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XTH STD --- MATHS CHAPTER 1 ------REAL NUMBERS April 1 to April 14 Previous knowledge : Terminating , non Terminating, recurring and non recurring decimals Definitions of rational and irrational numbers Prime and composite numbers Prime factorization Basic concepts : Euclid’s division lemma Fundamental theorem of Arithmetic Reviewing the concept of rational and irrational numbers Reviewing the decimal form of rational and irrational numbers Conditions for rational number to be terminating / non terminating recurring decimal form Find the H.C.F. and L.C.M. by Euclid’s lemma and by Fundamental theorem of Arithmetic. Verifying the property : H.C.F. x L.C.M = product of two numbers. Learning outcome : State the Euclid’s division lemma and Fundamental theorem of Arithmetic Define Real numbers and state few examples. Determine whether given rational number is terminating / non terminating recurring decimal form Prove given rational number can be written as terminating / non terminating recurring decimal form by observing the factors of denominator Calculate the H.C.F. and L.C.M. by Euclid’s lemma and by Fundamental theorem of Arithmetic Apply the above concepts while solving problems. Analyse the relation between H.C.F. and L.C.M. and two given numbers. Compare the relation between H.C.F. and L.C.M. and three given numbers. Justify real numbers to be rational or irrational . Sample questions: I. MCQ 1) 1 2 …. is a) Rational number b) Irrational number c) an integer d) none of these 2) HCF of ‘a’ and ‘b’ where a & b are prime no’s is : a) 1 b) a c) b d) a+b. II. 1) Define Euclid’s lemma 2) State fundamental theorem of arithmetic III. 1) Find HCF of 305, 657 and hence find L.C.M.(305 , 607 ). 2) Show that 12n cannot end with the digit ‘0’ or ‘5’. 3) Prove that 5 + 3 2 is an irrational number. 4) State the type of decimal for given rational number with reason. 129 2 57 7 5 2 Chapter: Pair of linear equations in two variables APRIL 15 to MAY 7, JUNE 15 to JUNE 25, 2011, Number of periods: 30 Previous knowledge: Mathematical equations Variables Examples of linear equations Solving of simple linear equations in one variable Graph of linear equations in two variables Key Concepts: Pair of linear equations in two variables Standard form of equations Intersecting, parallel and coincident lines Ratio of coefficients Relation between nature of solutions and ratio of coefficients Graph of a pair of linear equations in two variables Relation between number of solutions and points of intersection of lines Consistency of equations Graphical method of solving a pair of linear equations in two variables Algebraic method of solving a pair of linear equations in two variables Elimination method Substitution method Cross multiplication method Equations reducible to a pair of linear equations in two variables Word problems Learning Outcomes: The learner will be able to write equations in standard form state the conditions for consistency of a pair of linear equations in two variables find the nature of solutions find whether the lines are intersecting, parallel or coincident draw graphs of given linear equations in two variables solve by the graphical method solve by the elimination method solve by the substitution method solve by the cross multiplication method and verify by any other method reduce the given equations to linear equations and solve them convert word problems to linear equations and solve them Activity: To find the conditions for consistency of pairs of linear equations in two variables Type of Evaluation: MCQ Activity Written test Sample questions: 1. For what values of k is the system of equations 4x + 6y = 1 and 2x + ky = 7 consistent? a) k = 2 b) k = 3 