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Example 27-3 The Binding Energy of 4He Previously, we determined the binding energy per nucleon in the 4He nucleus using the mass of the nucleus. Use the values from Appendix C to determine the binding energy per nucleon (in MeV>c 2) in the 4He nucleus using the atomic mass of 4 He. Set Up We’ll use Equation 27-2 and the values given in Appendix C for the neutron mass, the atomic mass of 1H, and the atomic mass of 4He. Binding energy of a nucleus: EB = (Nmn + Zm1H 2 matom)c2 (27-2) binding energy of 4He = rest energy of rest energy of rest energy of + – two 1H atoms two neutrons a 4He atom + + + + Solve Calculate the binding energy of the 4He nucleus, which has two neutrons (N = 2) and two protons (Z = 2). From Appendix C, neutron mass = mn = 1.008665 u atomic mass of 1H = m1H = 1.007825 u atomic mass of 4He = m4He = 4.002602 u Substitute these into Equation 27-2, with matom = m4He: E B = 1211.008665 u2 + 211.007825 u2 - 4.002602 u2c 2 = 0.030378 uc2 Since 1 u = 931.494 MeV>c 2, E B = 0.030378 uc 2 a 931.494 MeV>c 2 1u = 28.297 MeV The binding energy per nucleon equals the binding energy of the nucleus divided by the number of nucleons in the nucleus. b The 4He nucleus has four nucleons (two neutrons and two protons), so the binding energy per nucleon is EB 28.297 MeV = = 7.0742 MeV A 4 Reflect Previously, we calculated E B >A = 7.1 MeV to two significant figures using the mass of the 4He nucleus; our new calculation is consistent with this. Why would we do this kind of calculation using atomic masses rather than nuclear masses? The reason is that in general, the masses of neutral atoms have been well measured, but precise measurements of the masses of atomic nuclei in isolation are difficult to obtain. Ch27_example.indd 3 9/4/13 12:54 PM