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Transcript
PS113
Chapter 1
Introduction and Mathematical Concepts
1. The nature of physics
• Physical laws are based on experiment
• Galileo Galilei, Isaac Newton, James Clerk Maxwell
• Four forces in nature–Gravity, electromagnetic, weak (radioactivity), and strong (nuclear)
2. Units
• We will use SI units: “Le Systeme International d’Unites”
• Length (meters), Mass (kilograms), and Time (seconds)
• Base units and derived units
3. The role of units in problem solving
• feet → meters, miles → kilometers,
• Standard prefixes:
mega- 1,000,000
hours → seconds
milli- 1/1000
nano- 1/1,000,000,000
giga- 1,000,000,000
• Scientific notation:
milli- 10−3
• Dimensional analysis:
time (t) → [T]
distance (x) → [L]
Problem 3
giga- 109
and so on.
mass (m) → [M]
Vesna Vulovic survived the longest fall on record without
a parachute when her plane exploded and she fell 6 miles,
551 yards. What is this distance in meters?
Answer:
10,160 m
1
Problem 6
Consider the equation v = 13 zxt2 . The dimensions of the
variables v, x, and t are [L]/[T], [L], and [T], respectively.
The numerical factor 3 is dimensionless. What must be the
dimensions of the variable z such that both sides of the equation have the same dimensions? Show how you determined
your answer.
4. Trigonometry
• Definition of sin θ, cos θ, and tan θ.
tan θ = ho /ha
• Using inverse trigonometric functions. For example θ = tan−1
• Pythagorean theorem
1
2 .
h2 = h2o + h2a
Problem 12
You are driving into St. Louis, Missouri, and in the distance you
see the famous Gateway-to-the-West arch. This monument rises
to a height of 192 m. You estimate your line of sight with the top
of the arch to be 2.0o above the horizontal. Approximately how
far in kilometers) are you from the base of the arch?
Problem 19
The drawing shows sodium and chlorine ions positioned at the
corners of a cube that is part of the crystal structure of sodium
chloride (common table salt). The edge of the cube is 0.281 nm
(1 nm = 1 nanometer=10−9 m) in length. Find the distance (in
nanometers) between the sodium ion located at one corner of the
cube and the chlorine ion located on the diagonal at the opposite
corner.
5. The nature of physical quantities
• Scalars
magnitude only
• Vectors
magnitude and direction
2
6. Vector addition and subtraction
~+B
~ =?
• A
“head-to-tail”
“head-to-tail”
~ points purely along the x direction and B
~ points purely along
• If A
~ =A
~ + B,
~ then
the y direction, and R
√
~ = A2 + B 2 and
the magnitude of R
~ is θ = tan−1 (B/A)
the direction of R
Watch out !!
The tan−1 function is only defined between -90o and +90o .
You have to use some “common sense” when reporting the
final angle.
~ and B
~ forming a right-triangle
Figure 1: The sum of two vectors A
~ and B
~ are not perpendicular to each other, then the resultant vector is
• If A
√
~ =A
~+B
~
still R
however, R =
6
A2 + B 2 and θ 6= tan−1 (B/A)
~ −B
~ =?
• A
~ + (−B)
~
is the same as A
3
Still use the “head-to-tail” rule
Problem 23 Two workers are trying to move a heavy crate. One pushes
on the crate with a force A, which has a magnitude of
445 newtons and is directed due west. The other pushes
with a force B, which has a magnitude of 325 newtons and
is directed due north. What are the magnitude and direction of the resultant force A+B applied to the crate?
(b) Suppose that the second worker applies a force -B instead of B. What then are the magnitude and direction of
the resultant force A-B applies to the crate? In both cases
express the direction relative to due west.
7. The components of a vector
~ = (Ax , Ay )
A
~ = (Bx , By )
B
Ax = A cos θ
Bx = B cos θ
Ay = A sin θ
By = B sin θ
Note: measure all your angles with respect to the x axis.
~ is
The magnitude of A
~ is
The direction of A
q
A = A2x + A2y
θ = tan−1 (Ay /Ax )
Problem 40 Your friend has slipped and fallen. To help her up, you
pull with a force F~ , as the drawing shows. The vertical
component of this force is 130 newtons, while the horizontal
component is 150 newtons. Find (a) the magnitude of F~
and (b) the angle θ. Answers: 198 N and 40.9o
8. Addition of vectors by means of components
~ =A
~+B
~
C
~ = (Cx , Cy ) = (Ax + Bx , Ay + By )
C
~ is
The magnitude of C
~ is
The direction of C
q
C = Cx2 + Cy2
θ = tan−1 (Cy /Cx )
4
Problem 47 Two forces are applied to a tree stump to pull it out of the
ground. Force FA has a magnitude of 2240 newtons and
points 34.0o south of east, while force FB has a magnitude of
3160 newtons and points due south. Using the component
method, find the magnitude and direction of the resultant
force FA + FB that is applied to the stump. Specify the
direction with respect to due east.
5