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Gravity and Orbits Announcements n Homework # 2 is available in SPARK/OWL. It is due on Friday, October 7th. n EXAM 1 will take place next Thursday, October 6th. ¨ IMPORTANT: Bring your student ID. IDs will be checked at the end of the exam, when you give back your exam sheet. No ID = No EXAM! ¨ The exam will consist of ~40 multiple-choice questions; you have 1 hr and 10 minutes (plenty of time!). ¨ The exam will follow the open-notes/open-book policy. Not permitted: talking to or copying from your neighbor, computers, PDAs or any device with wireless/wired connection (Violation = 0 points for the Exam). ¨ Covered: all lectures (including the lecture of October 4th) and Units 1-3, 5-20). Today s Goals 1) Discuss the universal law of gravity. 2) Discuss how the law of gravity defines the orbital motion of celestial bodies. Assigned Reading n Units 16 (second half), 17, and 18. Gravity n What force is responsible for motions in the universe? n What force makes objects fall? n What keeps us on the rotating Earth? n Why don’t planets move in straight lines, but orbit around the Sun instead? Gravity n We can summarize the universal law of gravitation with the following statements: § Every mass attracts every other mass through the force of gravity. § If mass #1 exerts force on mass #2, and mass#2 exerts force on mass#1, the force must depend on both masses, and is directly proportional to them. § The force of attraction is inversely proportional to the square of the distance between the masses. The Law of Gravity Near Earth s surface M 1M 2 Fg = G 2 d G= 6.67x10-11 Fg = gM 2 m3/kg/s2 M1 g =G 2 d 2 = 9.8m/s d M1 M2 M 1M 2 Fg = G Survey Question d2 Two equal masses, m, separated by a distance, d, exert a force, F, on each other due to their gravitational attraction. How large would their gravitational attraction be if the distance between them was doubled? 1) ¼ F 2) ½ F 3) F 4) 2F 5) 4F M 1M 2 Fg = G 2 Survey Question d Two equal masses, m, separated by a distance, d, exert a force, F, on each other due to their gravitational attraction. How large is the gravitational force between an object of mass m and an object of mass 2m separated by the same distance d? ¼F ½F F 2F 4F M 1M 2 Fg = G Survey Question d2 If aliens magically turned our Sun into a black hole of the same mass but 10 times smaller in diameter, what would change about the Earth s orbit? 1) it would be 10 times smaller in radius 2) it would spiral into the black hole 3) nothing would change 4) it would spiral away from the black hole 5) it would be 10 times larger in radius A Special Consequence of the Law of Gravitation n If we combine Newton s law of gravity with Newton s 2nd law, we see that the acceleration of an object due to a gravitational force is independent of the accelerating object s mass. M1 M 2 Fg = G d2 so ! and Fg = M 1a1 M2 a1 = G 2 d (on Earth surface a1=g) So… why don t planets just fall into the sun? M1 M2 … because they miss it (that is, they have enough tangential velocity to always miss) v Fg Fg M1 This is the concept of an orbit. M2 Is the earth falling into the sun? n n n It has a velocity and it has inertia! Force of gravity causes change in the direction of velocity --acceleration. The earth is falling towards the sun all the time! V=8km/s Newton s `thought experiment! Survey Question Why do astronauts float around inside the space shuttle? 1) there is no gravity in space 2) they are falling at the same rate as the space shuttle 3) they are above the Earth s atmosphere 4) their mass is smaller 5) more than one of these n The § § § Tethered Rock Tie a rock to a string, and start rotating it overhead. You feel the rock trying to `pull away, but if you hold on the string, you oppose a force to the `pulling away force of the string. What is happening? § § The `rotating rock has an inertia, and the rotating motion imparts it an acceleration (change of direction). If the rock could break free, it would move in a straight line (a tangent of the circle). Mass x acceleration = Force Your tether opposes a Force (Centripetal Force) to that Force Centripetal Force n n n n Planets orbiting the Sun are subject to centripetal force, the same force that keeps a weight tethered to a string from `flying away when you rotate it. The centripetal force is the force that keeps objects on a curved path. In the case of planets, the centripetal force is due to gravity, and compensates the planet s inertia and constant acceleration [Newton s Third Law]) The larger the velocity, the larger the force The farther away the weight, the smaller the force Fc = m v2 / R Centripetal Force = Gravitational Force: In an orbit, the gravitational force must equal the centripetal force F c = Fg Fc = mv2/R mv2/R = GmM/R2 Fg = GmM/R2 or: v2 = GM/R In a circular orbit: v = 2πR/P and: R3= G/4π2 M P2 If you express P in years and R in AU, then the term GM/4π2 cancels out and you have Kepler’s Third Law: R3 = P2. Kepler s Third Law of Orbits: Revisited 3. A planet s Period (the time it takes to complete one orbit) is related to its average distance to the sun. G/4π2 M P2 = R3 (orbital period in years)2 = (average distance in AU)3 P2 = a3 § Notice that there is nothing stated about the planet s mass here! § The period/radius is independent of the planet s mass! The same formula: R3= G/4π2 M P2 can be used to derive the mass of the Sun (if R and P are measured in MKS units): M = 4π2/G (R3/P2 ) = 2.0 E+30 kg R=Earth-Sun distance P=Earth s orbital period Orbital Velocity To remain in orbit, an object s gravity and centripetal force must balance each other: § Mv2/R = GMm/R2 n Solving for v gives: vorb = √GM/R n For the Earth: vorb = 7.9 km/s ~ 28,440 km/h = 17,665 miles/h n Escape Velocity It is the velocity needed by an object (a rocket) to escape a planet s gravitational pull n To escape, you must have a velocity that compensates for the gravitational pull: n 2GM v= d Vesc, Earth = 11.2 km/s Vesc, Moon = 2.4 km/s Escape Velocity The velocity to compensate for the gravitational pull must be calculated from the surface of the planet. It is the same for the rocket and for the cannon ball!