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Geometry Opener(s) 2/13 2/13 It’s World Radio Day, National Tortellini Day, Confession Day, Exorbitant Price Day, Get a Different Name Day, Clean Out Your Computer Day, Dump Your Significant Jerk Day, Blame Someone Else Day and Employee Legal Awareness Day!!! Happy Birthday Feist, Robbie Williams, Peter Gabriel, Jerry Springer, Stockard Channing, Peter Tork, Carol Lynley, Oliver Reed, Chuck Yeager, George Segal, Tennessee Ernie Ford, Kim Novak, Grant Wood, Dorothy McGuire and Bess Truman!!! Agenda 1. Openers (5) 2. HW/CW Lecture: Do you want just 50/60%? 3. Individual Work: Cognitive Tutor 4. Exit Pass (5) Standard(s) CCMS-HSS-CP.A.5: Recognize and explain the concepts of conditional probability in everyday language and everyday situations. Essential Question(s) How do I recognize and analyze a conditional statement? Objective(s) Students will be able to (SWBAT) identify a conditional statement. SWBAT rewrite a conditional statement in standard if-then form. SWBAT differentiate between a hypothesis and a conclusion. SWBAT transform a conditional into converse, inverse and contrapositive forms. SWBAT determine the logical equivalence of various conditional statements. 2/13 What to do today: 1. Do the opener. 2. Listen to yet another comment about your work. 3. Work on Cognitive Tutor. 4. Do the exit pass. TODAY’S OPENER Your opener today has two parts: 1. (P6) In another square of your opener, state the property that justifies each statement. 2. (P1) Give me an example of the Distributive Property..before and after. Then, in words, explain what the distributive property does. Answer? The Last Opener 1. (P1) In another square of your opener, state the property that justifies each statement. 2. (P6) Draw 2 right scalene s that are . Label them. Then list the parts. Exit Pass If mABD = 44 and mABC = 98 and D is in the interior of ABC, find mDBC. Show all your steps and identify the properties you used to advance from one step to another. Start with “Statement: mABD + mDBC = mABC Reason: Given”. Answer? The Last Exit Pass Write a conditional that is logically equivalent to its inverse. Answer? HOMEWORK Period 1 Text ?s, p. 112-113, #16-24 and #40-42. HOMEWORK Period 6 Text ?s, p. 98, #20-25. Extra Credit Period 1 Period 6 Stephanie C. (3x) Prisma Ayelen (4x) Saul (4x) Alejandra (3x) Magda Stephanie M. (3x) Tanya (2x) Crystal Demina Sergio (5x) Jesus (6x) Cynthia (3x) Jocelyn (5x) Carolina (2x) Melanie B. (4x) Melanie G. Maria Lily (3x) Denise Imelda Notes: Classifying Triangles 2/7 PICTURE What are the 9 parts of a triangle? What are the 3 ways to classify triangles by sides? What are the 4 ways to classify triangles by angles? SYMBOLS / DEFINITIONS / VOCABULARY Our Properties So Far… Name/# Description 2/11/14 Algebra Geometry Segments Reflexive Property Symmetric Property Transitive Property Addition & Subtraction Properties Multiplication & Division Properties Substitution Property Midpoint Theorem (2.8) Segment Addition Postulate (2.9) Angle Addition Postulate (2.11) Anything equals itself! Switching preserves equality! If the 1st thing = a 2nd, and that 2nd thing = a 3rd, then that 1st thing = the 3rd. If you add or subtract the SAME thing from equal things, then the resulting things are STILL equal. If you multiply or divide the SAME thing from equal things, then the resulting things are STILL equal. If 2 things are equal, then you can replace one with the other in any equation or expression. A midpoint ‘divides’ a segment into 2 = segments. A point between 2 other collinear points divides a segment into 2 parts of a whole. An point in the interior of 2 angles divides an angle into 2 parts of a whole. For all #s, x = x. For all #s, if x = y, then y = x. For all #s, if x = y and y = z, then x = z. For all #s, if x = y, then x + z = y + z and x – z = y – z. For all #s, if x = y, then x * z = y * z and x / z = y / z. For all #s, if x = y, then, for example, x + 2 = w is equivalent to y + 2 = w. Supplement Theorem A linear pair is supplementary. (2.3) Theorem 2.6: s supplementary to the same or to s are . Adjacent s with Complement noncommon sides are Theorem (2.4) complementary. Theorem 2.7: s complementary to the same or to s are . Vertical s are . Vertical Angles Theorem (2.8) Angles ̅̅̅̅ , If M is the midpoint of 𝐴𝐵 ̅̅̅̅̅ 𝑀𝐵 ̅̅̅̅̅. then 𝐴𝑀 If M is between A and B, ̅̅̅̅̅ + 𝑀𝐵 ̅̅̅̅ . ̅̅̅̅̅ = 𝐴𝐵 then 𝐴𝑀 If M is in the interior of DOG, then mDOM = mMOG. (The converse is ALSO true!) If A and B form a linear pair, then they are supplementary. If BED and DEN have noncommon sides, then they are complementary. If 1 and 2 are vertical s, then they are .