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Scattering µ1 µ2 m1 Ss H + U S1 Numbers (e,g,U) Rate equations Matrices (H, S, U) NEGF formalism m2 S2 1 Unified approach to quantum transport m1 Ss H + U S1 m2 S2 Unified approach [H]: Energy levels [U]: Channel potential S O U R C E D R A I N INSULATOR VG VD I [S1,2]: Injection from contacts [Ss]: Scattering Details of ingredients vary 2 Physics of Ss m1 Ss H + U S1 m2 S2 Scattering other than contacts (Responsible for Ohm’s Law) 3 Phase Breaking SP m1 Ss H + U S1 S2 m2 ihdy/dt – Hy – SPy = SP Environment changes during conduction through interactions (eg. Atoms vibrating, spins flipping, light absorption) Many-electron theory needed S, S function of occupancy (Pauli exclusion) 4 E.g. Electron-phonon m1 Ss H + U S1 m2 S2 Sin(E) ~ G.F = n(E-Eph) x Pabs(Eph) + n(E+Eph) x Pem(Eph) We’ll revisit this later Enforces Irreversibility m1 Ss H + U S1 S2 m2 ihdy/dt – Hy – SPy = SP Environment changes during conduction through interactions Brings system back to equilibrium PA->B/PB->A = exp[-(EB-EA)/kT] Signatures of Scattering Depending on DOS, scattering can increase or decrease G Phonon assisted Tunneling Sidebands 7 Signatures of Scattering g1 g 2 Electron can lose energy by setting molecule vibrating Current picks up signatures of these vibrations (Inelastic Electron Tunneling Spectroscopy) Expt. Mark Reed (Yale) 8 Scattering leads to Ohm’s Law T T1 T2 What’s the net transmission if we know T1 and T2 ? Simplest guess: T = T1T2 T T1 T2 Correction: T = T1T2 + T1T2R1R2 + .. 9 Bottom-Up treatment of Ohm’s Law T T1 T2 Net result: T = T1T2 + T1T2R1R2 + T1T2(R1R2)2 + … = T1T2/(1-R1R2) Since R1,2 = 1 – T1,2 T = T1T2/(T1+T2-T1T2) 1/T = 1/T1 + 1/T2 -1 10 There is an additive component ! T TL TL+dL Let r = (1-T)/T = R/T Then, r(L+dL) = r(L) + r(dL) = r(L) + dL/L dr/dL = 1/L L: Scattering length r(L) = L/L The limits L 0, ∞ T(L) = L/(L+L) make sense 11 Bottom-Up treatment of Ohm’s Law G = (2q2/h)MT (Landauer Theory) R = h/2q2MT = h/2q2M + (h/2q2M)R/T Contact Resistance Intrinsic Device Resistance Rdevice = (h/2q2M)L/L #modes depends on how many half wavelengths are fitted in M = A/(lF/2)2 = AkF2/p2 In 3-D, kF3 = 3p2n, and kF = mvF/ħ = mL/tħ Thus Rdevice = rL/A, where conductivity s = 1/r ~ nq2t/m OHM’s LAW 12 But we’re adding probabilities here !! What if we want to include quantum effects? t t1 t2 Correct way: Deal with t1, t2, r1, r2 (complex #s) Simplest guess: t = t1t2 t t1 t2 Correction: t = t1t2 + t1t2r1r2 + .. 13 Including phases then… t1 t t2 Net result: t = t1t2/(1-r1r2) T = |t|2 = |t1t2/(1-r1r2)|2 = T1T2/[1+R1R2-2(R1R2)cosDj] Dj = 2kDx • Resistances may not add !! • Resistances may be tunable by altering phase (e.g. path-length, temperature, magnetic field) 14 Interference with electrons Goldman group, Stonybrook Chandrasekhar et al, PRL ‘85 15 When do we simply add resistances? When interferences are unimportant. e.g. Impurities, temperature All cosine phase terms drop out in numerator (“Dephasing”) Ironically, we know how to solve the quantum problem!! So how would the classical equations come out of NEGF? (Dephasing or Incoherence) 16 Simple Model for Scattering ‘s’ m1 Ss H + U S1 S2 m2 Think of scattering center as a ‘virtual’ contact in equilibrium that extracts and reinjects charge after randomizing its phase T12 = [g1g2/(g1+g2)]D(E) T1s = [g1gs/(g1+gs)]D(E) Ts2 = [gsg2/(gs+g2)]D(E) Property of regular contacts: In thermal equilibrium determined by f1,2 17 Buttiker Probe Is = dE +.T2s(E) (f2 - fs ) = 0 ‘s’ m1 Ss H + U S1 T1s(E) (f1 - fs ) S2 Solve for fs and calculate m2 I1 = dE T1s(E) (f1 - fs ) +.T12(E) (f1 - f2 ) 18 Elastic Scattering Elastic scattering (No energy exchange) Set integrand of Is = 0 ‘s’ Ss m1 H + U S1 S2 1/T1s 1/Ts 2 1/T1 2 m2 fs = (T1sf1+Ts2f2)/(T1s+Ts2) I1 = dE T(E) (f1 - f2 ) T = T12 + T1sTs2/(T1s+Ts2) Like resistor network! 19 Inelastic Scattering ‘s’ m1 Ss H + U S1 m2 S2 Many parallel ‘channels’ Scattering exchanges energy among them (‘Vertical Flow’) A lot of energy exchange (‘Thermalization’) fs(E) = 1/[1+exp(E-ms)/kT] Adjust ms for zero Is Here we assume all energy relaxation processes allowed A single vibration (phonon) can only cause change in energy of ħw0 20 Beyond Buttiker Probes Instead of gs assume Ss has some energy structure More importantly, can’t calculate transmission between scatterer and channel very easily T1s ≠Tr(g1GgsG+), since Ssin ≠ gsfs Use instead I1 = 2q dETr[S1inA-G1Gn] h 21 Self-energy for Interacting systems El-El S(E): complicated function of f Instead of G(E) = 2p|t|2D(E) Coulomb Blockade Kondo effect We get G(E) = 2p|t|2f(E)D(E) 22 Self-energy for dephasing scattering Vibrations/Spins (“Bosons”) Ss = hGh+ Ssin(E) = D[Gn(E-ħw)Nw+ Gn(E+ħw)(Nw+1)] for 1 mode (Slide 5) ħw E E-ħw Phonon Absorption E ħw E+ħw Phonon Emission Ssout(E) = D[Gp(E-ħw)Nw + Gp(E+ħw)(Nw+1)] 23 Self-energy for dephasing scattering Vibrations/Spins (“Bosons”) Gn = GSsinG+ Ss = hGh+ Phonon emission Gs = Ssin + Ssout Ss = H(Gs) Polaronic shift Phonon absorption 24 Going beyond self-energy ‘s’ m1 Ss H + U S1 m2 S2 Beyond a certain point, calculating S(E) becomes hard, and may need summation of various infinite (possibly) non-convergent series A more accurate way is to directly solve the transport problem in ‘Fock’ space like in chapter 3 25 Summary Classical equations come out of quantum if we lose phase information (‘memory’) through dephasing While the consequence of dephasing is simple to implement (Newton’s Laws!), it’s not easy to get out of NEGF, especially if we have intermediate degrees of dephasing (ie, some incoherence, but not enough to make it classical) Needs careful physical considerations, but could have really important roles to play (e.g. spectroscopy) 26