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Fullerton College Office of Special Programs SI Review 111B Handout #14 Solutions 1. To determine the oxidation state of the metal ion, we consider the charges of all known ions and work backwards to the charge on the metal ion: a. [Co(NH3)5Br]2+ The total charge is equal to the total charges of all ions… Total Charge = (Co?) + 5(NH3) + (Br-) +2 = (Co?) + 5(0) + (-1) Co = +3 Since there are six monodentate ligands, the metal ion has a coordination number of six. b. [Fe(CN)6]4Total Charge = (Fe?) + 6(CN-) -4 = (Fe?) +6(-1) Fe = +2 Since there are six monodentate ligands, the metal ion has a coordination number of six. c. [Co(C2O4)3]4Total Charge = (Co?) + 3(C2O42-) -4 = (Co?) + 3(-2) Co = +2 Since there are three bidentate ligands, the metal ion has a coordination number of six. d. [PdCl4]2Total Charge = (Pd?) + 4(Cl-) -2 = (Pd?) + 4(-1) Pd = +2 Since there are four monodentate ligands, the metal ion has a coordination number of four. 2. For this problem, the geometries have been given to you. It is important to remember that these geometries are experimentally determined. Although we have the ability to predict the geometry, our predictions are less reliable than predictions concerning the shape of main group molecules. a. [Pt(en)Cl2], dichloro(ethylenediamine)platinum(II) Cl _ Cl _ __ ENGAGE in STEM is funded through the U.S Dept.Ptof_ Education, Hispanic Serving Institutions (H.S.I), _ __ STEM & Articulation Programs, Cooperative Arrangement Agreement Grant N N (There is only one structure for a square planar geometry and this formula.) b. [Pd(CO)2(H2O)Cl]+, aquadicarbonylchloropalladium(II) Cl __ Pd_ _ __ CO OH2 CO __ CO __ H2O c. _ __ _ Pd__ cis-aquadicarbonylchloropalladium(II) Cl trans-aquadicarbonylchloropalladium(II) OC [Fe(CO)4Cl2)]+, tetracarbonyldichloroiron(III) OC ___ OC Cl ____ Fe ____ OC ___ Cl OC OC ___ OC Cl ____ Fe ____ Cl d. trans-tetracarbonyldichloroiron(III) ___ CO cis-tetracarbonyldichloroiron(III) OC [Cr(CO)3(NH3)3]3+, tricarbonyltriamminechromium(III) OC ___ OC H3N ____ Fe ____ NH3 ___ H3N OC OC ___ OC H3N ____ Fe ____ OC ___ H3N mer-tricarbonyltriamminechromium(III) NH3 fac-tricarbonyltriamminechromium(III) 3. Linkage isomers are a form of structural isomer, where the formulas are the same, but the bonding is different. There are two linkage isomers for [Mn(NH3)5(NO2)]2+, pentaamminenitromanganese(II), above, and pentaamminenitritomanganese(II), below. Note, the formulas for these isomers are generally written so as to identify the difference in bonding pentaamminnitromanganese(II), [Mn(NH3)5(NO2)]2+: ___ NH3 NH3 H3N ____ Mn ____ NO2 ___ H3N NH3 pentamminenitritomanganese(II), [Mn(NH3)5(ONO)]2+: ___ NH3 NH3 H3N ____ Mn ____ ONO ___ H3N NH3 4. In writing the formula of a coordination compound (complex), be sure to follow the guidelines provided in class. a. hexaaquanickel(II) chloride [Ni(H2O)6]Cl2 b. pentacarbonylchloromanganese(I) Mn(CO)5Cl c. ammonium diaquatetrabromovanadate(III) NH4[V(H2O)2Br4] d. tris(ethylenediamine)cobalt(III) trioxalatoferrate(III) [Co(en)3][Fe(C2O4)3] 5. In naming coordination compounds (complexes), be sure to follow the guidelines provided in class. a. [Cu(CN)4]2- tetracyanocuprate(II) b. [Mn(CO)3(NO2)3]2+ tricarbonyltrinitritomanganese(V) c. Na[Cr(H2O)2(C2O4)2] sodium diaquadioxalatochromate(III) d. [Co(en)3][Fe(CN)6] tris(ethylenediamine)cobalt(III) hexacyanoferrate(III)