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Theory:
According to Newton's 2nd law F net = ma, where F net is the net force performing on the
object of mass m and a is the resultant acceleration of the object.
For cart mass ma on horizontal track with a cord attached over a pulley to hanging mass m2
,the force Fnet on the entire system (cart and hanging mass) is the weight of the hanging
mass, Fnet= m2g
According to Newton's 2nd law ,this net force should be equal to ma, where m is the total
mass that being accelerated, which in this case is m1+m2. Hence , this will lead to
𝑚−𝑔
m2g=(m1+m2)a . Hence , the theoretical acceleration of the system is a= 𝑚1+𝑚2
In this lab , the acceleration must be measured from the a velocity-time graph. Since
acceleration is defined as the change in the velocity per unit time, then the slop of the
velocity graph equals the acceleration.
Question number 3 answer is :
. Since acceleration is defined as the change in the velocity per unit time, then the slop of
the velocity graph equals the acceleration.
Ola M. AlShamlan
200800179
Part B:- Constant Mass
1. Add several masses to the cart: 500-g, 200-g, 50-g, 20-g and two 10-g.
Measure and record the mass of the cart plus the extra masses.
2. Follow the steps 4—14 from part A with only the 10-g mass hanging
from the string to obtain data for 1st run.
3. For run # 2, move 10-g from the top of the cart to the hanging mass.
Record the total mass hanging at the end of the string.
4. Record the motion of the cart as described in steps 11—14 from part
A.
5. For run # 3, move the two 10-g hanging masses back to the cart and
transfer the 50-g to the end of the string. Record the total mass
hanging at end of the string.
6. Record the motion of the cart as steps 11-14 from part A.
7. Finally for run # 4, transfer 10-g mass to the masses at the end of the
string. Record the total mass hanging.
8. Record the motion of the cart as steps 11-14 from part A.
Run
Hanging
Mass (kg)
Fnet (N)
Acceleration
calculated
from theory
(m/s2)
Acceleration Percenta
measured ge Error
from run
%
(m/s2)
differen
ce
#1
01
.0981
.o93
.199(+)(-)
0.93
.0977=.10
#2
01
.1962
.188
.208(+)().498=.158
#3
01
.411
.469
.580(+)().245=.33
1. What happens to an object’s acceleration if the net force applied to
the object is kept constant but the object’s mass increases?
Since the mass is constant, acceleration will increase linearly with
the force applied.
This describes the ordinary non-relativistic situation described by
Newton's 2nd law of motion, F=MA, or for this purpose: A=F/M
Shahad aldossary
201000495