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Normal Curve Calculations The Empirical Rule that we have applied to bell-shaped distributions is based on a special mathematical distribution called the normal distribution. The normal distribution is symmetric about the mean µ . The standard deviation σ describes the spread from the mean. See figure 1 below. In fact the Empirical Rule says that about 68% of the data falls in the interval µ ± σ and that about 95% falls in the interval µ ± 2σ. µ−σ µ Figure 1 µ+σ 288 401 514 627 740 Figure 2 In the year 2000 the SAT math scores had a mean of 514 and a standard deviation of 113. The distribution was approximated well by a normal distribution. The sketch is shown in figure 2 above. By the Empirical Rule we can say that 68% of the SAT math scores were between 401 and 627, and that 95% of the scores were between 288 and 740. What if we wanted to know the percentage of the scores that were between 500 and 700? Or what was the percentage above 700 ? These are the type of questions that we will learn to answer now. The key to answering these questions is to ask how many standard deviations are these scores from the mean. For example how many standard deviations is 700 from the mean of 514 ? (try to answer this before reading further). First 700 is 700 – 514 = 186 points above the mean. How many standard deviations are in 186 points? Answer: 186/113 = 1.65 standard deviations. This is called the standardized score or z-score. The calculation can be summarized by the formula z= € x −µ value − mean or z − score = σ stan dard deviation Let’s return to the problem of determining the percentage of the scores that fall between 500 and 700. First calculate the z-scores for each of the scores 500 and 700. The calculations are shown in the sketch in Figure 3. After finding the z-scores we need to determine the percentage of SAT scores between 500 and 700. To do this we use a command in the TI-83 calculator. The command is normalcdf and is found under the DISTR menu which is accessed by 2nd VARS. Figure 4 shows the shaded area corresponding to the desired percentage. The conclusion is that 49.83% of the SAT math scores were between 500 and 700. normalcdf(-.12,1.65) = .4983 288 401 514 627 740 500 − 514 700 − 514 z= z= 113 113 z ≈ −.12 z ≈ 1.65 Figure 3 288 401 514 627 740 Figure 4 €Exercise 1: What € percentage of the scores were between 600 and 700 ? (Answer 17.3%) Example 2. What percentage of the scores are higher than 700 ? Step 1. Make sketch Step 2. Calculate z-score Step 3. Use normalcdf 288 401 514 627 740 700 − 514 z= 113 z ≈ 1.65 normalcdf(1.65,100) = .0495 Therefore we conclude that about 4.95% of the SAT math scores were higher than 700. Note: Since there is no right boundary on the shaded region we use 100 for the z-score on the right. Any large number will give about the same answer. € Exercise 2: What percentage of the scores were below 600? (Answer: 77.67% ) The diagram below summarizes the procedure for finding the percentage of a normal distribution between two x values. x values z-scores area In the next example we will need to reverse this process. Example 3 Suppose we want to know the SAT math score that has 25% of the scores below it. First make the sketch. The SAT score we are looking for is indicated by the x. We will first find the z-score that corresponds to the score x. To do this we use the calculator command InvNorm. 25% 288 401 514 627 740 x The InvNorm command needs to be told the area to the left of the score we want. In this example we use InvNorm(0.25) = -0.67. This the z-score that corresponds to the SAT score, x, that has 25% of the scores below it. To find x we just solve as shown below. x − 514 113 −.67(113) = x − 514 −.67(113) + 514 = x x ≈ 438 Therefore a score of 438 on the SAT math test was higher than 25% of all the SAT math scores. Note that this means that 438 is the lower quartile of the SAT math scores in the year 2000. −.67 = € Problems 1. Based on the data from an article in Consumer Reports, the length of time CD players will work before replacement is needed is normally distributed with a mean of 7.1 years and a standard deviation of 1.4 years. A) Draw a sketch of the distribution labeling the mean and two standard deviations in each direction. B) According to the Empirical Rule, 95% of the CD players will last between _______ years and ________ years before they need to be replaced. C) What percent of CD players will last between 5 and 8 years before needing replacement? D) Joe is deciding if he should purchase the 5 year replacement warranty, which will replace his CD player if it should break within the first five years of ownership. What percent of CD players will last more than 5 years before needing replacement? Should he purchase the warranty? Defend your answer. 2. The gas mileage for a certain model car varies from car to car. Suppose that the distribution of mileages is summarized by a normal distribution with a mean of 26 and standard deviation of 3 miles per gallon. (A) Sketch the distribution labeling the mean and two standard deviations in each direction. (B) What percentage of the cars have a mileage more than 30 miles per gallon ? (C) What percentage of cars have mileages between 22 and 30 miles per gallon ? (D) Almost all of the cars will have mileages between 3. and . Explain. The pulse rate of the adult male population between age 18 and 25 is a normally distributed variable with mean of 72 and standard deviation of 12. Suppose that anyone with a pulse rate of 100 or more is not allowed to be a pilot. A) What percentage of adult males in this age range are not allowed to be pilots because of a high pulse rate ? B) What pulse rate would an adult male have in order to have a rate in the slowest 25% of adult males? 4. The GRE is a test taken by college students who intend to go to graduate school. For all college seniors and graduates who took the exam in 1989-1992 the scores on the GRE were normally distributed with a mean of 497 and a standard deviation of 115. Assume this distribution still applies. If a graduate school wants to admit only those whose score is in the top 20% of all scores, what would they use as the cutoff score to get in the school ? Include a sketch and show the cutoff score on the sketch. Write your answer in a complete sentence. 5. The weights of boxes of Raisin Nut Bran cereal produced at a factory vary from box to box. Suppose that these weights are normally distributed with a mean of 595 grams and a standard deviation of 12 grams. A) Sketch the distribution of weights and label the mean and two standard deviations in each direction. B) What is the weight of a box of cereal that is in the lightest 10%? C) What percentage of the boxes will weigh between 590 and 610 grams ? Include a sketch and show your work. Write your answer in a complete sentence. D) The quality control department will only ship a box if it weighs at least 570 grams. What percentage of the boxes will be shipped? Include a sketch and show your work. Write your answer in a complete sentence. 6. Referring to problem number 5, suppose the factory can control the mean weight of the boxes of cereal by adjusting the machine that fills the boxes. If the quality control department will ship a box only if it weighs at least 570 grams, and they want to discard only 1% of the boxes, what is the mean weight they should use to adjust the machine? Assume the standard deviation stays at 12 grams. 7. Suppose the scores on the SAT math test have a mean of 570 and a standard deviation of 50. The scores on the ACT test have a mean of 17 with a standard deviation of 3. Assume both are normally distributed. A) What is the z-score for a score of 700 on the SAT math test? What is the z-score for a score of 26 on the ACT test? B) Which is better : 700 on the SAT or a score of 26 on the ACT test. Explain. 8. Suppose that I.Q. scores on a commonly used test are normally distributed with a mean of 100 and a standard deviation of 15 and ths scores are normally distributed. Find the I.Q. scores that correspond to the lower quartile, the median, and the upper quartile. Answers 1 B) 4.3 to 9.9 C) 67.3% D) 93.3% 2. B) 9.1% C) 82% D) 17 and 35 mpg 3. 0.98% B) 64 beats per minute 4.) 594 6) 598 7A) SAT: z = 2.6 ACT: z = 3 5B) 579.6 C) 55.6% D) 98% 8) 90,100,110