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A1 Algebraic expressions This icon indicates the slide contains activities created in Flash. These activities are not editable. For more detailed instructions, see the Getting Started presentation. 1 of 24 © Boardworks Ltd 2009 A1.1 Writing expressions 2 of 24 © Boardworks Ltd 2009 The birth of algebra Al-Khwarizmi (780-850 C.E) was a mathematician who lived in Baghdad. He is known as the ‘father of algebra’ because he wrote the first book on solving equations, ‘Hisab al-jabr w'al-muqabala’. What does the word al-jabr remind you of? “al-jabr" means "completion" and is the process of removing negative terms from an equation. His book was meant to teach people maths for practical use, and it was written entirely in words, without any symbols. These were developed later, by other mathematicians. 3 of 24 25 © Boardworks Ltd 2009 Using symbols for unknowns Look at this problem: + 9 = 17 The symbol stands for an unknown number. We can work out the value of . =8 because 8 + 9 = 17 4 of 24 25 © Boardworks Ltd 2009 Using symbols for unknowns Look at this problem: – The symbols In this problem, Two examples are, and 5 of 24 25 and =5 stand for unknown numbers. and can have many values. 12 – 7 = 5 or 3.2 – –1.8 = 5 are called variables because their value can vary. © Boardworks Ltd 2009 Using letter symbols for unknowns In algebra, we use letter symbols to stand for numbers. These letters are called unknowns or variables. Sometimes we can work out the value of the letters and sometimes we can’t. For example: We can write an unknown number with 3 added on to it as n+3 This is an example of an algebraic expression. 6 of 24 25 © Boardworks Ltd 2009 Writing an expression Suppose Jon has a packet of biscuits and he doesn’t know how many biscuits it contains. He can call the number of biscuits in the full packet, b. If he opens the packet and eats 4 biscuits, he can write an expression for the number of biscuits remaining in the packet as: b–4 7 of 24 25 © Boardworks Ltd 2009 Writing an equation Jon counts the number of biscuits in the packet after he has eaten 4 of them. There are 22. He can write this as an equation: b – 4 = 22 We can work out the value of the letter b. b = 26 That means that there were 26 biscuits in the full packet. 8 of 24 25 © Boardworks Ltd 2009 Writing expressions When we write expressions in algebra we don’t usually use the multiplication symbol ×. 5 × n or n × 5 is written as 5n. The number must be written before the letter. When we multiply a letter symbol by 1, we don’t have to write the 1. 1 × n or n × 1 is written as n. 9 of 24 25 © Boardworks Ltd 2009 Writing expressions When we write expressions in algebra we don’t usually use the division symbol ÷. Instead we use a dividing line as in fraction notation. n ÷ 3 is written as n 3 When we multiply a letter symbol by itself, we use index notation. n squared n × n is written as n2. 10 of 24 25 © Boardworks Ltd 2009 Writing expressions Here are some examples of algebraic expressions: n+7 a number n plus 7 5–n 5 minus a number n 2n 2 lots of the number n or 2 × n 6 n 6 divided by a number n 4n + 5 4 lots of a number n plus 5 n3 a number n multiplied by itself twice or n×n×n 3 × (n + 4) or 3(n + 4) a number n plus 4 and then times 3. 11 of 24 25 © Boardworks Ltd 2009 Writing expressions Miss Green is holding n number of cubes in her hand: Write an expression for the number of cubes in her hand if: She takes 3 cubes away. n–3 12 of 24 25 She doubles the number of cubes she is holding. 2 × n or 2n © Boardworks Ltd 2009 Equivalent expression match 13 of 24 25 © Boardworks Ltd 2009 Identities When two expressions are equivalent we can link them with the sign. x + x + x is identically For example: equal to 3x x + x + x 3x This is called an identity. In an identity, the expressions on each side of the equation are equal for all values of the unknown. The expressions are said to be identically equal. 14 of 24 25 © Boardworks Ltd 2009 A1.2 Collecting like terms 15 of 24 © Boardworks Ltd 2009 Like terms An algebraic expression is made up of terms and operators such as +, –, ×, ÷ and ( ). A term is made up of numbers and letter symbols but not operators. 3a + 4b – a + 5 is an expression. 3a, 4b, a and 5 are terms in the expression. 3a and a are called like terms because they both contain a number and the letter symbol a. 16 of 24 25 © Boardworks Ltd 2009 Collecting together like terms Remember, in algebra letters stand for numbers, so we can use the same rules as we use for arithmetic. In arithmetic: 5+5+5+5=4×5 In algebra: a + a + a + a = 4a The a’s are like terms. We collect together like terms to simplify the expression. 17 of 24 25 © Boardworks Ltd 2009 Collecting together like terms Remember, in algebra letters stand for numbers, so we can use the same rules as we use for arithmetic. In arithmetic: (7 × 4) + (3 × 4) = 10 × 4 In algebra: 7 × b + 3 × b = 10 × b or 7b + 3b = 10b 7b, 3b and 10b are like terms. They all contain a number and the letter b. 18 of 24 25 © Boardworks Ltd 2009 Collecting together like terms Remember, in algebra letters stand for numbers, so we can use the same rules as we use for arithmetic. In arithmetic: 2 + (6 × 2) – (3 × 2) = 4 × 2 In algebra: x + 6x – 3x = 4x x, 6x, 3x and 4x are like terms. They all contain a number and the letter x. 19 of 24 25 © Boardworks Ltd 2009 Collecting together like terms When we add or subtract like terms in an expression we say we are simplifying an expression by collecting together like terms. An expression can contain different like terms. 3a + 2b + 4a + 6b = 3a + 4a + 2b + 6b = 7a + 8b This expression cannot be simplified any further. 20 of 24 25 © Boardworks Ltd 2009 Collecting together like terms Simplify these expressions by collecting together like terms. 1) a + a + a + a + a = 5a 2) 5b – 4b = b 3) 4c + 3d + 3 – 2c + 6 – d = 4c – 2c + 3d – d + 3 + 6 = 2c + 2d + 9 4) 4n + n2 – 3n = 4n – 3n + n2 = n + n2 5) 4r + 6s – t 21 of 24 25 Cannot be simplified © Boardworks Ltd 2009 Algebraic perimeters Remember, to find the perimeter of a shape we add together the lengths of each of its sides. Write algebraic expressions for the perimeters of the following shapes: 2a Perimeter = 2a + 3b + 2a + 3b 3b = 4a + 6b 5x 4y x 5x 22 of 24 25 Perimeter = 4y + 5x + x + 5x = 4y + 11x © Boardworks Ltd 2009 Algebraic pyramids 23 of 24 25 © Boardworks Ltd 2009 Algebraic magic square 24 of 24 25 © Boardworks Ltd 2009