Download Keys GEO SY13-14 Openers 2-13

Geometry Opener(s) 2/13
2/13
It’s World Radio Day, National Tortellini Day,
Confession Day, Exorbitant Price Day, Get a
Different Name Day, Clean Out Your Computer
Day, Dump Your Significant Jerk Day, Blame
Someone Else Day and Employee Legal
Awareness Day!!! Happy Birthday Feist, Robbie
Williams, Peter Gabriel, Jerry Springer, Stockard
Channing, Peter Tork, Carol Lynley, Oliver Reed,
Chuck Yeager, George Segal, Tennessee Ernie
Ford, Kim Novak, Grant Wood, Dorothy McGuire
and Bess Truman!!!
Agenda
1. Openers (5)
2. HW/CW Lecture: Do you want just 50/60%?
3. Individual Work: Cognitive Tutor
4. Exit Pass (5)
Standard(s)
 CCMS-HSS-CP.A.5: Recognize and explain the
concepts of conditional probability in everyday
language and everyday situations.
Essential Question(s)
 How do I recognize and analyze a conditional
statement?
Objective(s)
 Students will be able to (SWBAT) identify a
conditional statement.
 SWBAT rewrite a conditional statement in standard
if-then form.
 SWBAT differentiate between a hypothesis and a
conclusion.
 SWBAT transform a conditional into converse,
inverse and contrapositive forms.
 SWBAT determine the logical equivalence of
various conditional statements.
2/13
What to do today:
1. Do the opener.
2. Listen to yet another comment about your work.
3. Work on Cognitive Tutor.
4. Do the exit pass.
TODAY’S OPENER
Your opener today has two parts:
1. (P6) In another square of your opener, state
the property that justifies each statement.
2. (P1) Give me an example of the Distributive
Property..before and after. Then, in words,
explain what the distributive property does.
Answer?
The Last Opener
1. (P1) In another square of your opener, state the
property that justifies each statement.
2. (P6) Draw 2 right scalene s that are . Label
them. Then list the  parts.
Exit Pass
If mABD = 44 and mABC = 98 and D is in the interior of ABC, find mDBC.
Show all your steps and identify the properties you used to advance from one
step to another. Start with “Statement: mABD + mDBC = mABC Reason:
Given”.
Answer?
The Last Exit Pass
Write a conditional that is logically equivalent to its inverse.
Answer?
HOMEWORK Period 1
Text ?s, p. 112-113, #16-24 and #40-42.
HOMEWORK Period 6
Text ?s, p. 98, #20-25.
Extra Credit
Period 1
Period 6
Stephanie C. (3x)
Prisma
Ayelen (4x)
Saul (4x)
Alejandra (3x)
Magda
Stephanie M. (3x)
Tanya (2x)
Crystal
Demina
Sergio (5x)
Jesus (6x)
Cynthia (3x)
Jocelyn (5x)
Carolina (2x)
Melanie B. (4x)
Melanie G.
Maria
Lily (3x)
Denise
Imelda
Notes: Classifying Triangles
2/7
PICTURE
What are the 9 parts of a
triangle?
What are the 3 ways to
classify triangles by
sides?
What are the 4 ways to
classify triangles by
angles?
SYMBOLS /
DEFINITIONS /
VOCABULARY
Our Properties So Far…
Name/#
Description
2/11/14
Algebra
Geometry
Segments
Reflexive Property
Symmetric Property
Transitive Property
Addition &
Subtraction
Properties
Multiplication &
Division Properties
Substitution Property
Midpoint Theorem
(2.8)
Segment Addition
Postulate (2.9)
Angle Addition
Postulate (2.11)
Anything equals itself!
Switching preserves
equality!
If the 1st thing = a 2nd,
and that 2nd thing = a 3rd,
then that 1st thing = the
3rd.
If you add or subtract the
SAME thing from equal
things, then the resulting
things are STILL equal.
If you multiply or divide
the SAME thing from
equal things, then the
resulting things are STILL
equal.
If 2 things are equal, then
you can replace one with
the other in any equation
or expression.
A midpoint ‘divides’ a
segment into 2 =
segments.
A point between 2 other
collinear points divides a
segment into 2 parts of a
whole.
An point in the interior of
2 angles divides an angle
into 2 parts of a whole.
For all #s, x = x.
For all #s, if x = y, then y
= x.
For all #s, if x = y and y =
z, then x = z.
For all #s, if x = y, then x
+ z = y + z and x – z = y –
z.
For all #s, if x = y, then x
* z = y * z and x / z = y /
z.
For all #s, if x = y, then,
for example, x + 2 = w is
equivalent to y + 2 = w.
Supplement Theorem A linear pair is
supplementary.
(2.3)
Theorem 2.6: s supplementary to the same  or to  s are .
Adjacent s with 
Complement
noncommon sides are
Theorem (2.4)
complementary.
Theorem 2.7: s complementary to the same  or to  s are .
Vertical s are .
Vertical Angles
Theorem (2.8)
Angles
̅̅̅̅ ,
If M is the midpoint of 𝐴𝐵
̅̅̅̅̅  𝑀𝐵
̅̅̅̅̅.
then 𝐴𝑀
If M is between A and B,
̅̅̅̅̅ + 𝑀𝐵
̅̅̅̅ .
̅̅̅̅̅ = 𝐴𝐵
then 𝐴𝑀
If M is in the interior of
DOG, then mDOM =
mMOG. (The converse is
ALSO true!)
If A and B form a
linear pair, then they are
supplementary.
If BED and DEN have 
noncommon sides, then
they are complementary.
If 1 and 2 are vertical
s, then they are .