Page 232) V I 50 A combination circuit with capacitance causes I to lead V. McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 11 Reactance Causes Phase Shift (Page 232) 60 V I A combination circuit with inductance causes V to lead I. McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 12 Working With Right Triangles (Page 236) opposite tan q = adjacent q hypotenuse adjacent side Ireactive adjacent cos q = hypotenuse Ireactive sin q = opposite = q q Iresistive Vsource Iresistive The hypotenuse can be either the total voltage or the total current. Of course, the sides must be the same quantity as the hypotenuse. McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 13 Combination-Loads Quiz Capacitance causes current to ____ voltage. lead Inductance causes current to ____ voltage. lag The ____ of a triangle of current phasors represents the total current. hypotenuse The resistive current is ____ amperes when 9.2 theta is 40 and the total current is 12 amperes. The total voltage is ____ volts when theta is 25 and the reactive voltage is 40 volts. McGraw-Hill 94.6 © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 14 Concept Review • Capacitance causes I to lead V. • Inductance causes V to lead I. • Circuits with both resistance and reactance cause theta to be >0 and <90. • It (or Vt) can be divided into its resistive and reactive parts. Repeat Segment McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 15 Concept Preview (Page 240) • Phase-shifted circuits produce two positive and two negative power pulses. • In pure reactance circuits the negative and positive pulses are equal. • Wattmeters measure true power. • Apparent power ignores angle theta. • Power factor = power apparent power. McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 16 Power In A Phase-Shifted Circuit (Page 241) P cos 30° = 0.866 30° 3V 2A I V The power pulse is negative when I and V have opposite signs. P = I V cos q = 2 A x 0.707 x 3V x 0.707 x 0.866 = 2.6 W McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 17 Power in a Pure Reactance Circuit (Page 231) The negative power pulses cancel the positive power pulses. There is no true power. P I V 90 This circuit has capacitance because I leads V. McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 18 Two Types Of(PagePower In Ac Circuits 240) 80 W W 4A A 25 V V Combination of resistance and reactance Power (true power) is measured with a wattmeter or calculated using the formula P = IV cos q. Measured P = 80 W. Apparent power is determined by measuring current and voltage and then using the formula Papp = IV. Papp = 4 A x 25 V = 100 VA When the load is all resistance, power (P) = apparent power (Papp). McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 19 Determining Power Factor (PF) and Angle Theta (q) (Page 241) 75.5 W W 3A A 30 V V Combination of resistance and reactance The measured power, current, and voltage can be used to determine power factor and angle theta. Papp = 3 A x 30 V = 90 VA PF = cos q = P / Papp = 75.5 W / 90 VA = 0.839 q = arccos 0.839 = 33 ( Arccos means the angle that has this cos.) McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 20 Calculating Currents (Page 238) Determine the resistive and reactive currents when the source current is 43 A and the power factor is 0.92. cos q = Iresistive / IT Therefore, Iresistive = IT x cos q Iresistive = 43 A x 0.92 = 39.56 A arccos 0.92 = 23.1 ( Arccos means the angle that has this cos.) And, tan 23.1 = 0.426 tan q = Ireactive / Iresistive Therefore, Ireactive = Iresistive x tan q Ireactive = 39.56 A x 0.426 = 16.85 A McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 21 Combination-Load-Power Quiz There are ____ negative power pulses per cycle when current and voltage are out of phase. two With combination loads, P = IV cos q will yield the ____ power. true With combination loads, P = IV will yield the ____ power. apparent The unit for apparent power is the _____. VA The power is ____ watts when I = 16 A, V = 240 V, and q = 20. 3608.4 The power factor is ____ when P = 860 W, I = 10 A, and V = 120 V. 0.717 McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 22 Concept Review • Phase-shifted circuits produce two positive and two negative power pulses. • In pure reactance circuits the negative and positive pulses are equal. • Wattmeters measure true power. • Apparent power ignores angle theta. • Power factor = power apparent power. Repeat Segment McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved. 9 - 23 REVIEW • Phase Shift • True Power • Apparent Power • Angle Theta • Power Factor McGraw-Hill © 2013 The McGraw-Hill Companies Inc. All rights reserved.