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A GENERALIZATION OF THE CARTAN FORM pdq − Hdt VIOREL PETREHUŞ We prove the existence and uniqueness of a Cartan form for Lagrangians on J k Y . We restricted to fiber manifolds πX,Y : Y → X where X is unidimensional. AMS 2000 Subject Classification: Primary 57R55, Secondary 53Z05. Key words: fiber space, manifold of jets, Cartan form. In this paper we follow the lines of [7], [6], [4] from Lagrangians on J 1 Y or J 2 Y to Lagrangians on J k Y . The first part is standard and more general computations can be found in [6], [4], [8]. Our result is that the form θLag associated with a lagrangian Lag on J k Y is well defined on the space J 2k−1 Y , and is contained in Theorem 3. Many other forms θ with some properties of θLag can be defined, see [5]. This form is important in the study of conservation laws for Lag or in the study of conservative numerical methods for the Euler equations associated with Lag. The basic space of our computations is J k Y , the space of k jets of sections of the fiber space πXY : Y → X. In the sequel X is the real field and Y is an N + 1 dimensional manifold. The fibre of πXY : Y → X is diffeomorphic to a given manifold Q. All manifolds are finite dimensional. A k jet over x ∈ X is a class of equivalence of sections of Y defined in a neighborhood of x such that two sections are equivalent iff their Taylor developments agree up to order k. The jet corresponding to section s will be denoted by j k s(x). The definition is independent of the local coordinates on X or Q. If x is a local coordinate on X and y1 , y 2 , . . . , yN are local coordinates on Q, then on J k Y we use the coordinates x, y A , yiA A=1,...,N, i=1,...,k , where for the jet of a section s : X → di A Y , s(x) = x, s1 (x), s2 (x), . . . , sN (x) we have y A = sA (x), yiA = dx i s (x). A A k In what follows y0 is identical with y . The correspondence x → j s(x) is a section of J k Y and is denoted by j k s. By truncation of a k development to a l development (l < k) we get a projection πJ l Y,J k Y : J k Y → J l Y . The projective limit of these spaces is denoted by J ∞ Y and the limit of their jets MATH. REPORTS 9(59), 4 (2007), 357–368 358 Viorel Petrehuş 2 corresponding to section s at x ∈ X is denoted j ∞ s(x). For more about jet spaces and the change of coordinates see [10], A projetable diffeomorphism η of Y is a diffeomorphism ηY : Y → Y such that there exists a diffeomorphism ηX of X such that the diagram (1) η Y πX,Y Y −→ Y πX,Y X X −→ X η is commutative; η can be extended to a diffeomorphism ηJ k Y of J k Y that the diagram jk Y πJ k−1 Y,J k Y .. . j1Y πY,J 1Y η k J Y −→ η 1 J Y −→ ηY Y πX,Y −→ X −→ ηX such jk Y πJ k−1 Y,J k Y .. . j1Y πY,J 1 Y Y πX,Y X is commutative. The extension is given by −1 (ηX (x)) . (2) ηJ k Y j k s(x) = j k ηY ◦ s ◦ ηX ∂ A ∂ ∂x + y1 ∂y A + space T J k−1 Y , Using local coordinates we define the total derivative Dx = y2A ∂y∂A + · · · + ykA ∂y∂A 1 k−1 as a function from J k Y to the tangent which sends a point γ ∈ J k Y to a