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Transcript
Circular Motion What is circular motion? • Objects that move in a circle experience circular motion. • I know that’s tough. • Let’s take a moment and let it sink in… Now that that is out of the way… • There are specific features of circular motion that make it different from linear or projectile motion Constant speed • An object with a constant speed, which experiences no other forces, will travel in a straight line at that speed infinitely • Newton’s First Law Constant speed Constant speed • Objects can travel in a circle and maintain a constant speed Is velocity constant? • No • Velocity is speed in a given direction • Those directions cannot be circular What is acceleration? • Acceleration is a change in velocity • We have so far defined acceleration as a change in speed but it can be a change in direction, also Circular Motion • An object traveling in a circle travels at a constant speed but is accelerating What causes acceleration? • All changes in velocity are caused by a force • F = ma • Newton’s Second Law What is the force? • The force keeping the object in its circular path is called a centripetal force • Centripetal means “center seeking” Centripetal force • It is a real force • It is a contact force What direction does it point? • The centripetal force always points towards the center of the circle What applies the force? • It depends on the situation • In general, whatever keeps the item in it’s circular path applies the centripetal force Example Example Example Are there other forces? • When you make a turn in your car, what makes you pull to one side? • When you swing a bucket of water above your head, what keeps the water in the bucket? What causes that? • In truth, it is a delicate interplay between the inertia of the item and the acceleration • It is another force Centrifugal force • From the Latin, centrum, “center,” and fugere, “fleeing” • This is the force that pushes away from the center of the circle Centrifugal Force • It is the reaction force that compliments the action of the centripetal force • Newton’s Third Law Centrifugal • The centrifugal force is a fictitious force • Is it also a contact force Example • You have a bucket of water and you are swinging it around above you head. What forces are acting on it and what do they act on? The two forces • Remember, we have two forces, the centripetal and the centrifugal • The centripetal acts on the bucket • The centrifugal acts on the water The math • You knew it was coming • Math is the language of physics and you need to learn to speak that language Centripetal acceleration • There are two equations we can use depending on what we know The first (and easiest) 2 v ac r • v is the velocity of the object • r is the radius of the circle The second 4 r ac 2 T 2 • T is the time it takes for one full revolution • r is the radius of the circle Centrifugal acceleration • If the centrifugal force arises from Newton’s Third Law and is the equal but opposite reaction to the centripetal force, what is the equation going to be? Centrifugal acceleration 4 r ac 2 T Or 2 v ac r 2 Sample problem • A 1000 kg car enters an 80 meter radius curve at 20 m/s. What centripetal force must be supplied by friction so the car does not skid? What do we know? • m = 1000 kg • r = 80 m • v = 20 m/s Find the force • F = ma = • F = 1000 × (202/80) • F = 1000 × 400/80 • F = 1000 × 5 = 5000 N 2 mv /r Sample problem • The centripetal force on a 0.82 kg object on the end of a 2.0 m massless string being swung in a horizontal circle is 4.0 N. What is the tangential velocity of the object? What do we know? • m = 0.82 kg • r = 2.0 m • Fc = 4.0 N Find the velocity • F = ma = • 4.0 = 0.82 × v2/2.0 • 8.0 = 0.82v2 • v2 = 9.76 • v = 3.12 m/s 2 mv /r Sample problem • A dragonfly is sitting on a merry-go-round 2.8 m from the center. If the centripetal acceleration of the dragonfly is 3.6 m/s2, what is the period of the merry-goround? What do we know? • r = 2.8 m • a = 3.6 m/s2 Find the period • ac = • 3.6 = (4π2 × 2.8)/T2 • 3.6 = 110/T2 • T2 = 31 • T = 5.5 s 2 2 (4π r)/T Sample problem • A car moving at a 1.08 × m/s (30 km/h) rounds a bend in the road with a radius of 21.2 m. What is the centripetal acceleration on the car and the centrifugal acceleration on the occupants? 8 10 What do we know? • v = 1.08 × • r = 21.2 m 8 10 m/s Centripetal •a= • a = (1.08 × 108)2 / 21.2 • a = 5.50 × 1014 m/s2 2 v /r Centrifugal •a= • a = -(1.08 × 108)2 / 21.2 • a = -5.50 × 1014 m/s2 2 -v /r