Download Topic-2---Vectors-and-Forces

yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts
no text concepts found
Edexcel (9-1)
Triple Physics
Topic 2 Retrieval Practice Challenge
Calculate the final speed of a car
at rest of mass 1000kg that is hit Explain why doubling the velocity Calculate the acceleration of a
by a lorry of mass 7500kg
of an object would quadruple the bike that changes speed from 10
travelling at 20 m/s which then
stopping distance.
m/s to rest in 0.4 seconds.
comes to a rest.
Define momentum.
Describe how to calculate the
velocity from a distance time
Explain the difference between
vector and scalar quantities.
Describe the relationship
Describe and explain what would
Calculate the speed of a car that between the weight of an object
happen to a bag in a car that
moves 1500m in 1 minute.
and the gravitational field
braked suddenly without being
Calculate the weight of a 250g
mass on Earth.
One Point
List two factors that can increase
the reaction time of the driver of
a car.
Two Points
Three Points
Recall an example of a vector
and scalar pair.
Four Points
Edexcel (9-1)
Triple Physics
Topic 2 Answers
Momentum before = momentum The kinetic energy is related to
after (1)
the work done to stop the vehicle
Before = p = m x v (1)
(1), the kinetic energy is the
= 7500 x 5 = 37500 kgm/s (1) square of the velocity (1), double
After: 150000 = 1000 x v
the velocity then quadruple the
v= 37.5 m/s (1)
work (1).
a = (v-u) / t (1)
= (0-10)/0.4 (1)
=-25 m/s2 (1)
The velocity can be calculated
from the gradient of a distance
time graph (1).
Vector quantities have both
magnitude (size) and direction,
whereas scalar quantities have
only magnitude.
v = x/t
t = 1 x 60 = 60 s (1)
= 1500 / 60 (1)
= 25 m/s (1)
The greater the field strength
then the greater the weight (1)
as W = m x g (1).
Bag has a momentum (1), when
the car breaks the bag would
continue to travel in a straight
line (1) at the same velocity (1)
until it collides with the car again
to be decelerated (1).
W= mxg
m = 250 / 1000 = 0.25 kg (1)
W = 0.25 x 10 (1)
W = 2.5 N (1)
Drugs (1), Tiredness (1),
Distractions (1), Alcohol (1).
Velocity, Speed (1) or
Displacement, Distance (1)
p = m x v (1)