vector tangent to J k−1 Y at πJ k−1 Y,J k Y (γ). More conveniently, we consider Dx as a “vector field” on J ∞ Y by extending N ∂ ∂ A + ∞ the preceding definition to Dx = ∂x k=0 A=1 yk+1 ∂y A . k Any function f : J k Y → R can be considered as a function also denoted abusively f , defined on any J n Y (n > k) by the composition J n Y J kY f J ∞Y πJ k Y,J n Y −→ −→ R and consequently defined on . Analogously, any form ω ∈ ΛJ k Y gives a form on J n Y (n > k) by the formula πJ∗ n Y,J k Y ω, so it gives a form on J ∞ Y . We define Dx,p = Dx ◦ Dx ◦ · · · ◦ Dx (p times), which gives for f : J k Y → R, a function Dx,p f = Dx Dx (. . . Dx (f )) defined on J k+p Y . For A generalization of the Cartan form pdq − Hdt 3 359 p = 0 we define Dx,0 = identity. For a section s of Y we have dk sA (x) dsA (x) d f x, sA (x), ,..., = dx dx dxk dsA (x) dk sA (x) dk+1 sA (x) A k+1 , f ) j s(x) . ,..., = (D = (Dx f ) x, s (x), x dx dxk dxk+1 For the one parameter group of diffeomorphisms ηYε : Y → Y which ε : X → X, its infinitesimal generator is of covers the one parameter group ηX the form ∂ ∂ + V A (x, y) A (3) V = V x (x) ∂x ∂y (by convention the sum is taken over all values of A from 1 to N ). The extended group ηJε k Y : J k Y → J k Y has a generator denoted by j k (V ) = V x (x) (4) N N A=1 j=1 A=1 The components of jk k ∂ ∂ ∂ + V A (x, y) A + VjA A . ∂x ∂y ∂yj (V ) are given (see [8]) by A , VjA = Dx,j V vA + V x yj+1 where V vA = V A − y1A V x . ∂ A vA ∂ A x = is called the vertical The field V v = AV A V − y1 V ∂y A ∂y A k part of V . The field j (V ) can be split as (5) j k (V ) = j k (V )v + j k (V )h , (6) where the vertical part is (7) j k (V )v = V vA N N k k ∂ ∂ vA ∂ + D V = Dx,j V vA A x,j A A ∂y ∂yj ∂yj A=1 j=1 A A=1 j=0 and the horizontal one is (8) N k ∂ ∂ A + V x yj+1 = V x Dx . j (V ) = V ∂x ∂yjA k h x A=1 j=0 One sees that k j (V ) h k x ∂ . j s(x) = j s∗ (x) V ∂x k The field j k (V ) is tangent to J k Y , but j k (V )v and j k (V )h have extra A which cancel each other; j k (V )v and j k (V )h are always terms involving yk+1 ∞ defined on J Y by extending the sumation over j to ∞. To avoid such 360 Viorel Petrehuş 4 technical difficulties as (8) not being tangent to J k Y , we shall consider all fields as functions or forms defined on J ∞ Y . Functions and forms are supposed finitek depending on that form or function. For depending on J k Y for some ∂ A x is defined on a vector field V = V x ∂x + A ∞ j=0 Vj , we assume that V J m Y and VjA depends on J j+m Y for a fixed m which depends on V; Dx is an example of such a vector field. In this case, the basic operations of calculus with differential forms: outer product, exterior derivative, Lie derivative, etc. make sense (see [1]). A dx, The differential forms θ0A = θ A = dy A − y1A dx, θjA = dyjA − yj+1 for j ≥ 1 are defined using local coordinates. For any section s we have j k s∗ θjA = 0, and θjA (Dx ) = 0. For more on jet spaces see [1], [6], [10]. By a Lagrangian on J k Y we understand a differential of degree 1 1form ∗ X . Using local Λ which with any