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Transcript
Section 3
5b, 5C
Main Ideas
Atomic radii are related to
electron configuration.
Removing electrons from atoms
to form ions requires energy.
Adding electrons to atoms to
form ions also involves energy.
When atoms become ions, their
radii change.
Only the outer electrons are
involved in forming compounds.
Atoms have different abilities to
capture electrons.
The properties of d-block
metals do not vary much.
5B use the Periodic Table to
identify and explain the properties of
chemical families, including alkali metals,
alkaline earth metals, halogens, noble
gases, and transition metals; 5C use the
Periodic Table to identify and explain
periodic trends, including atomic and
ionic radii, electronegativity, and
ionization energy
Electron
Configuration and
Periodic Properties
Key Terms
atomic radius
ion
ionization
ionization energy
electron affinity
cation
anion
valence electron
electronegativity
So far, you have learned that the elements are arranged in the periodic table
according to their atomic number and that there is a rough correlation between
the arrangement of the elements and their electron configurations. In this section,
the relationship between the periodic law and electron configurations will be further
­explored.
Main Idea 5C
Atomic radii are related to electron configuration.
Ideally, the size of an atom is defined by the edge of its largest orbital.
However, this boundary is fuzzy and varies under different conditions.
Therefore, the conditions under which the atom exists must be specified
to estimate its size. One way to express an atom’s radius is to measure the
distance between the nuclei of two identical atoms that are chemically
bonded together and then divide this distance by two. Atomic radius may
be defined as one­-h
­ alf the distance between the nuclei of identical atoms that
are bonded together. This can be seen in Figure 3.1 on the next page.
Period Trends
Figure 3.2 gives the atomic radii of the elements, and Figure 3.3 (on the next
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Period Trends (Interaction)
spread) presents this information graphically. Note that there is a gradual
decrease in atomic radii across the second period from lithium, Li, to
neon, Ne. The trend to smaller atoms across a period is caused by the
increasing positive charge of the nucleus. As electrons add to s and p
sublevels in the same main energy level, they are gradually pulled closer
to the more highly charged nucleus. This increased pull results in a
decrease in atomic radii. The attraction of the nucleus is somewhat offset
by repulsion among the increased number of electrons in the same outer
energy level. As a result, the difference in radii between neighboring
atoms in each period grows smaller, as shown in Figure 3.2.
Group Trends
Examine the atomic radii of the Group 1 elements in Figure 3.2. Notice
that the radii of the elements increase as you read down the group.
148
Chapter 5
Figure 3.1
Atomic Radii One method of
Chlorine
nucleus
determining atomic radius is to measure
the distance between the nuclei of two
identical atoms that are bonded together in
an element or compound and then divide
this ­distance by two. The atomic radius
of a chlorine atom, for example, is about
100 picometers ­(pm).
Atomic
radius
99 pm
198 pm
Chlorine
nucleus
Distance
between nuclei
CHECK FOR UNDERSTANDING
As electrons occupy sublevels in successively higher main­energy levels
farther from the nucleus, the sizes of the atoms increase. In general, the
atomic radii of the main­-g­ roup elements increase down a group.
Explain Why is it necessary for the
radii of atoms to be expressed as
the distance between the nuclei
of two identical atoms bonded
together? (Refer to Figure 3.1.)
Now examine the radii of the Group 13 elements. Although gallium,
Ga, follows aluminum, Al, it has a slightly smaller atomic radius than does
aluminum. This is because gallium, unlike aluminum, is preceded in its
period by the 10 d-block elements. The expected increase in gal­lium’s
radius caused by the filling of the fourth main­-­energy level is outweighed
by a shrinking of the electron cloud caused by a nuclear charge that is
considerably higher than that of a­ luminum.
Figure 3.2
Decreasing Radii Atomic radii decrease from left to right across a
period and increase down a ­group. Values are given in picometers (pm).
