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Testing Means with small samples • Critical Value from the T-table – Use the one-tail heading for left or right tail • Make negative for left-tail – Use the two-tails heading for two tailed test – Remember degrees of freedom • For Example 1. 2. 3. 4. H0: μ ≥ 25, n = 18, Degree of confidence = 99% H0: μ = 110, n = 25, Degree of confidence = 95% H0: μ ≤ 1.5, n = 12, Degree of confidence = 90% H0: μ = 74, n = 28, Degree of confidence = 99.9% Live example/Your Turn • What would you guess to be average age of South students’ cars? – Let’s do a survey!! • What would you guess to be minimum number of colleges that average South student’s applied to? – Let’s take a sample!! Worksheet Sample mean = Original claim Opposite claim Degree of confidence Test statistics Critical region •Two-tailed (H0 =) •Left tailed (H0 ) •Right tailed (H0 ) Critical value Reject or accept? n= s= •Label null and alternative hypothesis Worksheet Sample mean = Original claim Opposite claim Degree of confidence Test statistics Critical region •Two-tailed (H0 =) •Left tailed (H0 ) •Right tailed (H0 ) Critical value Reject or accept? n= s= •Label null and alternative hypothesis Testing Hypothesis with Small Samples • We use the T (Student) table (A-3) to find the critical value – • We need to know the degrees of freedom, the significance level (alpha), and the number of tails Calculator: – – – [STAT] TESTS 1: T-Test… • μ0 is the benchmark. • X-bar is the mean • Sx is the standard deviation • n is the sample size • μ select the format of H1 Homework: Test the claims 1. 2. 3. 4. 5. Claim: Student population has a mean GPA of 2.0. A sample of 24 students has a mean is 2.35 and a standard deviation is 0.70. Use a 95% degree of confidence Claim: An SAT prep class produces scores above 1700. A sample of 15 students has a mean is 1685 and a standard deviation is 170. Use a 99% degree of confidence Claim: The average college student needs at least 5 years to get a degree. A sample of 20 students has a mean of 5.15 years and the standard deviation is 1.68. Use a 90% degree of confidence The following list contains the repair costs for five BMW cars used in a controlled crash test: 797 571 904 1147 418. Use this sample to text the claim that BMW’s repair costs are under $1000. Using a sample of 25 adults whose mean body temperature was 98.24 (standard deviation = 0.56), Test the claim that the mean body temperature for the population is 98.6 Homework #1 Sample mean = 2.35 n = 24 s = 0.07 Original claim µ = 2.0 (H0) Opposite claim µ ≠ 2.0 (H1) Label null and alternative hypothesis Degree of confidence 95% Test statistics t = 2.45 Critical region •Two-tailed (H0 =) •Left tailed (H0 ) •Right tailed (H0 ) Critical value Reject or accept? p-value = 0.022 < 0.05 Reject null, reject original claim Homework #2 Sample mean = 1685 n = 15 s = 170 Original claim µ > 1700 (H0) Opposite claim µ ≤ 1700 (H1) Label null and alternative hypothesis Degree of confidence 99% Test statistics t = -0.342 Critical region •Two-tailed (H0 =) •Left tailed (H0 ) •Right tailed (H0 ) Critical value Reject or accept? p-value = 0.631 > 0.01 FRT null, FTR original claim Homework #3 Sample mean = 5.15 n = 20 s = 1.68 Original claim µ ≥ 5(H0) Opposite claim µ < 5 (H1) Label null and alternative hypothesis Degree of confidence 90% Test statistics t = 0.399 Critical region •Two-tailed (H0 =) •Left tailed (H0 ) •Right tailed (H0 ) Critical value Reject or accept? p-value = 0.653 > 0.1 FRT null, FRT original claim Homework #4 Sample mean = 588 n=5 s = 424 Original claim µ < 1000 (H1) Opposite claim µ ≥ 1000 (H0) Label null and alternative hypothesis Degree of confidence 95% Test statistics t = -2.17 Critical region •Two-tailed (H0 =) •Left tailed (H0 ) •Right tailed (H0 ) Critical value Reject or accept? p-value = 0.048 < 0.05 Reject null, accept original claim Homework #5 Sample mean = 98.24 n = 25 s = 0.56 Original claim µ = 98.6 (H0) Opposite claim µ ≠ 98.6 (H1) Label null and alternative hypothesis Degree of confidence 95% Test statistics t = -3.214 Critical region •Two-tailed (H0 =) •Left tailed (H0 ) •Right tailed (H0 ) Critical value Reject or accept? p-value = 0.0037 < 0.05 Reject null, reject original claim