c) k = 4 d) k = - 2 2. The solution of 2x + 3y = 8, 4x + 6y = 14 is a) x = 4, y = 0 b) x = 1, y = 2 c) x = 0, y = 4 d) no solution 3. Which of the following pair of linear equations has unique solution, no solution or infinitely many solutions? (i) 2x + y = 5; 3x + 2y = 8 (ii) x - 3y – 7 = 0; 3x - 3y - 15 = 0 (iii) x - 3y - 3 = 0; 3x – 9y – 2 = 0 (iv)3x – 5y = 20; 6x – 10y = 40 4. Are the following pair of linear equations consistent? Justify your answer. (i) – 3x – 4y = 12; 4y + 3x = 12 (ii) 3x – y = 1; x – 3y = 6 5. Solve graphically; 2x + y = 4 and 2x – y = 4. Write the vertices of the triangle formed by these lines and the y-axis. Also find the area of this triangle. 6. Use elimination method to find the solution of: x – 5y = 11; 2x + 3y = 4 7. Solve by substitution method: 8x + 5y = 9; 3x + 2y = 4 8. Solve by cross multiplication method: 2ax – 2by + a + 4b = 0;2bx + 2ay + b – 4a = 0 9. Solve: 5 𝑥−1 + 1 𝑦−2 = 2; 6 𝑥−1 − 3 𝑦−2 =1 10. The sum of a two digit number and the number obtained by reversing the digits is 66. If the digits of the number differ by 2. Find the number. How many such numbers are there? Chapter: Polynomials JUNE 27 to JULY 9, 2011, Number of periods: 14 Previous knowledge: Condition for an algebraic expression to be a polynomial. Polynomials with one variable The degree of a polynomial The zero of a polynomial Remainder theorem and factor theorem The difference between factor and a divisor and their relationship. Solution of a linear equation. Constructing graph Factorizing a polynomial by splitting the middle term. Factorizing a polynomial using factor theorem. Division of a polynomial. Graph of a first degree equation. Key Concepts: Graph of a linear polynomial Graph of a quadratic polynomial The quadratic polynomial as a parabola.( a>0 it is upward ‘u’ shape and a< 0 then it is reverse ‘u’ shaped curve) Geometrical meaning of the zeroes of a polynomial Points of intersection of graph with x-axis Number of zeroes of a polynomial The relation between the number of zeroes of a polynomial and the points of intersection of graph with x-axis Relation between zeroes of a polynomial and the coefficients of the polynomial Division Algorithm Verification of division algorithm Application of division algorithm Learning Outcomes: The learner will be able to state the standard form of a polynomial define linear, quadratic and cubic polynomials and give examples define the zero and degree of a polynomial draw the graphs of polynomials Find the number of zeroes of polynomials from the graph compute the zeroes of quadratic polynomial using suitable methods verify the relation between zeroes and the coefficients of polynomials frame a quadratic polynomial with the sum and product of zeroes given. state division algorithm do the long division of a polynomial of degree one and two verify division algorithm by dividing one polynomial with another apply division algorithm to find the dividend / divisor / quotient / remainder factorise given polynomials using Factor theorem and long division and determine other zeroes of polynomials of degree 3 or 4 Type of Evaluation: MCQ Written test Sample questions: 1. Quadratic polynomial having zeroes 1 and -2 is a) x2 – x + 2 b) x2 – x – 2 c) x2 + x – 2 d) x2 + x + 2 2. If 1 is a zero of the polynomial p(x) = a2x2 – 3ax + 3x – 1, then the value of a is a) – 1 b) 2 c) – 2 d) 0 3. Define a zero of a polynomial 4. State the division algorithm for polynomials 5. Find the zeroes of the quadratic polynomial and verify the relation between zeroes and the coefficients of polynomial: x2 + 7x + 10 6. Verify division algorithm after dividing p(x) = x3 – x2 + 4x – 8 by g(x) = x + 3 7. On dividing 2x3 + 4x2 + 5x + 7 by g(x), the quotient and the remainder are 2x and 7 – 