1
2
H
37
Group 1 Group 2
Li
3 Be
4
152
3
Period
31
Group 13 Group 14 Group 15 Group 16 Group 17
B
5 C
6 N
7 O
8 F
9 Ne 10
Relative
atomic size
77
85
Cs
Fr
13 Si
75
14 P
73
15 S
72
16 Cl
2
71
17 Ar
18
118
110
103
100
98
Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Group 11 Group 12 143
20 Sc 21 Ti 22 V
23 Cr 24 Mn 25 Fe 26 Co 27 Ni 28 Cu 29 Zn 30 Ga 31 Ge 32 As 33 Se 34 Br 35 Kr 36
197
180
134
128
127
40 Nb 41 Mo 42 Tc
160
57 Hf
183
88 Ac
220
147
39 Zr
56 La
222
87 Ra
162
38 Y
215
55 Ba
270
Al
77
1
3
160
Rb 37 Sr
265
7
Group 18
He
2
Atomic radius
112
19 Ca
248
6
6
146
72 Ta
159
139
73 W
146
125
124
43 Ru 44 Rh 45 Pd
136
74 Re
139
126
134
75 Os
137
134
76 Ir
135
136
—
—
—
—
—
135
144
149
49 Sn
167
78 Au 79 Hg 80 Tl
122
120
50 Sb
140
81 Pb
119
51 Te
140
82 Bi
142
83 Po
—
—
—
133
5
131
85 Rn 86
140
4
112
53 Xe 54
84 At
144
151
170
175
150
168
110 Rg 111 Cn 112
113 Fl 114
115 Lv 116
—
—
114
52 I
139
89 Rf 104 Db 105 Sg 106 Bh 107 Hs 108 Mt 109 Ds
188
134
46 Ag 47 Cd 48 In
137
77 Pt
128
Period
K
227
5
C
Atomic
number
Na 11 Mg 12
186
4
Atomic
symbol
1
6
141
117
118
—
7
Lanthanide series
Ce
58 Pr
182
Th
182
90 Pa
179
59 Nd 60 Pm 61 Sm 62 Eu
91 U
163
181
183
180
92 Np 93 Pu
156
155
63 Gd 64 Tb
208
180
65 Dy 66 Ho 67 Er
177
94 Am 95 Cm 96 Bk
159
173
174
178
97 Cf
—
176
98 Es
186
186
68 Tm 69 Yb 70 Lu
176
176
—
71
174
99 Fm 100 Md101 No 102 Lr 103
—
—
—
—
Actinide series
The Periodic Law
149
Figure 3.3
Periodic Trends The plot of atomic radius versus
atomic number shows period and group ­trends.
Atomic Radius vs. Atomic Number
300
Period
2
Period
3
Period
4
Period
5
Period
6
Cs
Fr
Period
7
Rb
250
K
Atomic radius (pm)
200
Es
Na
Li
150
Rn
Xe
Kr
100
Ar
Ne
50
H
He
0
0
10
20
30
40
50
60
70
80
90
100
Atomic number
5C
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Atomic Radius
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Sample Problem E Of the elements magnesium, Mg, chlorine, Cl,
sodium, Na, and phosphorus, P, which has the largest atomic radius?
Explain your answer in terms of trends in the periodic t­ able.
Solve
All of the elements are in the third period. Of the four, sodium has the lowest
atomic number and is the first element in the period. This means sodium has
the smallest nucleus and, therefore, the least attraction on the electrons.
Therefore, sodium has the largest atomic radius, because atomic radii decrease
across a ­period.
Answers in Appendix E
1. Which of the following elements has the largest atomic radius: Li, O, C, or F? Which has the
smallest atomic radius?
2. Of the elements calcium, Ca, beryllium, Be, barium, Ba, and strontium, Sr, which has the
largest atomic radius? Explain your answer in terms of trends in the periodic t­ able.
3. Of the elements aluminum, Al, magnesium, Mg, silicon, Si, and sodium, Na, which has the
smallest atomic radius? Explain your answer in terms of trends in the periodic table.
150
Chapter 5
5B, 5C
Main Idea Removing electrons from atoms to form ions
requires energy.
An electron can be removed from an atom if enough energy is supplied.
Using A as a symbol for an atom of any element, the process can be
expressed as ­follows.
A + energy → A+ + eThe A+ represents an ion of element A with a single positive charge,
referred to as a 1+ ion. An ion is an atom or group of bonded atoms that has
a positive or negative charge. Sodium, for example, forms an Na+ ion. Any
process that results in the formation of an ion is referred to as ionization.
To compare the ease with which atoms of different elements give up
electrons, chemists compare ionization energies. The energy required to
remove one electron from a neutral atom of an element is the ionization energy,
IE (or first ionization energy, IE1). To avoid the influence of nearby atoms,
measurements of ionization energies are made on isolated atoms in the
gas phase. Figure 3.4 gives the first ionization energies for the elements
in kilojoules per mole (kJ/mol). Figure 3.5, on the next page, presents this
information ­graphically.
Figure 3.4
Ionization Energy In general, first ionization energies increase
across a period and decrease down a ­group. Values are given in kJ/mol.
