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There are two ways to figure out whether power is positive (dissipated by the element) or
negative (generated by the element). Approach 1 is to look at the problem intuitively
(which is what I focused on in lecture) Is positive current entering through the positive
terminal? Then P is positive. Is positive current entering through the negative terminal?
Then P is negative. Be aware that P is also negative if negative current enters through the
positive terminal or if positive current heads away from the positive terminal (refer to
Figure 1.15b in the textbook).
Approach #2 is to take a more rigorous treatment of power, i.e.
P = Iab Vab
or P = Iba Vba
where Vab is the voltage from point a to point b, Iab is the current from point a to point b,
etc.
Consider how this applies in the following problem (which we worked out at the end of
class):
–2 v
A
2v
B
-2 A
Using the intuitive approach, the positive terminal should be assigned to B and the
negative terminal to A. (since B has a higher potential/voltage). The current is actually
flowing from left to right. So since positive current is entering the negative terminal,
power is being generated, i.e. P = -8 W.
Using the rigorous approach, Vab = Va – Vb = –2 – 2 = –4 v. Iab = 2 A, so P = Vab Iab = –4
* 2 = –8 W. Alternatively, Vba = Vb – Va = 2 – (–2) = 4 v. Iba = –2 A, so P = Vba Iba = 4 *
–2 = –8 W.
I don’t care which method you use. Just get the right answer. You can always use the
other method to check your work.
Try this technique on the following:
1v
0v
A
B
1A
(answer: P = + 1 W)