5x respectively. Find g(x) 8. Form a quadratic polynomial whose zeroes are 3 and – 4 9. Form a quadratic polynomial which has its sum and product of zeroes ½ and – 4 respectively 10. Find other zeroes of x4 – 6x3 + 26x2 + 138x – 35 if two of its zeroes are 2 ± √3 Chapter: Statistics AUGUST 16 to SEPTEMBER 7, 2011, Number of periods: 22 Previous knowledge: Collection of data Organization of data Frequency table Class intervals Class size Class limits Class mark Measures of central tendency – mean, median, mode Frequency polygon Histogram Key Concepts: Mean of grouped data Direct method – x = 𝛴𝑓𝑖 𝑥𝑖 𝛴𝑓𝑖 Assumed mean method – x = a + 𝛴𝑓𝑖𝑑𝑖 𝛴𝑓𝑖 𝛴𝑓𝑖𝑢𝑖 Step-deviation method – x = a + h [ Mode of grouped data - mode = l + [ ] where ui = 𝛴𝑓𝑖 𝑓1 −𝑓0 2𝑓1 −𝑓0 −𝑓2 𝑥𝑖 −𝑎 ℎ ]Xh l = lowest limit of the modal class h = size of the class interval (all class sizes to be equal) f1 = frequency of the modal class fo = frequency of the class preceding the modal class. f2 = frequency of the class succeeding the modal class. Median of grouped data – median = l + [ 𝑛 −𝑐𝑓 2 𝑓 ] X h where l = lower limit of the median class cf = cu. frequency of class preceding the median class n= no. of observation h = class size (to be equal) Empirical relationship – 3 median = mode + 2 mean Cumulative frequency Ogive curves where ‘More than’ and ‘less than’ ogives Median as the x-coordinate of the point of intersection of the two ogives Learning Outcomes: The learner will be able to define the three measures of central tendency state the formulae for mean, median and mode identify the symbols in the formulae and the values to be substituted in their place apply the formulae to find the value of mean, median and mode organize the given data in the frequency table and find cumulative frequency draw the ogive curves calculate the median from the point of intersection of the ogive curves describe the use of measures of central tendency in real life situations Type of Evaluation: Written test Sample questions: 1. If the point of intersection of the two ogives for a given data is (17.5, 15), find the median of the data. 2. . Median of the following data is 525. If the total frequency is 100, find x and y. Class 0-100 Interval Freq. 2 100200 5 200300 x 300400 12 400500 17 500600 20 600700 y 700800 9 800900 7 9001000 4 3. The marks obtained by 30 students of class IX of a certain school in Math paper consisting of 100 marks are presented in table below. Find the mean and mode of marks obtained by the students. Using empirical formula, find the median also. Marks 10 - 25 25 - 40 40 - 55 55 - 70 70 - 85 85 - 100 Number of 2 3 7 6 6 6 students 4. The annual profits earned by 30 shops of a shopping complex in a locality give rise to the following distribution. Profit (in lakhs Rs.) No. of shops (frequency) More than or equal to 5 30 More than or equal to 10 28 More than or equal to 15 16 More than or equal to 20 14 More than or equal to 25 10 More than or equal to 30 7 More than or equal to 35 3 Draw both ogives for the data given above. Hence obtain the median profit from the graph and verify the result by using the formula. 5. The following distribution gives the daily income of 50 workers of a factory. Daily income(Rs) 100-120 120-140 140-160 160-180 180-200 Number of workers 12 14 8 6 10 Convert the distribution above to a less than type cumulative frequency distribution and draw its ogive. Hence obtain the median weight from the graph and verify the result by using the formula. TRIANGLES July 10 to July 31 ---2011 No. of periods: 22 PREVIOUS CONCEPTS Area of triangles between same parallel lines Area of triangle Congruent triangles; its criteria and its corresponding parts Pythagoras theorem (statement) Basic concepts Similar figurs.similar polygons