1
2
Li
520
11
5
6
7
Be
12
Mg
19
20
738
2
Group 13 Group 14 Group 15 Group 16 Group 17
Symbol
1086
900
Na
496
C
4
Group 18
5
B
First ionization
energy
21
22
24
25
26
27
28
29
30
2372
10
1402
1314
1681
F
Ne
13
14
15
16
17
18
578
787
1012
1000
1251
1521
31
32
33
34
35
36
P
O
9
1086
Si
N
8
S
Cl
Sc
633
659
651
V
Cr
Mn
Fe
Co
Ni
Cu
Zn
Ga
Ge
As
Se
941
1140
1351
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
653
717
762
760
737
746
906
579
762
947
Sr
550
600
Y
Zr
Nb
Mo
Tc
Ru
Rh
Pd
Ag
Cd
In
Sn
Sb
Te
869
1008
I
Xe
55
56
57
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
640
652
684
702
710
720
804
731
868
558
709
834
1170
Cs
Ba
La
Hf
Ta
W
Re
Os
839
878
Ir
Pt
Au
Hg
1007
589
Tl
Pb
Bi
Po
At
Rn
87
88
89
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
376
Fr
—
503
Ra
509
538
Ac
490
659
Rf
—
761
Db
—
770
Sg
—
760
Bh
—
Hs
—
Mt
—
868
Ds
—
890
Rg
—
Cn
—
716
Fl
703
—
812
Lv
—
3
4
Kr
Rb
403
2
Ar
Ca
590
Br
2081
K
419
Ti
23
C
7
He
801
Al
Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Group 11 Group 12
6
1
1038
5
Period
Period
4
6
1312
Group 1 Group 2
3
3
Atomic
number
1
H
6
7
—
Lanthanide series
58
59
60
61
62
63
64
65
66
67
68
69
70
71
Ce
Pr
Nd
Pm
Sm
Eu
Gd
Tb
Dy
Ho
Er
Tm
Yb
Lu
90
91
92
93
94
95
96
97
98
99
100
101
102
103
578
581
642
—
534
Th
527
Pa
587
570
Actinide series
533
U
598
536
Np
600
545
Pu
585
547
592
Am Cm
566
Bk
601
573
Cf
608
581
Es
619
589
Fm
627
597
Md
635
603
No
523
Lr
The Periodic Law
151
Figure 3.5
Ionization Energy Plot of first ionization energy, IE 1, versus atomic number. As
atomic number increases, both the period and the group trends become less pronounced.
First Ionization Energy vs. Atomic Number
3000
Period
2
2500
Period
3
Period
4
Period
5
Period
6
Period
7
He
First ionization energy (kJ/mol)
Ne
2000
Ar
1500
Kr
H
Xe
Rn
1000
No
Li
500
0
Ra
0
Na
10
K
20
Rb
30
40
Cs
50
60
Atomic number
70
80
90
100
Period Trends
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Period Trends
1st Pass
6/18/04
Nanda Patel
In Figures 3.4 and 3.5, examine the ionization energies for the first and last
elements in each period. You can see that the Group 1 metals have the
lowest first ionization energies in their respective periods. Therefore, they
lose electrons most easily. This ease of electron loss is a major reason for
the high reactivity of the Group 1 (alkali) metals. The Group 18 elements,
the noble gases, have the highest ionization energies. They do not lose
electrons easily. The low reactivity of the noble gases is partly based on
this difficulty of electron ­removal.
In general, ionization energies of the main­-­group elements increase
across each period. This increase is caused by increasing nuclear charge.
A higher charge more strongly attracts electrons in the same energy level.
Increasing nuclear charge is responsible for both increasing ionization
energy and decreasing radii across the ­periods. Note that, in general,
nonmetals have higher ionization energies than metals do. In each
pe­riod, the element of Group 1 has the lowest ionization energy, and the
element of Group 18 has the highest ionization ­energy.
152
Chapter 5
Group Trends
Among the main­-g­ roup elements, ionization energies generally decrease
down the groups. Electrons removed from atoms of each succeeding
element in a group are in higher energy levels, farther from the nucleus.
Therefore, they are removed more easily. Also, as atomic number
increases going down a group, more electrons lie between the nucleus
and the electrons in the highest occupied energy levels. This partially
shields the outer electrons from the effect of the nuclear charge.
Together, these influences overcome the attraction of the electrons due to
the increasing nuclear c­ harge.
Removing Electrons from Positive Ions
With sufficient energy, electrons can be removed from positive ions as
well as from neutral atoms. The energies for removal of additional
electrons from an atom are referred to as the second ionization energy
(IE2), third ionization energy (IE3), and so ­on. Figure 3.6 shows the first five
ionization energies for the elements of the first, second, and third periods. You can see that the second ionization energy is always higher than
the first, the third is always higher than the second, and so on.
Figure 3.6
Ionization Energies (in kj/mol) for Elements of Periods 1–3
Period 1
H
IE1
IE2
IE3
1312
He
Period 2
Li
Be
B
C
N
O
F
Ne
2372
520
900
801
1086
1402
1314
1681
2081
5250
7298
1757
2427
2353
2856
3388
3374
3952
11 815
14 849
3660
4621
4578
5300
6050
6122
21 007
25 026
6223
7475
7469
8408
9370
32 827
37 830
9445
10 990
11 023
12 178
P
S
Cl
Ar
IE4
IE5
Period 3
Na
Mg
Al
Si
IE1
496
738
578
787
1012
1000
1251
1521
IE2
4562
1451
1817
1577
1903
2251
2297
2666
IE3
6912
7733
2745
3232
2912
3361
3822
3931
IE4
9544
10 540
11 578
4356
4957
4564
5158
5771
IE5
13 353
13 628
14 831
16 091
6274
7013
6540
7238
The Periodic Law
153
CHECK FOR UNDERSTANDING
Explain Explain in your own
words why ionization energies
increase as successive electrons are
removed from an ion.
