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Physics I 95.141 LECTURE 22 11/29/10 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Administrative Notes • Exam III – In Class Wednesday, 9am – Chapters 9-11 – 9 problems posted on Website in Practice Exam Section. At least 1 of these problems will be on EXAM III. • If you have questions, start a discussion thread on Facebook, that way my response is seen by everyone in the class. – Review Session Tuesday Night, 6:00pm, OH150 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Outline • • • Oscillations Simple Harmonic Motion What do we know? – Units – Kinematic equations – Freely falling objects – Vectors – Kinematics + Vectors = Vector Kinematics – Relative motion – Projectile motion – Uniform circular motion – Newton’s Laws – Force of Gravity/Normal Force – Free Body Diagrams – Problem solving – Uniform Circular Motion – Newton’s Law of Universal Gravitation – Weightlessness – Kepler’s Laws 95.141, F2010, Lecture 22 Department of Physics and Applied Physics – – – – – – – – – – – – – – – – – – – – – – – – – Work by Constant Force Scalar Product of Vectors Work done by varying Force Work-Energy Theorem Conservative, non-conservative Forces Potential Energy Mechanical Energy Conservation of Energy Dissipative Forces Gravitational Potential Revisited Power Momentum and Force Conservation of Momentum Collisions Impulse Conservation of Momentum and Energy Elastic and Inelastic Collisions2D, 3D Collisions Center of Mass and translational motion Angular quantities Vector nature of angular quantities Constant angular acceleration Torque Rotational Inertia Moments of Inertia Angular Momentum – – Vector Cross Products Conservation of Angular Momentum Review of Lecture 21 • Discussed cross product definition of angular momentum and torque L I RF Lrp r F • Why would we ever use cross products instead of simpler scalar expressions? – 3D vectors – Point masses not moving in uniform circle dL nd – Newton’s 2 Law for rotational motion dt • Conservation of Angular Momentum – No external torque, angular momentum conserved. 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Oscillations (Chapter 14) • Imagine we have a spring/mass system, where the mass is attached to the spring, and the spring is massless. A vmax A 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Oscillations • So we can say that the mass will move back and forth (it will oscillate) with an Amplitude of oscillation A. • Can we describe what is going on mathematically? • Would like to determine equation of motion of the mass. In order to do this, we need to know the force acting on the block. • Force depends on position: Hooke’s Law Fspring kx 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Oscillations Fspring kx dv d dx d x F ma m dt m dt dt m dt 2 2 2 d x (t ) kx (t ) m 2 dt 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Possible Solutions • What if x=At? • What if x=Aebt? 95.141, F2010, Lecture 22 Department of Physics and Applied Physics d x (t ) k x (t ) 2 dt m 2 Possible Solutions • What if x=Acos(bt)? • What if x=Acos(bt+Φ)? 95.141, F2010, Lecture 22 Department of Physics and Applied Physics d x (t ) k x (t ) 2 dt m 2 Possible Solutions • What if d x (t ) k x (t ) 2 dt m x(t ) A cos(t ) , 2 k m If we start with the mass displaced from equilibrium by a distance A at t=0, then we can determine x(t). 95.141, F2010, Lecture 22 Department of Physics and Applied Physics What does motion vs. time look like? x(t ) A cos(t ) , k m • Plot x at t=0, π/2ω, π/ω, 3π/2ω, 2π/ω, 5π/2ω x A t -A 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Harmonic Motion: terminology • Displacement: Distance from equilibrium • Amplitude of oscillation: max displacement of object from equilibrium • Cycle: one complete to-and-fro motion, from some initial point back to original point. • Period: Time it takes to complete one full cycle • Frequency: number of cycles in one second 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Simple Harmonic Motion • A form of motion where the only force on the object is the net restoring force, which is proportional to the negative of the displacement. • Such a system is often referred to as a simple harmonic oscillator • The simple harmonic oscillator’s motion is described by: x(t ) A cos(t ) , 95.141, F2010, Lecture 22 Department of