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MATH 408 SPRING 2010 QUIZ 3 1. Suppose X1 , X2 , . . . , Xn are independent normal random variables with Pn Xi −µ 2 mean µ and variance σ 2 . Let Wn = . What is the disi=1 σ tribution of Wn ? Solution. Xi − µ = Z ∼ N (0, 1) σ so n X Wn = Zi2 ∼ χ2n i=1 i.e. Wn is the sum of n standard normals squared, so it is chi-squared with n degrees of freedom. 2 ) distribution and Y1 , . . . , Ym 2. Let X1 , . . . , Xn be a sample from an N (µX , σX be an independent random sample from a N (µY , σY2 ) distribution. Show 2 /SY2 > c) (You may leave your how to use the F distribution to find P (SX answer in the form of a probability involving a random variable with F distribution, but be sure to include the degrees of freedom). (HINT: a. (n − 1)S 2 /σ 2 has a χ2n−1 distribution with n − 1 degrees of freedom. b. The random variable W has F distribution with m and n degrees of freedom if U/m W = , V /n where U and V are independent chi-square random variables with m and n degrees of freedom, respectively.) From part a of the hint, we have 2 (n − 1)SX ∼ χ2n−1 2 σX (m − 1)SY2 ∼ χ2m−1 . σY2 From part b of the hint we know that 2 (n−1)SX /(n 2 σX 2 (m−1)SY 2 σY − 1) /(m − 1) = W ∼ Fn−1,m−1 . Now we simplify W to obtain W = 2 2 SX σY 2 2 , SY σX 1 2 QUIZ 3 hence P 2 2 2 SX SX σY σY2 >c = P 2 > c σ2 XY2 SY2 σX X σY2 = P W >c 2 , σX where W ∼ Fn−1,m−1 .