This rise in ionization energies is understandable when you consider
what is occurring. The first electron is removed from a neutral atom.
However, the second electron is removed from a positive ion, so it takes
more energy to remove it. Therefore, it is harder to remove each additional
electron because it is being removed from an even more positive ion.
The electrons in the outermost energy level are called valence
electrons. Those electrons in the lower levels are called core electrons.
Once all of the valence electrons have been removed, it requires a lot
more energy to remove successive core electrons. Look at the pattern in
Figure 3.6 again. The green boxes are the IE values to remove the first
core electron, after all the valence electrons have been removed. Using
Na (sodium) with the electron configuration 1s22p23s1 as an example,
the 1s, 2s, and 2p electrons are the core electrons, and the 3s electron is
the valence electron. Notice that it takes a lot more energy to remove
the 2p electron from the core than it does the 3s valence electron. Also
consider Mg (magnesium). Magnesium’s third ionization energy is
much greater than its first or second ionization energies. This is because
Mg has two valance electrons, and so the third ionization energy is the
energy required to remove a core electron. This pattern continues for
the remainder of the elements in the third period.
Periodic Trends in Ionization Energy
Sample Problem F Consider two main­-­group elements, A and B. Element A has a first
ionization energy of 419 kJ/mol. Element B has a first ionization energy of 1000 kJ/mol.
Decide if each element is more likely to be in the s-block or p-block. Which element is more
likely to form a positive i­ on?
SOLVE
Element A has a lower ionization energy, which means that atoms of A lose
electrons easily. Therefore, element A is most likely to be an s-block metal,
because ionization energies increase across the periods.
Element B has a higher ionization energy, which means that atoms of B have
difficulty losing electrons. Element B would most likely lie at the end of a
period in the p-block.
Element A is more likely to form a positive ion, because it has a much lower
ionization energy than element ­B does.
Answers in Appendix E
1. Consider four hypothetical main­-­group e­ lements, Q, R, T, and X, that have the outer
electron ­configurations indicated below. Then, answer the questions that follow.
Q: 3s23p5 R: 3s1 T: 4d105s25p5 X: 4d105s25p1
a. Identify the block location of each hypothetical main­-g­ roup ­element.
b. Which of these elements are in the same period? Which are in the same g­ roup?
c. Which element would you expect to have the highest first ionization energy?
Which would have the lowest first ionization e­ nergy?
d. Which element would you expect to have the highest second ionization e­ nergy?
e. Which of the elements is most likely to form a 1+ ­ion?
154
Chapter 5
5B, 5C
Main Idea Adding electrons to atoms to form ions also involves
energy.
Neutral atoms can also acquire electrons. The energy change that occurs
when an electron is acquired by a neutral atom is called the atom’s
electron affinity. Most atoms release energy when they acquire an e
­ lectron.
A + e- → A- + ­energy
On the other hand, some atoms must be “forced” to gain an electron
by the addition of ­energy.
A + e- + energy → AThe quantity of energy absorbed would be represented by a positive
number, but ions produced in this way are very unstable, and hence
the electron affinity for them is very difficult to determine. An ion
produced in this way will be unstable and will lose the added electron
spontaneously.
Figure 3.7 shows the electron affinity in kilojoules per mole for
the elements. Positive electron affinities, because they are so difficult
to determine with any accuracy, are denoted in Figure 3.7 by “(0).”
Figure 3.8, on the next page, presents these data g
­ raphically.
Figure 3.7
Period Trends
Periodic Table of Electron
Affinities (kJ/mol) The values
Among the elements of each period, the halogens (Group 17) gain
electrons most readily. This is shown in Figure 3.7 by the large negative
values of halogens’ electron affinities and is a major reason for the high
reactivity levels of Group 17 elements. In general, as electrons add to the
same p sublevel of atoms with increasing nuclear charge, electron
affinities become more negative across each period within the p-block.