Physics and Applied Physics k m What is Φ? 22 tt)t)))2 2cos( 2cos( cos( cos( t t t ) ) ) , , , 2022 2 222cos( t ) , x (xtxx()x(t((t)( t ) , cos(t ) , 5 5555,5 ,,,,, 4 222 Displacement Displacement Displacement Displacement Displacement 2 22 1 11 0 00 -1 -1 -1 -2 -2 -2 0 00 95.141, F2010, Lecture 22 5 10 5 time(s) time(s) time(s) Department of Physics and Applied Physics 15 10 10 10 15 15 15 More terminology • So the Φ term is known as the phase of the oscillation. It basically shifts the x(t) plot in time. • The term ω, which for a spring mass system, is equal to k m , is known as the angular frequency. x (t ) A cos(t ) T 2 2 T 95.141, F2010, Lecture 22 Department of Physics and Applied Physics 2f Velocity and Acceleration for SHO • If we know x(t), we can calculate v(t) and a(t) x (t ) A cos(t ) 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Velocity and Acceleration for SHO • If x (t ) A cos(t ) 2 x(t) 1 0 -1 -2 v(t) 2 0 -2 4 a(t) 2 0 -2 -4 0 2 4 6 8 time (s) 95.141, F2010, Lecture 22 Department of Physics and Applied Physics 10 12 14 Example • A SHO oscillates with the following properties: – Amplitude=3m – Period = 2s • Give the equation of motion for the SHO 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Example • A SHO oscillates with the following properties: – Amplitude=3m – Period = 2s – At t=0s, x=3m. • Give the equation of motion for the SHO 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Example • A SHO oscillates with the following properties: – Amplitude=3m – Period = 2s – At t=0s, x=1.5m • Give the equation of motion for the SHO 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Example • A SHO oscillates with the following properties: – Amplitude=3m – Period = 2s – At t=0s, v=2m/s. • Give the equation of motion for the SHO 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Energy of SHO • The total energy of a simple harmonic oscillator comes from the potential energy in the spring, and the kinetic energy of the mass. x (t ) A cos(t ) v (t ) A sin( t ) 95.141, F2010, Lecture 22 Department of Physics and Applied Physics k m Example • A spring mass system with m=4kg and k=400N/m is displaced +0.2m from equilibrium and released. – A) What is the equation of motion for the mass? 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Example • A spring mass system with m=4kg and k=400N/m is displaced +0.2m from equilibrium and released. – B) What is the total energy of the system? 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Example • A spring mass system with m=4kg and k=400N/m is displaced +0.2m from equilibrium and released. – C) What is the Kinetic Energy and Potential Energy of the system at t=2s? 95.141, F2010, Lecture 22 Department of Physics and Applied Physics SHO and Circular Motion y • You will notice that we use the same variable for both angular velocity and angular frequency of a simple harmonic oscillator. • If we imagine an object moving with uniform circular motion (angular velocity=ω) on a flat surface. Starting, at t=0s, at θ=0. • We know that θ(t)=ωt • We can write the x-position of the object as: • And the y-position as: 95.141, F2010, Lecture 22 Department of Physics and Applied Physics A θ x The pendulum • A simple pendulum consists of a mass (M) attached to a massless string of length L. • We know the motion of the mass, if dropped from some height, resembles simple harmonic motion: oscillates back and forth. • Is this really SHO? Definition of SHO is motion resulting from a restoring force proportional to displacement. 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Simple Pendulum L • We can describe displacement as: • The restoring Force comes from gravity, need to find component of force of gravity along x • Need to make an approximation here for small θ… 95.141, F2010, Lecture 22 Department of Physics and Applied Physics θ Δx Simple Pendulum • Now we have an expression for the restoring force F mg sin mg x L mg F x L • From this, we can determine the effective “spring” constant k • And we can determine the natural frequency of the pendulum 95.141, F2010, Lecture 22 Department of Physics and Applied Physics L θ Δx Simple Pendulum • If we know g L L θ • We can determine period T • And we can the equation of motion for displacement in x • …or θ 95.141, F2010, Lecture 22 Department of Physics and Applied Physics Δx