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Physics 103: Lecture 13 Newtonian Gravity Extended Objects : Center of Gravity 03/05/2003 Today’s lecture will cover Newton’s Law of Gravitation Kepler’s Laws Center of Gravity Physics 103, Spring 2003, U. Wisconsin 1 Lecture 13 - Preflight 1, 2 & 3 You are driving a car with constant speed around a horizontal circular track. On a piece of paper draw a Free Body diagram for the car. How many forces are acting on the car? 2% 9% 61% 24% 1 2 3 4 5 a) gravity b) normal force of road c) centripetal force 3% Fc 0% 20% 40% 60% 80% Pretty Sure Not Quite Sure Just Guessing 03/05/2003 N mg N Physics 103, Spring 2003, U. Wisconsin 2 Lecture 13 Preflight 4 & 5 The net force on the car is Zero Pointing radially inward, toward the center of the circle Pointing radially outward, away from the center of the circle 32% 55% To travel in a circle something must supply the centripetal acceleration. 13% 0% 03/05/2003 20% 40% 60% Pretty Sure Not Quite Sure Just Guessing Physics 103, Spring 2003, U. Wisconsin 3 Lecture 13 - Preflight 6 & 7 Suppose you are driving through a valley whose bottom has a circular shape. If your car has mass M, what is the normal force exerted on you by the car seat as you drive past the bottom of the hill? Fn < Mg V Fn = Mg down Fn > Mg Normal force must also supply centripetal acceleration 20% 51% 29% Pretty Sure Not Quite Sure Just Guessing 0% 03/05/2003 20% 40% 60% Physics 103, Spring 2003, U. Wisconsin 4 A SPECIAL POINT Center of mass (or center of gravity) If line of force passes thru c.m. No rotation m1r1 m2 r2 m3 r3 m4 r4 ....... rcm m1 m2 m3 m4 ........ Center of mass is the same as the center of the volume Provided: uniform density -- material! 03/05/2003 Symmetry Physics 103, Spring 2003, U. Wisconsin 5 Question 1 Can a body’s center of gravity be outside its volume? a) yes b) no Center of gravity (CG) is defined as: In three dimensions, the coordinates of CG xcm m1 x1 m 2 x2 m1 m 2 ycm m1 y1 m 2 y2 m1 m 2 zcm m1z1 m2 z2 m1 m2 where m1 is the mass of element at coordinate (x1,y1,z1) … CG can be outside the volume. 03/05/2003 Physics 103, Spring 2003, U. Wisconsin 6 Question 2 Where is the center of gravity of a “yummy” donut? It is at the origin of the circular ring, half way from the bottom of the donut - where there is no dough. 03/05/2003 Physics 103, Spring 2003, U. Wisconsin 7 A moment later…… M R New c.g. old c.g. m 8 M R shift 8 C G has shifted along the line of symmetry away from the bite. 03/05/2003 Physics 103, Spring 2003, U. Wisconsin 8 Newton’s Law of Gravitation Every particle in the universe attracts every other particle with a force along the line joining them. The force is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Note: “particle”! If an extended object you must treat the vector sum of all the forces. This is done automatically by considering the object as if it were of the same mass concentrated at the “center of mass” (or the center of gravity!?) If a system of extended objects you must still consider the center of mass) 03/05/2003 Physics 103, Spring 2003, U. Wisconsin 9 Newton’s Law of Gravity m Magnitude: r Fg = G mM r2 M G = 6.67 x 10-11 N m2/kg2 Direction: attractive (pulls them together) force on M due to m is away from M center and force on m due to M is away from m center Mm PE G r PE(r ) 0 Work done to bring mass m from infinity to the proximity of mass M Only differences in potential energy matter Zero point is arbitrary. 03/05/2003 Physics 103, Spring 2003, U. Wisconsin 10 Close to the Surface of the Earth Consider an object of mass m near the surface of the earth. Fg = ma = G mg M m PE1 G E RE M m PE 2 G E RE h 1 1 PE GME m R R h E E 03/05/2003 a=g = G mM M RE2 r2 =9.8 m/s2 r~RE h h PE GME m GME m 2 h RE RE h RE 1 R E GM h PE m 2 E h mgh for small RE RE Physics 103, Spring 2003, U. Wisconsin 11 Escaping Gravity Kinetic energy of the rocket must be greater than the gravitational potential energy Defines minimum velocity to escape from gravitational attraction KE PE constant Consider case when speed is just sufficient to escape to infinity with vanishing final velocity At infinity, KE + PE = 0, therefore, on Earth, 1 2 M m mvesc G E 0 2 RE v esc 03/05/2003 2GME 11.2 km/s 25000 mph RE Physics 103, Spring 2003, U. Wisconsin 12 Lecture 13 Preflight 8 & 9 Two satellites A and B of the same mass are going around Earth in concentric orbits. the distance of satellite B from Earth’s center is twice that of satellite A. What is the ratio of the centripetal acceleration of B to that of A? Since the only force is the gravitational force, it must scale as the inverse square of their distances from the center of the Earth. 1/8 1/4 1/2 0.707 1.0 4% GmME FB rA2 1 rB2 2 GmM FA rB 4 E rA2 03/05/2003 47% 44% 1% Pretty Sure Not Quite Sure Just Guessing 4% 0% 10% 20% 30% 40% 50% Physics 103, Spring 2003, U. Wisconsin 13 Lecture 13 Preflight 10 & 11 Suppose Earth had no atmosphere and a ball were fired from the top of Mt. Everest in a direction tangent to the ground. If the initial speed were high enough to cause the ball to travel in a circular trajectory around the earth, the ball’s acceleration would • be much less than g (because the ball doesn’t fall to the ground) • be approximately g • depends on the velocity of the ball 23% 49% Pretty Sure Not Quite Sure Just Guessing 28% 0% 10% 03/05/2003 20% 30% 40% 50% Physics 103, Spring 2003, U. Wisconsin 14 Orbits Acceleration is provided by gravity mM mac Fg G 2 R 03/05/2003 Physics 103, Spring 2003, U. Wisconsin 15 Kepler’s Emperical Laws Based on Tycho Brahe’s astronomical measurements Orbit of a planet is an ellipse with the Sun at one focus Equal areas swept out in equal times. T2 R3 = constant Newton: V2 mM m mR 2 G 2 R R 2 T R 3 GM 2 T 4 2 03/05/2003 Physics 103, Spring 2003, U. Wisconsin Do read Examples 7.14-7.16 if you have not already done so. 16