1
2
3
5
6
7
6
–75.4
Group 1 Group 2
3
Li
Be
11
12
–61.8
Mg
19
20
(0)
21
Sc
22
Ca
(0)
–18.8
–7.9
37
38
39
40
Rb
Sr
(0)
–30.7
55
56
57
–48.6
Y
Ti
Zr
–52.5
Cr
–66.6
Mn
Co
(0)
–16.3
–66.1
41
42
43
44
45
–105
–113.7
74
75
76
77
(0)
—
Fe
27
73
104
(0)
26
–89.3
89
–47.0
25
72
88
Ac
V
24
–42.6
87
–50
23
Rf
—
Ta
–74.6
–55
–32.2
W
–81.5
Re
–15
–110
–156.5
105
106
107
108
109
Db
—
Sg
—
Bh
—
Os
Rh
Hs
—
Ir
Mt
—
28
Ni
29
30
6
7
–27.7
C
–126.3
N
(0)
13
14
15
–44.1
–138.5
–74.6
31
32
33
Al
Ru
Hf
Ra
Electron
affinity
Tc
La
Fr
B
Mo
Ba
(0)
5
Nb
Cs
–47.2
Symbol
Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Group 11 Group 12
K
–50.1
2
Group 13 Group 14 Group 15 Group 16 Group 17
–126.3
(0)
Na
–54.8
C
4
Group 18
Si
P
–115.6
Cu
–122.8
Zn
Ga
Ge
As
–81
46
47
48
49
50
51
Pd
(0)
–30
–135
–55.7
Ag
–130.2
Cd
In
–30
–120
–107
78
79
80
81
82
83
Pt
(0)
–212.8
Au
–230.9
Hg
110
111
Ds
—
Rg
—
Sn
Sb
(0)
Tl
–20
Pb
–36
–94.6
112
113
114
115
Cn
—
Fl
—
Bi
8
O
9
He
(0)
10
–146.1
F
–339.9
Ne
16
17
18
S
(0)
–207.7
Cl
–361.7
Ar
34
35
36
Se
(0)
–202.1
Br
–336.5
Kr
52
53
54
Te
(0)
–197.1
I
–305.9
Xe
84
85
86
Po
(0)
–190
At
–280
Rn
116
117
118
Lv
1
(0)
2
3
4
5
Period
Period
4
Atomic
number
1
H
listed in parentheses in this periodic table
of electron affinities are approximate.
Electron affinity is estimated to be
-50 kJ/mol for each of the lantha­nides
and 0 kJ/mol for each of the ­actinides.
6
7
—
The Periodic Law
155
Electron Affinity vs. Atomic Number
0
Electron affinity (kJ/mol)
–100
Ne
He
H
Li
Ar
Na
Kr
Xe
Ra
Fr
Cs
Rb
K
Rn
–200
–300
–400
Period
2
0
Period
3
10
20
Period
4
30
Period
5
40
50
60
Period
6
70
80
Period
7
90
100
Atomic number
Figure 3.8
Electron Affinity and Atomic
Numbers The plot of electron affinity
versus atomic number shows that most
atoms release energy when they acquire
an electron, as indicated by negative
values.
An exception to this trend occurs between Groups 14 and 15. Compare
the electron affinities of carbon ([He]2s22p2) and nitrogen ([He]2s22p3).
Adding an electron to a carbon atom gives a half­-­filled p sublevel. This
occurs more easily than forcing an electron to pair with another electron
in an orbital of the already half­-­filled p sublevel of a nitrogen ­atom.
Group Trends
Trends for electron affinities within groups are not as regular as trends for
ionization energies. As a general rule, electrons are added with greater
difficulty down a group. This pattern is a result of two competing factors.
The first is an increase in nuclear charge down a group, which i­ ncreases
electron affinities. The second is an increase in atomic radius down a
group, which decreases electron affinities. In general, the size effect
predominates. But there are exceptions, especially among the heavy
transition metals, which tend to be the same size or even decrease in
radius down a group.
Adding Electrons to Negative Ions
For an isolated ion in the gas phase, it is more difficult to add a second
electron to an already negatively charged ion. Therefore, second electron
affinities are all positive. Certain p-block nonmetals tend to form negative
ions that have noble­g­ as configurations. The halogens do so by adding
one electron. For example, chlorine has the configuration [Ne]3s23p5.
156
Chapter 5
An atom of chlorine achieves the configuration of the noble gas argon by
adding an electron to form the ion Cl- ([Ne]3s23p6). Adding another
electron is so difficult that Cl2- never occurs. Atoms of Group 16 elements
are pres­ent in many compounds as 2- ions. For example, oxygen
([He]2s22p4) achieves the configuration of the noble gas neon by adding
two electrons to form the ion O2-([He]2s22p6).
5C
Main Idea When atoms become ions, their radii change.
Figure 3.9 shows the radii of some of the most common ions of the
elements. Positive and negative ions have specific names.
A positive ion is known as a cation. The formation of a cation by the loss
of one or more electrons always leads to a decrease in atomic radius,
because the removal of the highest-energy-level electrons results in a
smaller electron cloud. Also, the remaining electrons are drawn closer to
the nucleus by its unbalanced positive charge.
A negative ion is known as an anion. The formation of an anion by the
addition of one or more electrons always leads to an increase in atomic
radius. This is because the total positive charge of the nucleus remains
unchanged when an electron is added to an atom or an ion. So the
electrons are not drawn to the nucleus as strongly as they were before
the addition of the extra electron. The electron cloud also spreads out
because of greater repulsion between the increased number of ­electrons.
Figure 3.9
Period Trends
Periodic Table of Ionic Radii
(pm) The ionic radii of the ions most
Within each period of the periodic table, the metals at the left tend to
form cations, and the nonmetals at the right tend to form anions. Cationic
radii decrease across a period, because the electron cloud shrinks due to
the increasing nuclear charge acting on the electrons in the same main
energy level.
