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Quiz 4 Math 220 1. It is reasonable to assume the heights of male college students are normally distributed. It is known the mean height is 70 inches with standard deviation 2.8 inches. 1). You choose a student at random. What is the probability he is taller than 71 inches? ) = P (z > 0.36) = 1 − 0.6406 = 0.3594. P (x > 71) = P (z > 71−70 2.8 2). You choose a SRS of 25 students. What is the probability the mean height of your sample is bigger than 71 inches? Note σx̄ = √2.8 = 0.56. 25 P (x̄ > 71) = P (z > 71−70 ) = P (z > 1.79) = 1 − P (z ≤ 1.79) = 0.56 1 − 0.9633 = 0.0367. 2. A manager in a baby food factory suspects the containers of the baby food in his factory are underfilled. The average net weight of 16 containers he randomly took is 497.5 grams. Suppose the net weights of the containers follow a normal distribution with a known standard deviation σ = 3 grams. 1). Get a 95% confidence interval for µ, the mean weight of baby food containers in the factory. What is the margin of error of your confidence interval? x̄ ± z0.025 √σn = 497.5 ± 1.96 √316 = (496.03, 498.97) grams. The margin of error is 1.96 ∗ √316 = 1.47. 2). Suppose it is desired the margin of error of the 95% CI is 1 gram. What sample size is needed to achieve this? Set 1.96 ∗ √3n = 1, we get n ≈ 35. or n = ( 1.96∗3 )2 ≈ 35. 1 1