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Chapter 9 Momentum & Its Conservation Determining Impulse F = ma a = Dv/Dt Thus F = mDv/Dt or FDt = mDv Impulse •The product of a force times the amount of time the force is applied. •FDt Determining Momentum Dv = vf – vi thus mDv = mvf – mvi Momentum (p) •The product of mass times velocity •p = mv Change in Momentum Dp = mDv FDt = mDv •Impulse = momentum change FDt = mDv = mvf - mvi = pf - pi The Equation below is called the ImpulseMomentum Theorem FDt = pf - pi A 750 kg car is traveling east at 180 km/hr. Calculate the magnitude & direction of its momentum. A 250 kg car is traveling east at 360 km/hr. Calculate the magnitude & direction of its momentum. A 250 kg car collides with a 10.0 Mg shed & remains in contact with the shed for 0.500 s. Calculate the force of the collision & the impulse imparted onto the shed. Drill: A force of 25 N is applied to a 5.0 kg object for 5.0 seconds. Calculate: impulse, Dp & Dv: A force of 75 N is applied to a 5.0 kg object for 15.0 seconds. Calculate: impulse, Dp & Dv: A 250 kg sled is accelerated from 6.0 m/s to 18 m/s over 120 s. Calculate: a, pi, pf, Dp, & impulse A 150 g ball pitched at 40.0 m/s is batted in the opposite direction at 40.0 m/s. Calculate: Dp, & impulse Drill: A 60.0 kg man drives his car into a tree at 25 m/s. The car comes to rest in 0.20 s. Calculate: Dp & F on the man. Calculate the momentum change when a 100.0 kg block accelerates for 10.0 s o down a 37 incline with a frictional coefficient of 0.25 Conservation of Momentum •In a closed system, momentum is conserved •pf = pi or p1 = p2 Conservation of Momentum • In collisions, momentum is conserved •(p1 + p2)b = (p1 + p2)a Book Notation of Momentum (p1 + p2)b = (p1 + p2)a (pA + pB)1 = (pA + pB)2 pA1 + pB1 = pA2 + pB2 Book Notation of Momentum pA1 + pB1 = pA2 + pB2 mAvA1 + mBvB1 = mAvA2 + mBvB2 Collision Momentum mAvA + mBvB = mAvA’ + mBvB’ A 200. Mg freight car moving at 2.5 m/s collides with the same sized car at rest where they remain connected. Calculate vf: A 125 g hockey puck moving at 40.0 m/s is caught in a glove by a 75 kg goalie. Calculate vf of the goalie. A 35 g bullet strikes a 2.5 kg stationary block at 750 m/s. The bullet exits the block at 350 m/s.Calculate vf of the block. A 250 g ball at 4.0 m/s collides head on with a 1.0 kg ball 2.0 m/s. the 250 g ball bounced backwards at 5.0 m/s. Calculate vf of the other. Drill: A 750 g ball at 4.0 m/s collides head on with a 1.0 kg ball 5.0 m/s. The 750 g ball bounced backwards at 8.0 m/s. Calculate vf of the other. A 25 g ball at 40.0 m/s collides head on with a 2.0 kg ball 2.0 m/s. the 25 g ball bounced backwards at 50.0 m/s. Calculate vf of the other. A 250 g ball at 4.0 m/s collides head on with a 2.0 kg ball 5.0 m/s. the 250 g ball bounced backwards at 40.0 m/s. Calculate vf of the other. A 1.0 kg bat swung at 50.0 m/s strikes a 250 g ball thrown at 40.0 m/s. The bat continues at 10.0 m/s. Calculate vf of the ball. Explosion Momentum • The momentum before the explosion must = the momentum after the explosion. • The momentum before the explosion = 0 Explosion Momentum •pA = pB •pB = 0 thus •pA = 0 Explosion Momentum •The summation of all parts after the explosion = 0 Explosion Momentum mAvA + mBvB + etc = 0 Explosion Momentum with only 2 parts mAvA + mBvB =0 Explosion Momentum with only 2 parts mAvA = -mBvB A 50.0 kg gun fired a 150 g bullet at 500.0 m/s. Calculate the recoil velocity of the gun. Drill: A 500.0 Mg cannon fired a 150 kg projectile at 1500.0 m/s. Calculate the recoil velocity of the gun. A 250 g cart is connected to a 1.5 kg cart. When disconnected, a compressed spring pushes the smaller cart 4.0 m/s east. Calculate the velocity of the larger cart. A 2.0 kg block is tied to a 1.5 kg block. When untied, a compressed spring pushes the larger block 6.0 m/s east. mblock = 0.25 Calculate: vi, a, t, d for the smaller block A 5.0 kg block is tied to a 2.0 kg block. When untied, a compressed spring pushes the larger block 1.0 m/s east. mblock = 0.20 Calculate: vi, a, t, d for the smaller block Two Dimensional Collisions A 5.0 kg ball moving at 40.0 m/s collides with a stationary 2.0 kg. The 2.0 o kg ball bounced at a 30 angle from the path at 50.0 m/s. Calculate vf of the other. A 2.0 kg ball is dropped from a 14.7 m high ledge collides with a stationary 10.0 kg ball hanging at a height of 9.8 m. The 2.0 kg ball bounced straight up at 4.9 m/s. Calculate vi, vf, & tair of the 10 kg ball.