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• Chapter 4 Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Goals for Chapter 4 • To understand force – either directly or as the net force of multiple components. • To study and apply Newton’s First Law. • To study and apply the concept of mass and acceleration as components of Newton’s Second Law. • To differentiate between mass and weight. • To study and apply Newton’s Third Law. • To open a new presentation of problem data in a free body diagram. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Dynamics, a new frontier • Stated previously, the onset of physics separates into two distinct parts: – statics and – dynamics. • So, if something is going to be dynamic, what causes it to be so? – A force is the cause, it is either • pushing or • pulling. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Types of Force Illustrated I – Figure 4.1 Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Types of Force II – Figure 4.2 • Single or net – Contact force – Normal force – Frictional force – Tension – Weight Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley A force may be resolved into components – Figure 4.4 •Fx = F CosΘ •Fy = F SinΘ Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Components and Resultants II – Figure 4.6 • An example of component resolution. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley R = F1 + F2 + F3 + ……..= Σ F, (resultant, and vector sum, of forces) Rx = Σ Fx , Ry = Σ Fy (components of vector sum of forces) Once we have the components Rx and Ry, we can find the magnitude and direction of the vector R. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley HOMEWORK 3; 5; 12; 13; 17; 18; 20; 22; 26; 28; 30; 31; 33; 35; 36; 37; 38 Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Newton’s First Law – Figure 4.7 •“Objects at rest tend to stay at rest and objects in motion tend to stay in motion in a straight line unless it is forced to change that state by forces acting on it” Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley R = F1 + F2 = 0 • Zero resultant force is equal to no force at all. • When an object is acted on by no forces or by several forces whose vector sum (resultant) is zero, we say that the object is in equilibrium, R = Σ F = 0 (equilibrium under zero resultant force) Each component of R must be zero, so Σ Fx = 0, Σ Fy = 0. (object in equilibrium) Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley We determine effect with the net force. – Figure 4.8 Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Mass and Newton’s Second Law II – Figure 4.12 •Let’s examine some situations with more than one mass. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley INERTIA Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Newton’s Second Law of Motion (Vector Form) The vector sum (resultant) of all the forces acting on an object equals the object’s mass times its acceleration : ΣF = ma The acceleration a has the same direction as the resultant force ΣF. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Newton’s Second Law of Motion (Components Form) For an object moving in a plane, each component of the total force equals the mass times the corresponding component of acceleration: ΣFx = max Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley ΣFx = max Definition of the newton One newton is the amount of force that gives an acceleration of 1 meter per second squared to an object with a mass of 1 kilogram. That is, 1 N = (1 kg) ( 1 m/s2) Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley ON THE MOON Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Measurement of mass – Figure 4.20 •Since gravity is constant, we can compare forces to measure unknown masses. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Forces are the origin of motion Forces Acceleration a=F/m Velocity v= v0 + at Position x = x0 + v0t + ½ at2 Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Forces and free body diagrams • we account for the forces and draw a free body diagram. •In this case, the net force is unbalanced. •This is a good example of forces in dynamics. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Newton’s Third Law Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Newton’s Third Law •“For every action there is an equal and opposite reaction.” •Rifle recoil is a wonderful example. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Newton’s Third Law For two interacting objects A and B, the formal statement of Newton’s third law is FA on B = -FB on A Newton’s own statement, translated from the latin of the Principia, is To every action there is always opposed an equal reaction; or, the mutual actions of two objects upon each other are always equal, and directed to contrary parts. Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Free-Body Diagram Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Use free body diagrams in any situation – Figure 4.24 •Find the object of the focus of your study and collect all forces acting upon it Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley Homework • 3, 9, 14, 20, 21, 23, 30, 34, 41, 52 Copyright © 2007 Pearson Education, Inc. publishing as Addison-Wesley