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Section 4.2
Graphing Linear Equations in Two
Variables: Ax + By = C
HAWKES LEARNING SYSTEMS
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Objectives
o Plot points that satisfy a linear equation and draw
the corresponding line.
o Recognize the standard form of a linear equation in
two variables: Ax + By = C
o Find the x-intercept and y-intercept of a line and
graph the corresponding line.
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
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The Standard Form: Ax + By = C
Standard Form of a Linear Equation
Any equation of the form
Ax + By = C,
where A, B, and C are real numbers and A and B are not
both equal to 0, is called the standard form of a linear
equation.
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The Standard Form: Ax + By = C
Notes
Note that in the standard form Ax + By = C, A and B may
be positive, negative, or 0, but A and B cannot both
equal 0.
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Copyright © 2013 by Hawkes Learning
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The Standard Form: Ax + By = C
To Graph a Linear Equation in Two Variables
1. Locate any two points that satisfy the equation.
(Choose values for x and y that lead to simple
solutions. Remember that there is an infinite
number of choices for either x or y. But, once a
value for x or y is chosen, the corresponding value
for the other variable is found by substituting into
the equation.)
2. Plot these two points on a Cartesian coordinate
system.
HAWKES LEARNING SYSTEMS
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Copyright © 2013 by Hawkes Learning
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The Standard Form: Ax + By = C
To Graph a Linear Equation in Two Variables (cont.)
3. Draw a line through these two points. (Note: Every
point on that line will satisfy the equation.)
4. To check: Locate a third point that satisfies the
equation and check to see that it does indeed lie on
the line.
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Copyright © 2013 by Hawkes Learning
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Example 1: Graphing a Linear Equation
in Two Variables
Graph each of the following linear equations.
a. 2x + 3y = 6
Solution
Make a table with headings x and y and, whenever
possible, choose values for x or y that lead to simple
solutions for the other variable. (Values chosen for x
and y are shown in red.)
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
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Example 1: Graphing a Linear Equation
in Two Variables (cont.)
x
2 x + 3y = 6
y
0 2  0  + 3y = 6 2
3 2  3 + 3y = 6 4
3
2 x + 3 0 = 6
0
5
2
 1
2x + 3   = 6
 3
1
3
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Example 1: Graphing a Linear Equation
in Two Variables (cont.)
b. x  2y = 1
Solution
Solve the equation for x (x = 2y + 1) and substitute 0, 1,
and 2 for y.
Results Substitutions Choices
x
x = 2y + 1
y
1
x = 2  0 + 1
0
3
x = 2 1 + 1
1
5
x = 2  2 + 1
2
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Example 1: Graphing a Linear Equation
in Two Variables (cont.)
c. y = 2x
Solution
Substitute 1, 0, and 1 for x.
Choices Substitutions Results
x
y = 2x
y
1
y = 2  1
2
0
y = 2  0
0
1
y = 2 1
2
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Locating the y-intercept and x-intercept
Intercepts
1. To find the y-intercept (where
the line crosses the y-axis),
substitute x = 0 and solve for y.
2. To find the x-intercept (where
the line crosses the x-axis),
substitute y = 0 and solve for x.
HAWKES LEARNING SYSTEMS
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Copyright © 2013 by Hawkes Learning
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Example 2: x- and y-Intercepts
Graph the following linear equations by locating the
y-intercept and the x-intercept.
a. x + 3y = 9
Solution
x=0
 0 + 3y = 9
3y = 9
y=3
 0,3 is the y -intercept.
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y=0
x + 3 0 = 9
x=9
 9,0 is the x -intercept.
Copyright © 2013 by Hawkes Learning
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Example 2: x- and y-Intercepts (cont.)
Plot the two intercepts and draw the line that contains
them.
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Example 2: x- and y-Intercepts (cont.)
b. 3x  2y = 12
Solution
x=0
3 0  2y = 12
2y = 12
y = 6
y=0
3x  2  0 = 12
3x = 12
x=4
 0, 6 is the y -intercept.  4,0 is the x -intercept.
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Copyright © 2013 by Hawkes Learning
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Example 2: x- and y-Intercepts (cont.)
Plot the two intercepts and draw the line that contains
them.
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Locating the y-intercept and x-intercept
Notes
In general, the intercepts are easy to find because
substituting 0 for x or y leads to an easy solution for the
other variable. However, when the intercepts result in
a point with fractional (or decimal) coordinates and
estimation is involved, then a third point that satisfies
the equation should be found to verify that the line is
graphed correctly.
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Practice Problems
1. Find the missing coordinate of each ordered pair so
that it belongs to the solution set of the equation
2x + y = 4:
(0, ), ( , 0), ( , 8), (1, )
 3
2. Does the ordered pair 1 ,
satisfy the equation
 2
3x + 2y = 6?
3. Find the x-intercept and y-intercept of the equation
3x + y = 9.
4. Graph the linear equation x  2y = 3.
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Practice Problem Answers
1.
 0,4  , 2,0  ,  2,8  ,  1,6 
2. Yes
3. x -intercept =  3,0  , y -intercept =  0,9 
4.
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Students Matter. Success Counts.
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