Atomic
number
1
H–
154
Relative
atomic size
Group 1 Group 2
2
4
Li+
76 Be2+
45
C
Ionic symbol
2
4–
260
Relative
ionic size
Group 13 Group 14 Group 15 Group 16 Group 17 He
Ionic radius (pm)
B
5
11
12
13
Na+
Mg2+
Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Group 11 Group 12
Al3+
21
31
102
19
72
20
22
23
24
25
26
27
28
29
30
6
— C4–
7
260 N3–
8
146 O2–
9
10
140 F–
133 Ne
2
14
15
16
17
18
54 Si
P3–
S2–
Cl–
181 Ar
—
32
33
62 Ge
— As
50
51
212
184
34
1
—
—
3
35
36
— Se2– 198 Br–
196 Kr
—
4
4
K+
138 Ca2+ 100 Sc3+
37
38
39
75 Ti2+
86 V2+
40
41
90 Zr
— Nb
79 Cr2+
42
80 Mn2+ 83 Fe2+
43
44
— Tc
— Ru
78 Co2+
45
65 Ni2+
46
69 Cu2+
47
73 Zn2+
74 Ga3+
48
49
52
53
Period
Period
3
3
Group 18
6
1
common in chemical compounds are
shown. Cations are smaller and anions
are larger than the atoms from which they
are ­formed.
—
54
5
5
Rb+ 152 Sr2+ 118 Y3+
55
56
57
— Mo
72
73
74
75
76
167 Ba2+ 136 La3+ 116 Hf
— Ta
— W
— Re
— Os
— Rh3+
77
67 Pd2+
78
86 Ag+ 115 Cd2+
79
95 In3+
80
81
80 Sn2+ 118 Sb3+
82
83
76 Te2– 221 I–
220 Xe
84
85
86
89 Pb2+ 119 Bi3+ 103 Po
— At
— Rn
—
6
6
Cs+
87
88
89
Fr+
Ra2+
Ac3+
104
105
106
107
108
— Ir
109
— Pt2+
110
80 Au+ 137 Hg2+ 119 Tl3+
111
112
113
114
115
117
116
—
118
7
7
180
148
111 Rf
— Db
— Sg
— Bh
— Hs
— Mt
— Ds
— Rg
— Cn
—
Fl
—
Lv
—
The Periodic Law
157
Starting with Group 15, in which atoms assume stable noble­-­gas
configurations by gaining three electrons, anions are more common than
cations. Anionic radii decrease across each period for the elements in
Groups 15–18. The reasons for this trend are the same as the reasons that
cationic radii decrease from left to right across a ­period.
Group Trends
The outer electrons in both cations and anions are in higher energy levels
as one reads down a group. Thus, just as there is a gradual increase of
atomic radii down a group, there is also a gradual increase of ionic ­radii.
Main Idea
Only the outer electrons are involved in
forming compounds.
Chemical compounds form because electrons are lost, gained, or shared
between atoms. The electrons that interact in this manner are those in
the highest energy levels. These are the electrons most subject to the
influence of nearby atoms or ions. The electrons available to be lost,
gained, or shared in the formation of chemical compounds are referred to as
valence electrons. Valence electrons are often located in incompletely
filled main­-­energy levels. For example, the electron lost from the 3s
sublevel of Na to form Na+ is a valence ­electron.
For main­-­group elements, the valence electrons are the electrons in
the outermost s and p sublevels. The inner electrons are in filled energy
levels and are held too tightly by the nu­cleus to be involved in compound
formation. The Group 1 and Group 2 elements have one and two valence
electrons, respectively, as shown in Figure 3.10. The elements of Groups
13–18 have a number of valence electrons equal to the group number
minus 10. In some cases, both the s and p sublevel valence electrons of
the p-block elements are involved in compound formation (Figure 3.10).
In other cases, only the electrons from the p sublevel are ­involved.
Figure 3.10
Valence Electrons in Main-Group Elements
158
Chapter 5
Group ­number
Group configuration
Number of valence
electrons
1
ns1
1
2
ns 2
2
13
ns 2p1
3
14
ns 2p 2
4
15
ns 2p 3
5
16
ns 2p 4
6
17
ns 2p 5
7
18
ns 2p 6
8
5C
Main Idea Atoms have different abilities to capture electrons.
Valence electrons hold atoms together in chemical compounds. In many
compounds, the negative charge of the valence electrons is concentrated
closer to one atom than to another. This uneven concentration of charge
has a significant effect on the chemical properties of a compound. It is
therefore useful to have a measure of how strongly one atom attracts the
electrons of another atom within a c­ ompound.
Linus Pauling, one of America’s most famous chemists, devised a
scale of numerical values reflecting the tendency of an atom to attract
electrons. Electronegativity is a measure of the ability of an atom in a chemical
compound to attract electrons from another atom in the compound. The most
electronegative element, fluorine, is arbitrarily assigned an electronegativity of four. Other values are then calculated in relation to this v­ alue.
