Download 8.4-8.6 Electron Configuration, The Explanatory Power of the

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Noble gas wikipedia , lookup

Period 6 element wikipedia , lookup

Period 3 element wikipedia , lookup

Period 5 element wikipedia , lookup

Period 2 element wikipedia , lookup

Tennessine wikipedia , lookup

Transcript
8.4-8.6 Electron Configuration, The Explanatory Power of the Quantum Mechanical Model, and a Few Periodic Trends
Valence vs. Core Electrons
• The key connection between the macroscopic world (an
elements chemical properties) and the atomic world (an
atom’s electronic structure) lies in these outer most electrons.
• The reason that elements within the same group have similar
chemical properties is because they have the same number of
valence electrons.
• Valence electrons, those in the outer most principle energy
level, are those that are most important in chemical bonding
because they are the most loosely held.
• Core electrons are the electrons in lower complete principle
energy levels.
Let’s Try a Practice Problem
Write an electron configuration for phosphorus.
Identify the valence electrons and core electrons.
P 1s22s22p63s23p3 or [Ne] 3s23p3
Phosphorus has 5 valence electrons and 10
core electrons.
Orbital Blocks on the Periodic Table
• The number of columns (groups) in a block
corresponds to the maximum number of electrons
that can occupy the particular sublevel of that
block.
s block: groups 1-2 (1A-2A)
p block: groups 13-18 (3A-8A)
d block: groups 3-12 transition metals (Bs)
f block: inner transition metals (below the main table)
Let’s Try a Practice Problem
Use the periodic table to write the electron
configuration of bismuth (Bi).
Bi [Xe] 6s24f145d106p3
Exceptions to aufbau’s priciple
• The patterns that we have discussed allow us to
accurately predict the electron configurations for
most of the elements in the periodic table.
However there are a few elements that have been
proven, based on spectroscopy, to have a more
stable electron configuration that is irregular.
Memorization of the few exceptions is beyond the
scope of the AP exam!
The Explanatory Power of the
Quantum-Mechanical Model
• The number of valence electrons that an element
contains determines the chemical properties of the
element.
• Even though we do not explore the quantum
mechanical model quantitatively in this curriculum,
mathematical computation has proven that the valence
electrons of noble gases have particularly low PE, so
they are unreactive.
• Elements with electron configurations close to noble
gases are the most reactive because they only need to
lose or gain 1e- to achieve stability.
Periodic Trends: Atomic Size
• Atomic radius:
– the covalent radius of an atom is ½ the distance between
two bonded atoms of the same non-metal.
• The approximate bond length between two covalently
bonded atoms is the sum of the two atoms radii.
• As we move down a group (or family) on the periodic
table, atomic radius increases.
• As we move across a period on the periodic table,
atomic radius decreases.
Reasons for the Trends in Atomic
Radius
• Atomic radius increases down a group because as
we move down a group, we enter higher principle
energy levels (valence electrons are further from
the nucleus).
• Atomic radius decreases across a period because
as we move from left to right across a period, the
elements experience a effective nuclear charge
(Zeff becomes more positive) resulting in a
stronger attraction of the valence electrons to the
nucleus, and a smaller atomic radii.
Let’s Try a Practice Problem!
Which electrons experience a greatest effective
nuclear charge?
(a) the valence electrons in Mg
(b) the valence electrons in Al
(c) the valence electrons in S
(c) The valence electrons in S will experience a greater
nuclear charge because they lie further to the right of
the same period.
Let’s Try Another!
On the basis of periodic trends, chose the larger atom in each pair (if possible).
(a)
(b)
(c)
(d)
Sn or I
Ge or Po
Cr or W
F or Se
(a) Sn is further to the left of the same period experiencing a less effective nuclear
charge.
(b) Can’t tell based on trend alone
(c) W is further down the same group meaning that it’s valence electrons are in a
higher energy level.
(d) Se is both further down and to the left of the periodic table, indicating a larger
radius.
• Mention Ionization Energy for quiz!!!
8.4-8.6 Pg. 376-377 #’s 62, 64, 92
Study For Quiz On 8.1-8.6