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General Physics (PHY 2130) Lecture 15 • Energy Kinetic and potential energy Conservative and non-conservative forces http://www.physics.wayne.edu/~apetrov/PHY2130/ Lightning Review Last lecture: 1. Work and energy: work: connection between forces and energy kinetic energy Review Problem: . Potential Energy • Potential energy is associated with the position of the object within some system • Potential energy is a property of the system, not the object • A system is a collection of objects or particles interacting via forces or processes that are internal to the system • Units of Potential Energy are the same as those of Work and Kinetic Energy Gravitational Potential Energy • Gravitational Potential Energy is the energy associated with the relative position of an object in space near the Earth’s surface • Objects interact with the earth through the gravitational force • Actually the potential energy of the earth-object system Potential Energy: example Work and Gravitational Potential Energy • Consider block of mass m at initial height yi • Work done by the gravitational force Wgrav = (F cosθ ) s = (mg cosθ ) s, but : s = yi − y f , cosθ = 1, Thus : Wgrav = mg (yi − y f ) = mgyi − mgy f . This quantity is called potential energy: PE = mgy Note: Wgravity = PEi − PE f Important: work is related to the difference in PE’s! Reference Levels for Gravitational Potential Energy • A location where the gravitational potential energy is zero must be chosen for each problem • The choice is arbitrary since the change in the potential energy is the important quantity • Choose a convenient location for the zero reference height • often the Earth’s surface • may be some other point suggested by the problem Reference Levels for Gravitational Potential Energy A location where the gravitational potential energy is zero must be chosen for each problem The choice is arbitrary since the change in the potential energy gives the work done Wgrav1 = mgyi1 − mgy f1 , Wgrav 2 = mgyi2 − mgy f 2 , Wgrav 3 = mgyi3 − mgy f 3 . Wgrav1 = Wgrav 2 = Wgrav 3 . 9 Example: What is the change in gravitational potential energy of the box if it is placed on the table? The table is 1.0 m tall and the mass of the box is 1.0 kg. First: Choose the reference level at the floor. U = 0 here. ΔU g = mgΔy = mg (y f − yi ) ( ) = (1.0 kg ) 9.8 m/s2 (1.0 m − 0 m) = +9.8 J 10 Example continued: Now take the reference level (U = 0) to be on top of the table so that yi = -1.0 m and yf = 0.0 m. ΔU g = mgΔy = mg (y f − yi ) ( ) = (1 kg ) 9.8 m/s2 (0.0m − (− 1.0 m)) = +9.8 J The results for the energy difference do not depend on the location of U = 0! ConcepTest At the bowling alley, the ball-feeder mechanism must exert a force to push the bowling balls up a 1.0-m long ramp. The ramp leads the balls to a chute 0.5 m above the base of the ramp. Approximately how much force must be exerted on a 5.0-kg bowling ball? 1. 200 N 2. 50 N 3. 25 N 4. 5.0 N 5. impossible to determine ConcepTest At the bowling alley, the ball-feeder mechanism must exert a force to push the bowling balls up a 1.0-m long ramp. The ramp leads the balls to a chute 0.5 m above the base of the ramp. Approximately how much force must be exerted on a 5.0-kg bowling ball? 1. 200 N 2. 50 N 3. 25 N 4. 5.0 N 5. impossible to determine Note: The force exerted by the mechanism times the distance of 1.0 m over which the force is exerted must equal the change in the potential energy of the ball. 13 More about Gravitational Potential Energy The general expression for gravitational potential energy is: GM1M 2 U (r ) = − r where U ( r = ∞) = 0 14 Example: What is the gravitational potential energy of a body of mass m on the surface of the Earth? GM e m GM 1M 2 U (r = Re ) = − =− r Re Conservative Forces • A force is conservative if the work it does on an object moving between two points is independent of the path the objects take between the points • The work depends only upon the initial and final positions of the object • Any conservative force can have a potential energy function associated with it Note: a force is conservative if the work it does on an object moving through any closed path is zero. Examples of Conservative Forces: • Examples of conservative forces include: • Gravity • Spring force • Electromagnetic forces • Since work is independent of the path: Wc = PEi − PE f : only initial and final points • Nonconservative