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11 Find the current through the 3Ω resistor if the entire combination is connected across a 24V source of emf. 5Ω 4Ω 5Ω 3Ω 24V 6Ω 9Ω 9.94 V 6Ω 8Ω 9.94 V 9Ω 9Ω 24V 6Ω 2.34 A 9.94 V 9Ω 24V 10.24 2.34 A 2. Identify the unknown: I3=? 3. Work backwards using what you know about series / parallel 9Ω 24V 1. First simplify the circuit 4.24 Ω • I3=I5 Current is same in series • I3= I8 b/c they are equivalent • V4.24= V8= V9 b/c they are parallel • I6= I10.24 Current is same in series 4. Get crackin’ find I10.24 first I10.24 = VT/R10.24 = 24/10.24 = 2.34 A 5. To find V8 you’ll need to find V4.24 V4.24 = I4.24R4.24 = (2.34 A)(4.24) =9.94V 11 Find the current through the 3Ω resistor if the entire combination is connected across a 24V source of emf. 5Ω 4Ω 5Ω 3Ω 24V 6Ω • V4.24= V8= V9 b/c they are parallel 9Ω • I6= I10.24 Current is same in series 8Ω 24V 6Ω 2.34 A 9Ω 7. Realize that I8= I3 Feel victorious! 9Ω 6Ω 6. Now find I8 I8 = V8/R8 = 9.94/8 = 1.24 A 9.94 V 2.34 A 9.94 V 9Ω 24V • I3=I5 Current is same in series • I3= I8 b/c they are equivalent 9Ω 24V Work backwards using what you know about series / parallel 10.24 2.34 A 4.24 Ω I3 = 1.24 A