Period Trends
As shown in Figure 3.11, electronegativities tend to increase across each
period, although there are exceptions. The alkali and alkaline­-­earth metals
are the least electronegative elements. In compounds, their atoms have a
low attraction for electrons. Nitrogen, oxygen, and the halogens are the
most electronegative elements. Their atoms attract electrons strongly.
Figure 3.11
Periodic Table of Electronegativities Shown are the electronegativities of the elements
according to the Pauling scale. The most-electronegative elements are located in the upper right of
the p-block. The least-electronegative elements are located in the lower left of the s-block.
1
Atomic
number
1
H
2
3
5
6
7
Group 2
3
4
Li
Be
11
12
1.0
C
Group 13 Group 14
Symbol
2.5
1.5
2
5
B
Electronegativity
Na
Mg
1.2
Group 3
Group 4
Group 5
Group 6
Group 7
Group 8
Group 9
19
20
21
22
23
24
25
26
27
0.9
K
Ca
Sc
Ti
37
38
39
0.8
1.0
1.3
Group 10 Group 11 Group 12
28
29
30
6
C
Group 15 Group 16 Group 17
7
N
8
O
9
Ne
18
2.5
3.0
3.5
4.0
13
14
15
16
17
Al
Si
1.8
31
32
1.5
P
—
10
F
2.0
—
2.1
S
2.5
Cl
Ar
33
34
35
36
3.0
—
1.5
V
1.6
Cr
Mn
Fe
Co
Ni
Cu
Zn
Ga
Ge
As
Se
Br
Kr
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
1.6
1.5
1.8
1.8
1.8
1.9
1.6
1.6
1.8
2.0
2.4
2.8
3.0
Rb
Sr
1.0
1.2
Y
Zr
Nb
Mo
Tc
Ru
Rh
Pd
Ag
Cd
In
Sn
Sb
Te
2.1
2.5
I
Xe
55
56
57
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
0.8
1.4
1.6
1.8
1.9
2.2
2.2
2.2
1.9
1.7
1.7
1.8
1.9
2.6
Cs
Ba
La
Hf
Ta
W
Re
Os
2.2
2.2
Ir
Pt
Au
Hg
Tl
Pb
Bi
Po
At
Rn
87
88
89
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
0.7
Fr
0.7
0.9
Ra
0.9
1.1
Ac
1.1
1.3
Rf
—
1.5
Db
—
1.7
Sg
—
1.9
Bh
—
Hs
—
Mt
—
2.2
Ds
—
2.4
Rg
—
1.9
Cn
1.8
—
1.8
Fl
1.9
—
2.0
Lv
2.2
1
He
2.4
2
3
4
Period
Period
4
6
2.1
Group 1
Group 18
5
6
7
—
Lanthanide series
58
59
60
61
62
63
64
65
Ce
Pr
Nd
Pm
Sm
Eu
Gd
Tb
90
91
92
93
94
95
96
97
1.3
1.5
Actinide series
1.4
1.1
Th
1.1
Pa
1.1
U
1.1
Np
1.4
1.2
Pu
1.3
1.1
Am
1.3
1.2
Cm
1.3
1.1
Bk
1.3
66
Dy
1.2
98
Cf
1.3
67
68
69
70
71
Ho
Er
Tm
Yb
Lu
99
100
101
102
103
1.3
—
1.2
Es
1.3
1.2
Fm
1.3
1.3
Md
1.3
1.1
No
1.3
Lr
The Periodic Law
159
CHECK FOR UNDERSTANDING
Electro­negativities tend to either decrease down a group or remain about
the same. The noble gases are unusual in that some of them do not form
compounds and therefore cannot be assigned electronegativities. When
a noble gas does form a compound, its electronegativity is rather high,
similar to the values for the halogens. The combination of the period and
group trends in electronegativity results in the highest values belonging
to the elements in the upper right of the periodic table. The lowest values
belong to the elements in the lower left of the table. These trends are
shown graphically in Figure 3.12.
Predict Metals generally have
lower electronegativities than
nonmetals. What type of ion would
this suggest each would form?
5B
Main Idea The properties of d -block metals do not vary much.
The properties of the d-block elements (which are all metals) vary less
and with less regularity than those of the main­-­group elements. This
trend is indicated by the curves in Figures 3.3 and 3.5, which flatten where
the d-block elements fall in the middle of Periods 4–6.
Recall that atoms of the d-block elements contain from zero to two
electrons in the s orbital of their highest occupied energy level and one
to ten electrons in the d sublevel of the next-lower energy level.
Figure 3.12
Electronegativity and Atomic Number The plot shows
electronegativity versus atomic number for Periods 1–6.
