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Force on a current carrying conductor Submitted to: Dr. Tariq Bhatti Submmited by: Ahmad Mushtaq Roll No.: 07-45 Program BS-it Session 2007-11 Department of Computer Science Bahauddin Zakariya University, Multan How to find force on a current carrying conductor ? Equation for finding force on a moving particle can be used to find force on a current carrying conductor. Current Source: www.boredofstudies.org Substituting We know that, F = qv x B Substituting, Velocity v = vd Total Charge q = Nq = nAlq Hence, F = nAlqvd x B . .. N = nAl Relation of Force with Length & Current F = nAlqvd x B ‘l’ has the same direction as ‘vd’ we can write: lvd = lud Substituting: F = nAlqud x B Relation of Force with Length & Current F = nAlqud x B We know that, Current Density j = nqud and Current I = jA = nqud A Hence, F = Il x B Magnitude of Magnetic Force F = Il x B sin0 Where ‘O’ is angle b/w directions of ‘l ’ & ‘B’. Direction of the force can be determined by fleming’s left hand rule Source: http://physics503.one-school.net What if conductor is not straight? Here we use, dF=Idl x B For sum, F= ∫Idl x B Conclusion: The magnitude of the force on length l of the conductor is proportional to the length as well as to the current in the conductor and to the magnitude of the magnetic field. Elements For Presentation