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There are two ways to figure out whether power is positive (dissipated by the element) or negative (generated by the element). Approach 1 is to look at the problem intuitively (which is what I focused on in lecture) Is positive current entering through the positive terminal? Then P is positive. Is positive current entering through the negative terminal? Then P is negative. Be aware that P is also negative if negative current enters through the positive terminal or if positive current heads away from the positive terminal (refer to Figure 1.15b in the textbook). Approach #2 is to take a more rigorous treatment of power, i.e. P = Iab Vab or P = Iba Vba where Vab is the voltage from point a to point b, Iab is the current from point a to point b, etc. Consider how this applies in the following problem (which we worked out at the end of class): –2 v A 2v B -2 A Using the intuitive approach, the positive terminal should be assigned to B and the negative terminal to A. (since B has a higher potential/voltage). The current is actually flowing from left to right. So since positive current is entering the negative terminal, power is being generated, i.e. P = -8 W. Using the rigorous approach, Vab = Va – Vb = –2 – 2 = –4 v. Iab = 2 A, so P = Vab Iab = –4 * 2 = –8 W. Alternatively, Vba = Vb – Va = 2 – (–2) = 4 v. Iba = –2 A, so P = Vba Iba = 4 * –2 = –8 W. I don’t care which method you use. Just get the right answer. You can always use the other method to check your work. Try this technique on the following: 1v 0v A B 1A (answer: P = + 1 W)