Forces • A force is nonconservative if the work it does on an object depends on the path taken by the object between its final and starting points. • Examples of nonconservative forces • kinetic friction, air drag, propulsive forces Example: Friction as a Nonconservative Force • The friction force transforms kinetic energy of the object into a type of energy associated with temperature • the objects are warmer than they were before the movement • Internal Energy is the term used for the energy associated with an object’s temperature Friction Depends on the Path • The blue path is shorter than the red path • The work required is less on the blue path than on the red path • Friction depends on the path and so is a nonconservative force Conservation of Mechanical Energy • Conservation in general • To say a physical quantity is conserved is to say that the numerical value of the quantity remains constant • In Conservation of Energy, the total mechanical energy remains constant • In any isolated system of objects that interact only through conservative forces, the total mechanical energy of the system remains constant. Conservation of Energy • Total mechanical energy is the sum of the kinetic and potential energies in the system E = K +U = KE + PE Ei = E f KEi + PEi = KE f + PE f • Whenever nonconservative forces do no work, the mechanical energy of a system is conserved. That is Ei = Ef or ΔK = -ΔU. • Other types of energy can be added to modify this equation 22 What do you do when there are nonconservative forces? For example, if friction is present ΔE = E f − Ei = Wfric The work done by friction. Problem Solving with Conservation of Energy • Define the system • Select the location of zero gravitational potential energy • Do not change this location while solving the problem • Determine whether or not nonconservative forces are present • If only conservative forces are present, apply conservation of energy and solve for the unknown 24 Example: A roller coaster car is about to roll down a track. Ignore friction and air resistance. At what speed does the car reach the top of the loop? m = 988 kg 40 m 20 m y=0 (a) Idea: use conservation of energy: mechanical energy is the same! Ei = E f U i + Ki = U f + K f 1 2 mgyi + 0 = mgy f + mv f 2 v f = 2 g (yi − y f ) = 19.8 m/s ConcepTest A block initially at rest is allowed to slide down a frictionless ramp and attains a speed v at the bottom.To achieve a speed 2v at the bottom, how many times as high must a new ramp be? 1. 2. 3. 4. 5. 6. 1 2 3 4 5 6 ConcepTest A block initially at rest is allowed to slide down a frictionless ramp and attains a speed v at the bottom.To achieve a speed 2v at the bottom, how many times as high must a new ramp be? 1. 2. 3. 4. 5. 6. 1 2 3 4 5 6 Note: The gain in kinetic energy, proportional to the square of the block’s speed at the bottom of the ramp, is equal to the loss in potential energy. This, in turn, is proportional to the height of the ramp. Work Done by Varying Forces • The work done by a variable force acting on an object that undergoes a displacement is equal to the area under the graph of F versus x 28 Example: What is the work done by the variable force shown below? Fx (N) F3 F2 F1 x1 x2 x3 x (m) The work done by F1 is W1 = F1 (x1 − 0) The work done by F2 is W2 = F2 (x2 − x1 ) The work done by F3 is W3 = F3 (x3 − x2 ) The net work is then W1+W2+W3. Potential Energy Stored in a Spring • Involves the spring constant (or force constant), k • Hooke’s Law gives the force • F=-kx • F is the restoring force • F is in the opposite direction of x • k depends on how the spring was formed, the material it is made from, thickness of the wire, etc. 30 Example: (a) If forces of 5.0 N applied to each end of a spring cause the spring to stretch 3.5 cm from its relaxed length, how far does a force of 7.0 N cause the same spring to stretch? (b) What is the spring constant of this spring? (a) For springs F∝x. This allows us to write Solving for x2: F1 x1 = . F2 x2 F2 ⎛ 7.0 N ⎞ x2 = x1 = ⎜ ⎟(3.5 cm ) = 4.9 cm. F1 ⎝ 5.0 N ⎠ (b) What is the spring constant of this spring? Use Hooke’s law: F1 5.0 N k= = = 1.43 N/cm. x1 3.5 cm Or F2 7.0 N k= = = 1.43 N/cm. x2 4.9 cm 31 Example: An ideal spring has k = 20.0 N/m. What is the amount of work done (by an external agent) to stretch the spring 0.40 m from its relaxed length? Fx (N) kx1 x1=0.4 m x (m) W = Area under curve 1 1 2 1 2 = (kx1 )(x1 ) = kx1 = (20.0 N/m)(0.4 m ) = 1.6 J 2 2 2