Condition for the similarity between two triangles, ratio of corresponding sides in two equilateral triangles Basic proportionality theorem and its converse Criteria for similarity of triangles Pythagoras theorem and its converse LEARNING OUTCOME Learner will be able to Define and recognize similar and congruent triangles State the theorem Identify the corresponding parts of triangles and state the suitable criteria for… Explain the proof of the BPT with the help of areas of triangles between two parallel lines and area of triangle Prove the theorem based on areas of the triangles and pythagorus theorem by applying the criteria for the triangles. Apply the theorem while solving the problems after analyzing the questions,changing figures and explain the proof and summarizing the solution. Justify the proof of the theorem by activity method Activity 1. Pythagoras theorem 2. Areas of similar triangles 3. Basic Proportionality Theorem FA-II Sample Questions 1. D and E trisect BC. Prove that 8. AE2 = 3.AC2 + 5.AD2. 2. In ABC, C = 90 0, AC= 3 .BC. Prove that ABC = 90 0. 3. In Q no.2, D is the midpoint of BC. Prove that BC2 = 4 ( AD2 - AC2 ) ; AB2 = 4 AD2 – 3 AC2. 4. In ABC, C is an obtuse angle and AD BC, AB2 = AC2 + 3. BC2. Prove that BC = CD. 5. A point ‘D’ is on the side BC of an equilateral triangle ABC such that DC = 1 BC. Prove that AD2 = 13. AD 2. 4 6. ABC is a right triangle , right angled at B. AD and CE are two medians drawn from A and C respectively. If AC = 3 5 c.m., find the length of CE. 7.In fig. DE ll BC such that AE = ¼ BC. If AB = 6 c.m. find AD. 8. In ABC, D and E are points on the sides AB and AC respectively such that DE ll BC if AD= x, DB = x-2, AE= x+2 and EC= x-1. Find the value of x. 9. AE is the bisector of the exterior CAD meeting BC produced in E. If AB= 10cm, AC=6cm and BC=12cm. Find CE. 10. ABC=900 and BD AC. If BD=8cm and AD=4cm, find CD. 11.The areas of 2 similar triangles are: 25cm2 and 36 cm2 respectively if the altitude of the first triangle is 2.4cm. Find the corresponding altitude of the other. 12. Two isosceles triangles have equal vertical angles and their areas are in the ratio 36:25. Find ratio of the corresponding heights. 13. ABCD is a trapezium in which AB ll CD. The diagonals AC and BD intersect at O. Prove that AOB ~ 14. In COD, find Ar( AOD)/ Ar( COD). ABC, BD ll AC, BC2 =2AC*CD, then prove that AB=AC. 15. In ABC, N is a point on AC such that BN AC. If BN2=AN*NC prove that B=900. 16.`ABCD is a rectangle points M and N are on BD such that AM BD and CN BD. Prove that BM2+BN2= DM2+DN2. 17.In ABC, AD is a median. Prove that AB2+AC2=2AD2+2 DC2. Introduction to Trigonometry August 1 to August 12 No of periods: 15 Previous knowledge: Right angled triangle Pythagoras theorem Complementary angles Identity Key concepts: Hypotenuse, adjacent and opposite sides of a given angle Trigonometric ratios Trigonometric ratios of Complementary angles Trigonometric Identity Learning outcome: Learner will be able to Define right triangle, Hypotenuse Name adjacent and opposite sides of given angle Define Trigonometric ratios Identify Complementary angles State and relate Trigonometric ratios of Complementary angles State, prove the identity Apply basic identity with the help of known concepts Sample Questions 1. If tan + sin = a and tan - sin =b, show that a2 – b2 = 4. 2. Without using tables, evaluate: Sin (50+) – cos (40-) +tan10. tan100. tan200. tan700. tan800. tan890. 3. Prove that sin2A.tanA+cos2A.cotA+2sinA.cosA=tanA+cotA. 4. If x=r.sin1.cos2 , y= r.sin1 r.sin2, z= r.cos1 , show that x2+y2+z2 =r2. 5. If 3 tan =3 sin, find the values of sin2 - cos2. ( 1/3) 6. Prove that sin6+cos6=1-3 sin2.cos2. 7. If (cosec - sin ) =’ m ‘and sec - cos =’ n’. show that m2 n2 (m2 +n2 + 3) = 1