jet γ ∈ J k Y associates a value in πX,J kY coordinates, a Lagrangian is a differential form (9) Lag = L x, y A , y1A , . . . , ykA dx. Consider now a C ∞ -family of sections sε : [a (ε) , b(ε)] → Y defined for ε d |ε=0 sε . Then if all fits into a coordinate in a neighborhood of 0, and let ζ = dε 0 chart, integration by parts gives (s equals s): b(ε) d k ε (10a) L j s (x) dx = dε ε=0 a(e) b(ε) dk sεA (x) dsεA (x) d εA ,..., L x, s (x), dx = = dε ε=0 a(e) dx dxk N k b d ∂L (10b) (−1)j · ζ A (x)dx+ j k s (x) = dxj ∂yjA a A=1 j=0 (10c) + L j k s (b) b (0) − L j k s (a) a (0)+ j−1 N k dj−m−1 ζ A b d ∂L m k (−1) · = j s(x) + dxm ∂yjA dxj−m−1 a m=0 A=1 j=1 (10d) (10e) N k ∂L 2k s(x) · ζ A (x)dx+ j A ∂y j A=1 j=0 a + L j k s (b) b (0) − L j k s (a) a (0)+ = b (−1)j Dx.j dj−m−1 ζ A b ∂L 2k−1 . (−1) Dx,m A j s (x) · + dxj−m−1 a ∂y j m=0 A=1 j=1 j−1 N k m A generalization of the Cartan form pdq − Hdt 5 361 The variation splits into an integral over [a, b] and a boundary part. We shall express the variation in terms of the differential form below defined locally on J 2k−1 Y as θLag = Ldx + (11) j−1 N k (−1)m Dx,m A=1 j=1 m=0 = Ldx + N k−1 k−b−1 ∂L A · θj−m−1 = A ∂yj (−1)m Dx,m A=1 b=0 m=0 ∂L A ∂ym+b+1 · θbA . Let us look at this variation in a different way, as in [6], [4]. Let M the space of C ∞ -applications ϕ : [0, 1] → Y and ϕX : [0, 1] → X with ϕX injective such that ϕX = πX,Y ◦ ϕ. Then s = ϕ ◦ ϕ−1 X is a section of Y defined on [a, b] = ϕX ([0, 1]) ⊂ X and we define the action S by S (ϕ) = (12) b a = a b b k L j s(x) dx = L j k ϕ ◦ ϕ−1 (x) dx = X ∗ j k ϕ ◦ ϕ−1 Lag. X a Let ηYε be a one-parameter group of diffeomorphisms of Y which covers ε of X, and let V be its infinitesimal generator. If the one parameter group ηX def def ε ◦ ϕ , then we have ϕε = π ε ϕε = ηYε ◦ ϕ and ϕεX = ηX X X,Y ◦ ϕ . In this case, X ε−1 sε = ϕε ◦ ϕX is a section of Y defined on [a(ε), b (ε)] = ϕεX ([a, b]) and there is defined the action ε S (ϕ ) = b(ε) a(ε) b(ε) = a(ε) L j s (x) dx = b(ε) k ε a(ε) ε−1 L j k ϕε ◦ ϕX (x) dx = ε−1 ∗ j k ϕε ◦ ϕX Lag. The definition of ηJε k Y as ε ε−1 (x) = j k ηYε ◦ ϕ ◦ ϕ−1 (ηX (x)) = ηJε k Y j k ϕ ◦ ϕ−1 X X ◦ ηX ε−1 ε (x)) (ηX = j k ϕε ◦ ϕX implies ∗ ε−1 ∗ ε∗ ◦ ηJε∗k Y = ηX ◦ j k ϕε ◦ ϕX . j k ϕ ◦ ϕ−1 X 362 Viorel Petrehuş 6 Using this, we get (L is the Lie derivative) b(ε) ∂ ∂ ε−1 ∗ j k ϕε ◦ ϕX Lag = S (ϕε ) = ∂ε ε=0 ∂ε ε=0 a(ε) b ∂ ε−1 ∗ ε∗ k ηX j ϕε ◦ ϕX Lag = = ∂ε ε=0 a b ∗ ε∗ ∂ j k ϕ ◦ ϕ−1 ηJ k Y Lag = = X ∂ε ε=0 a b ∗ j k ϕ ◦ ϕ−1 Lj k (V ) Lag. = X a Now, we split the Lie derivative as Lj k (V ) = Lj k (V )h + Lj k (V )v and obtain (13a) [a,b] (13b) ∗ j ϕ ◦ ϕ−1 Lj k (V )h Lag = X k = [a,b] = (13c) [a,b] [a,b] (13d) (13e) LV x ∂ ∂x diV x [a,b] = [a,b] ∗ j k ϕ ◦ ϕ−1 LV x Dx Lag = X ∗ j k ϕ ◦ ϕ−1 Lj k (ϕ◦ϕ−1 ) (V x ∂ ) Lag = X X ∗ ∂x = diV x ∗ j k ϕ ◦ ϕ−1 Lag = X ∂ ∂x ∂ ∂x + iV x ∂ ∂x ∗ d j k ϕ ◦ ϕ−1 Lag = X L j k ϕ ◦ ϕ−1 (x) dx = X b x (x) · V = L j k ϕ ◦ ϕ−1 = L j k s(b) b (0) − L j k s(a) a (0) = X a b −1 ∗ 2k−1 ϕ ◦ ϕX ij 2k−1 (V )h θLag = =j a −1 ∗ 2k−1 j ϕ ◦ ϕX ij k (V )h θLag . = ∂[a,b] So, the