Electronegativity vs. Atomic Number
F
4.0
Period
2
Period
3
Period
4
Period
5
Period
6
3.5
Kr
Cl
3.0
Electronegativity
Xe
Rn
2.5
H
2.0
1.5
1.0
Li
Na
0.5
0
10
K
20
Rb
30
Cs
40
Atomic number
160
Chapter 5
50
60
70
80
go online
Periodic Trends in Electronegativity
Solve It! Cards
HMDScience.com
Sample Problem G Of the elements gallium, Ga, bromine, Br, and
calcium, Ca, which has the highest electronegativity? Explain your answer
in terms of periodic ­trends. 5C
SOLVE
All of these elements are in the fourth period. Bromine has the highest atomic
number and is farthest to the right in the period. Therefore, bromine should have
the highest electronegativity because electronegativity increases across the p
­ eriods.
Answers in Appendix E
1. Consider five hypothetical main-group elements, E, G, J, L, and M, that have the outer
electron ­configurations shown below.
E = 2s22p5 G = 4d105s25p5 J = 2s22p2
L = 5d106s26p5 M = 2s22p4
a. Identify the block location for each element. Then, determine which elements are in
the same ­period and which are in the same group.
b. Which element would you expect to have the highest electron affinity? Which would
you expect to form a 1- ion? Which should have the highest e­ lectronegativity?
c. Compare the ionic radius of the typical ion formed by the element G with the radius
of the ­atom from which the ion was formed.
d. Which element(s) contains seven valence e­ lectrons?
Therefore, electrons in both the ns sublevel and the (n–1)d sublevel are
available to interact with their surroundings. As a result, electrons in the
incompletely filled d sublevels are responsible for many characteristic
properties of the d-block ­elements.
Atomic Radii
The atomic radii of the d-block elements generally decrease across the
periods. However, this decrease is less than that for the main­-­group
­elements, because the electrons added to the (n–1)d sublevel shield the
outer electrons from the nucleus.
Also, note in Figure 3.3 that the radii dip to a low and then increase
slightly across each of the four periods that contain d-block elements.
As the number of electrons in the d sublevel increases, the radii increase
because of repulsion among the e­ lectrons.
In the sixth period, the f-block elements fall between lanthanum
(Group 3) and hafnium (Group 4). Because of the increase in atomic
number that occurs from lanthanum to hafnium, the atomic radius of
hafnium is actually slightly less than that of zirconium, Zr, the element
immediately above it. The radii of elements following hafnium in the
sixth period vary with increasing atomic number in the usual ­manner.
The Periodic Law
161
Ionization Energy
As they do for the main­-­group elements, ionization energies of the
d-block and f-block elements generally increase across the periods.
In contrast to the decrease down the main groups, however, the first
ionization energies of the d-block elements generally increase down each
group. This is because the electrons available for ionization in the outer
s sublevels are less shielded from the increasing nuclear charge by
electrons in the incomplete (n–1)d ­sublevels.
Ion Formation and Ionic Radii
Among all atoms of the d-block and f-block elements, electrons in the
highest occupied sublevel, the s and p sublevels, are always removed first.
For the d-block elements, this means that although newly added electrons occupy the d sublevels, the first electrons to be removed are those in
the outermost s sublevels. For example, iron, Fe, has the electron configuration [Ar]3d64s2. First, it loses two 4s electrons to form Fe2+ ([Ar]3d6).
Fe2+ can then lose a 3d electron to form Fe3+ ([Ar]3d5).
Most d-block elements commonly form 2+ ions in compounds. Some,
such as iron and chromium, also commonly form 3+ ions. The Group 3
elements form only ions with a 3+ charge. Copper forms 1+ and 2+ ions,
and silver usually forms only 1+ ions. As expected, the cations have
smaller radii than the atoms do. Comparing 2+ ions across the periods
shows a decrease in size that parallels the decrease in atomic ­radii.
Electronegativity
The d-block elements all have electronegativities between 1.1 and 2.5.
Only the active metals of Groups 1 and 2 have lower electronegativities.
The d-block elements also follow the general trend for electro­negativity
values to increase as radii decrease and vice ­versa. The f-block elements
all have similar electronegativities, which range from 1.1 to 1.5.
Section 3 Formative ASSESSMENT
Reviewing Main Ideas
1.State the general period and group trends among
main­-­group elements with respect to each of the
following ­properties: 5C
a.atomic radii
b.first ionization energy
c.electron affinity
d.ionic ­radii
e.electronegativity
2.a. In general, how do the periodic properties of
the d-block elements compare with those of
the main­-­group ­elements? 5B
b.Explain the comparison made in (­ a).
162
Chapter 5
3.For each main­-­group element, what is the
relationship between its group number and
the number of valence electrons that the group
­members have?
Critical Thinking
4. RELATING IDEAS Graph the general trends
(left to right and top to bottom) in the second
ionization energy (IE2) of an element as a
function of its atomic number, over the range
Z = 3–20. Label the minima and maxima on the
graph with the appropriate element symbol. 5C