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Section 8.2
Solving Linear Equations:
ax + b = c
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Objectives
o Solve equations of the form ax + b = c.
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Solving Equations of the Form ax + b = c
Procedure for Solving Linear Equations that Simplify
to the Form ax + b = c
1. Combine like terms on both sides of the equation.
2. Use the addition principle of equality and add the
opposite of the constant b to both sides.
3. Use the multiplication (or division) principle of
equality to multiply both sides by the reciprocal of
the coefficient of the variable (or divide both sides
by the coefficient itself). The coefficient of the
variable will become +1.
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Solving Equations of the Form ax + b = c
Procedure for Solving Linear Equations that Simplify
to the Form ax + b = c (cont.)
4. Check your answer by substituting it for the variable
in the original equation.
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 1: Solving Linear Equations of the Form
ax + b = c
Solve the equation 3x + 3 = -18.
Solution
3x + 3= -18
3x + 3 - 3 = -18 - 3
3x = -21
3x -21
=
3
3
x = -7
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Write the equation.
Add -3 to both sides.
Simplify.
Divide both sides by 3.
Simplify.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 1: Solving Linear Equations of the Form
ax + b = c (cont.)
Check
3x + 3= -18
?
3 -7 + 3 = - 18
?
-21 + 3 = - 18
-18 = -18
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Substitute x = -7.
Simplify.
true statement
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 2: Solving Linear Equations of the Form
ax + b = c
Solve the equation –26 = 2y – 14 – 4y.
Solution
-26 = 2y - 14 - 4 y
Write the equation.
-26 = -2y - 14
Combine like terms.
-26 + 14 = -2y - 14 + 14
Add 14 to both sides.
-12 = -2y
-12 -2y
=
-2 -2
6=y
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Simplify.
Divide both sides by -2.
Simplify.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 2: Solving Linear Equations of the Form
ax + b = c (cont.)
Check
-26  2y - 14 - 4 y
?
-26  2  6 - 14 - 4  6 
?
-26  12 - 14 - 24
Simplify.
-26  -26
true statement
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Substitute y = 6.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 3: Solving Linear Equations involving
Decimals
Solve the equation 16.53 – 18.2z – 7.43 = 0.
Solution
Write the equation.
16.53 - 18.2z - 7.43  0
100 16.53 - 18.2z - 7.43  100  0
1653 - 1820z - 743  0
910 - 1820z  0
910 - 1820z - 910  0 - 910
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Multiply both sides by 100.
(This results in integer coefficients.)
Simplify.
Combine like terms.
Add -910 to both sides.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 3: Solving Linear Equations involving
Decimals (cont.)
-1820 z -910

-1820 -1820
1

z  0.5  or z  

2
16.53 - 18.2z - 7.43= 0
?
16.53 - 18.2  0.5 - 7.43 = 0
Divide both sides by -1820.
Simplify.
Check
?
16.53 - 9.10 - 7.43 = 0
0=0
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Substitute z = 0.5.
Simplify.
true statement
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 4: Solving Linear Equations involving
Decimals
Solve the equation 5.1x + 7.4 – 1.8x = –9.1.
Solution
Because the decimal numbers are accurate to tenths,
we could multiply both sides by 10 to get integer
coefficients. However, we can also work with the
decimal numbers directly as shown here.
5.1x + 7.4 - 1.8 x = -9.1
3.3x + 7.4 = -9.1
3.3x + 7.4 - 7.4 = -9.1 - 7.4
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Write the equation.
Combine like terms.
Add -7.4 to both sides.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 4: Solving Linear Equations involving
Decimals (cont.)
3.3x = -16.5
3.3x -16.5
=
3.3
3.3
x = -5
Simplify.
Divide both sides by the coefficient 3.3.
Simplify.
5.1x + 7.4 - 1.8 x  -9.1
?
5.1 -5 + 7.4 - 1.8  -5  - 9.1
?
-25.5 + 7.4 + 9  - 9.1
Check
-9.1  -9.1
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Substitute x = -5.
Simplify.
true statement
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 5: Solving Linear Equations with
Fractional Coefficients
5
5
10
Solve the equation x - = - .
6
2
9
Solution
5
5
10
x- =6
2
9
5
5
 10
18 x - = 18 6
 9
2
5 
 5
 10
18 x - 18
= 18 6 
 2
 9
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Write the equation.
Multiply both sides by 18 (the
LCM of the denominator).
Apply the distributive property.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 5: Solving Linear Equations with
Fractional Coefficients (cont.)
3
9
2
18 5
18 5 18  10 
 x -  =  - 
1 6
1 2 1  9
Multiply.
15x - 45= -20
Simplify.
15x - 45 + 45 = -20 + 45
15x = 25
15x 25
=
15 15
5
x=
3
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Add 45 to both sides.
Simplify.
Divide both sides by 15.
Simplify.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 5: Solving Linear Equations with
Fractional Coefficients (cont.)
Check
5
5
10
x- 6
2
9
5  5  5 ? 10
  -  6 3 2
9
25 45 ? 20
- 18 18
18
20
20
- 18
18
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
5
Substitute x = .
3
Simplify.
true statement
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Solving Equations of the Form ax + b = c
Notes
About Checking: Checking can be quite time
consuming and need not be done for every problem.
This is particularly important on exams. You should
check only if you have time after the entire exam is
completed.
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 6: Solving Linear Equations with
Fractional Coefficients
1
3
7 2
Solve the equation x + x + - x = 0.
2
4
2 3
1
3
7 2
x+ x+ - x=0
2
4
2 3
Solution
Write the equation.
3
7 2 
1
12 x + x + - x = 12  0
2
4
2 3 
Multiply both sides by 12
(the LCM of the denominator).
1 
3 
 7
2 
12  x  + 12  x  + 12   - 12  x  = 12  0 
2 
4 
 2
3 
Apply the distributive property.
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Example 6: Solving Linear Equations with
Fractional Coefficients (cont.)
6x + 9 x + 42 - 8 x = 0
7x + 42 = 0
7x + 42 - 42 = 0 - 42
Simplify.
Combine like terms.
Add -42 to both sides.
7 x = -42
Simplify.
7 x -42
=
7
7
Divide both sides by 7.
x = -6
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Simplify. Checking will
show that -6 is the solution.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Completion Example 7: Solving Linear Equations
with Fractional Coefficients
3 1 5
Solve the equation y + = .
4 2 8
3
1 5
y+ =
Solution
4
2 8
1
3
 5
_8  y +  = 8_  
4
 8
2
3
1
5



_8  y + 8
_   = 8_  
 4
 2
 8
6_y + _4 = 5_
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Write the equation.
8
Multiply both sides by__.
Apply the distributive property.
Simplify.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Completion Example 7: Solving Linear Equations
with Fractional Coefficients (cont.)
6_y + 4 - 4_ = 5 - _4
6y = _1
6y 1
=
_6 6_
1
y = 6_
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
4
Subtract __from
both sides.
Simplify.
6
Divide both sides by__.
Simplify.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Practice Problems
Solve the following linear equations.
1. x + 14 - 8x = -7
2. 2.4 = 2.6y - 5.9y - 0.9
2n 1 1
3. n - - =
3 2 6
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
3x 1 x
4.
+ - =0
14 2 7
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.
Practice Problem Answers
1. x = 3
2. y = -1
3. n = 2
4. x = -7
HAWKES LEARNING SYSTEMS
Students Matter. Success Counts.
Copyright © 2013 by Hawkes Learning
Systems/Quant Systems, Inc.
All rights reserved.