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ENZYMES Introduction Enzymes are biological catalysts that carry out thousands of chemical reactions in living cells. They are generally large proteins made up of several hundred amino acids. Enzymes often contain a nonproteinaceous group called the "prosthetic group" that is important in the reaction. Prosthetic groups include substances such inorganic cofactors (calcium, copper, magnesium, zinc, and manganese ions) and organic compounds (called co-enzymes) such as some B vitamins (niacin, flavin). In an enzyme-catalyzed reaction, the substance acted upon, or substrate, binds to a specialized region of the enzyme called the active site. The enzyme and substrate are held together in an "enzyme-substrate complex" by hydrophobic bonds, hydrogen bonds, and ionic bonds. The enzyme then converts the substrate to the reaction products in a process that often requires several chemical steps, and may involve forming or breaking covalent bonds. Finally, the products are released and the enzyme is ready to form another enzyme-substrate complex. The enzyme is not consumed as it carries out the reaction but is recycled again and again. One enzyme molecule can carry out thousands of reaction cycles every minute. The general "equation" summarizing enzyme action is: Enzyme + Substrate - Enzyme-Substrate complex Product + Enzyme ……or, simply E + S ES P + E The rate of reaction will depend upon the concentration of enzyme, the concentration of the substrate, and "environmental" factors such as the presence of inhibitors, the pH of the medium, and temperature. Enzyme Kinetics If we start with a fixed concentration of enzyme and measure the rate of enzyme activity with different substrate concentrations [S], enzymes typically show what is called “first order kinetics.” At first there is a linear relationship between the rate (velocity, V) of the reaction and the amount of substrate present (point A below), but with higher levels of substrate, the reaction rate levels off, reaching a maximal velocity, or Vmax ( C ). At Vmax, the enzyme is working as fast as it can and adding more substrate will not matter. The substrate concentration that produces a rate that is 1/2 of Vmax (B) is called the Km (Michaelis-Menton constant) and is characteristic of the enzyme and the substrate. Km is a measure of the affinity of the enzyme for the substrate – the smaller the Km, the greater the affinity. Km 1 Each enzyme is specific for a certain reaction because its amino acid sequence is unique and causes it to have a unique three-dimensional structure. The "business" end of the enzyme molecule, the active site, also has a specific shape so that only one or a few of the thousands of compounds present in the cell can interact with it. If there is a prosthetic group on the enzyme, it will form part of the active site. Any substance that blocks or changes the shape of the active site will interfere with the activity and efficiency of the enzyme. Objectives In this exercise you will study the enzyme catalase, which accelerates (catalyzes) the breakdown of hydrogen peroxide (a common end product of oxidative metabolism) into water and oxygen, according to the summary reaction: 2H2 O2 + catalase 2H2O + O2 + catalase This catalase-mediated reaction is extremely important in the cell because it prevents the accumulation of hydrogen peroxide, a strong oxidizing agent that tends to disrupt the delicate balance of cell chemistry. Catalase is found in animal and plant tissues. You will measure its rate of activity under different conditions. A paper disc will be immersed in the enzyme solution, and then placed in the hydrogen peroxide substrate. The oxygen produced will become trapped in the disc and will give it buoyancy. The time measured from the moment the disc enters the substrate to the time it reaches the surface of the solution is a measure of the rate of the enzyme activity. Keep the catalase in the ice bath throughout the experiment. General Procedure: Use a hole-punch to generate a number of small discs from the filter paper and place them in a plastic petri dish. Using forceps, immerse a filter disc "punch" into the catalase solution. Allow the disc to absorb the enzyme solution for a few seconds, remove excess enzyme solution by touching the edge to a paper towel for a few seconds. Drop the disc into the first substrate solution (use forceps to place the disc in the fluid). The disc will sink rapidly into the solution. The oxygen produced from the breakdown of the hydrogen peroxide by catalase becomes trapped in the fibers of the disc causing the disc to float to the surface of the solution. Rate of Enzyme Reaction = 1 / disc rising time. The time (t) in seconds, from the instant the disc enters into the solution to the time it floats back to the surface is inversely proportional to enzyme activity: So, the longer it takes to rise, the slower the reaction rate. Repeat the procedure twice for each test and average the results. Record your results in the tables provided and then plot your data. 2 Test 1: Effect of Substrate Concentration To determine the effect of substrate concentration on enzyme activity obtain six 50-ml plastic beakers and label them as follows: 0%, 0.5%, 1.0 %, 1.5% 2.0% and 3% H2O2 (Note: They may already be labeled). Add 30 mls of the proper (as outlined above) H2O2 solution to each beaker. Using the filter disc procedure described above, determine the rate of the reaction at the various substrate concentrations. Record your results in the Table below. Repeat the procedure twice for each substrate concentration and average the results. Substrate % H2O2 0 Time 1 (Seconds) Time 2 (Seconds) Time 3 (Seconds) Average Time Rate (1/Ave Time) 0.5 1.0 1.5 2.0 3.0 (Note: if the disc doesn’t rise within a few minutes, consider that it takes an infinite amount of time. 1/infinity is “0” for our purposes) Plot your results (Make sure you label the y-axis and estimate the Km and Vmax). 0 0.5 1.0 1.5 Substrate Concentration (% H2O2) 2.0 3.0 3 Test 2: Effect of Enzyme Inhibitor Hydroxylamine attaches to the iron atom of catalase (iron is a cofactor that is part of the active site) and thereby interferes with the formation of enzyme-substrate complex. Add 1 drop (50 microliters) of 0.1% hydroxylamine into each beaker of hydrogen peroxide substrate. Stir or swirl the solution to make sure the hydroxylamine is well diffused, and then measure the activity as above and record your data below. Plot your data on the graph on the previous page. Indicate the inhibited rates with a different style point. For example, if you used filled circles ● to indicate the normal results, use a box ❑ or asterix * to note the inhibited rates. Rates with Inhibitor Substrate % H2O2 0 Time 1 Time 2 Time 3 Average Time Rate (1/Ave Time) 0.5 1.0 1.5 2.0 3.0 4 Lab Report Questions NAME: _______________________ Lab: Mon 4:00, 7:00, Tues. 4:00, 7:00 What are the key features of an enzyme? Define active site. What are the two working models of enzyme action? Which one is believed to be more accurate? How is the rate of enzyme activity affected by increasing the concentration of the substrate? Was there any evidence of enzyme saturation? What do you think would happen if you tested a substrate concentration of 10%? What was the effect of the hydroxylamine on the enzyme reaction rates? Did higher amounts of substrate overcome the inhibition? What are some of the uncontrolled variables in this experiment and how might they have affected your results? 5 Data Sheet Effect of Substrate Concentration on Reaction Rates Substrate Time 1 Time 2 Time 3 % H2O2 0 Average Time Rate (1/Ave Time) 0.5 1.0 1.5 2.0 3.0 Rates With Inhibitor Substrate Time 1 % H2O2 0 Time 2 Time 3 Average Time Rate (1/Ave Time) 0.5 1.0 1.5 2.0 3.0 Plot your data below. (Make sure you label the y axis and indicate the “Km” and Vmax). 0 0.5 1.0 1.5 2.0 Substrate Concentration (% H2O) 3.0 6