first two terms of the boundary part of the variation (10e) come b ∗ · from j 2k−1 (V )h . Necessarily, the third term of (10e) is equal to a j k ϕ ◦ ϕ−1 X A generalization of the Cartan form pdq − Hdt 7 363 Lj k (V )v Lag. To connect the third term in (10e) with θLag , we look at the equations ε d d d ε−1 ε−1 (x) = ηY ◦ ϕ ◦ ϕ−1 (x) = ζ(x) = sε = ϕε ◦ ϕX X ◦ ηX dε ε=0 dε ε=0 dε ε=0 ε d ∂ ε−1 = = ηY ◦ s ◦ ηX (x) = V (s(x)) − ds V x (x) dε ε=0 ∂x ∂ dsA (x) = V v (s(x)). = V A (s(x)) − V x (x) dx ∂y A Hence j−m−1 dj−m−1 vA dj−m−1 ζ A (x) vA = V (s(x)) = D V s(x) = j x,j−m−1 dxj−m−1 dxj−m−1 = j 2k−1 (V )vA j−m−1 . Then the third term of the boundary part of the variation (10e) is b ∂L 2k−1 vA 2k−1 (−1) Dx,m A j s (x) · j (V )j−m−1 a ∂yj A=1 j=1 m=0 j−1 N k = j−1 N k m (−1)m Dx,m A=1 j=1 m=0 (14) (15) b ∂L 2k−1 v A 2k−1 s (x) · θ (V ) j j j−m−1 a ∂yjA b = j 2k−1 s∗ ij 2k−1 (V )v θLag a j 2k−1 (s)∗ ij 2k−1 (V )v θLag . = ∂[a,b] ∗ ij 2k−1 (V ) θLag for the Now, (13e) and (15) yield ∂[a,b] j 2k−1 ϕ ◦ ϕ−1 X boundary part of the variation. These results may be summarized as Lemma 1. Let Lag = L x, y A , y1A , . . . , ykA dx be a Lagrangian defined on J k Y and ηYε : Y → Y a one parameter group of projetable diffeomrphisms of Y with infinitesimal generator V . Let ηJε k Y be the extension of ηYε to J k Y and j k (V ) its infinitesimal generator. Then for ϕ ∈ M, ϕX ([0, 1]) = [a, b], such that the image of ϕ is contained into a coordinate chart, the variation of the action functional (12) is given by k b N ∂L ∂ ε (−1)j Dx,j A j 2k ϕ ◦ ϕ−1 (x) ·V vA (s(x)) dx+ S (ϕ ) = X ∂ε ε=0 ∂yj A=1 j=0 a ∗ j 2k−1 ϕ ◦ ϕ−1 ij 2k−1 (V ) θLag . + X ∂[a,b] 364 Viorel Petrehuş 8 The exterior derivative of θLag is given by dθLag − j−1 N k ∂L = (−1)m d Dx,m A ∂yj A=1 j=1 m=0 j−1 N k (−1)m Dx,m A=1 j=1 m=0 A ∧ θj−m−1 − ∂L A dyj−m ∧ dx + dL ∧ dx. A ∂yj ∗ iW dθLag for a vertical Now, we are going to compute j 2k−1 ϕ ◦ ϕ−1 X 2k−1 A ∂ 2k−1 Y . We have W on J vector field W = N j ∂y A A=1 j=0 j ∂L A (−1) d Dx,m A (W ) · θj−m−1 − iW dθLag = ∂yj A=1 j=1 m=0 j−1 N k ∂L m A (−1) Wj−m−1 · d Dx,m A − − ∂yj A=1 j=1 m=0 j−1 N k j−1 N k m N k ∂L ∂L A A (−1) Dx,m A · Wj−m · dx + W · dx. − ∂yj ∂yjA j A=1 j=1 m=0 A=1 j=0 m ∗ A θj = 0, we get Taking into account that j 2k−1 ϕ ◦ ϕ−1 X (16a) (16b) (16c) (16d) (16e) ∗ iW dθLag j 2k−1 ϕ ◦ ϕ−1 X ∂L −1 (−1) · m+1 ϕ ◦ ϕX (x) dx =− A dx ∂y j A=1 j=1 m=0 j−1 N k d ∂L m A −1 (−1) Wj−m · m ϕ ◦ ϕX (x) · dx − A dx ∂y j A=1 j=1 m=0 j−1 k N m A Wj−m−1 d k N ∂L −1 ϕ ◦ ϕ (x) · WjA · dx + X A ∂yj A=1 j=0 N ∂L −1 ϕ ◦ ϕ (x) · W0A + = X A ∂y0 A=1 N k ∂L j d −1 (−1) Dx,j A ϕ ◦ ϕX (x) · W0A dx + dxj ∂yj A=1 j=1 A generalization of the Cartan form pdq − Hdt 9 (16f) = N A=1 k j=0 365 ∂L · W0A dx. Dx,j A ϕ ◦ ϕ−1 X (x) ∂yj d (−1)j dxj Now, Lemma 1 may be reformulated as Proposition 2. Under the hypotheses of Lemma 1, the variation of the functional S is (17) ∂ |ε=0 S (ϕε ) = ∂ε [a,b] ∗ j 2k−1 ϕ ◦ ϕ−1 ij 2k−1 (V ) dθLag + X + ∂[a,b] ∗ j 2k−1 ϕ ◦ ϕ−1 ij 2k−1 (V ) θLag . X Proof. Because ∗ ∗ ij 2k−1 (V )h dθLag = j 2k−1 ϕ ◦ ϕ−1 ij 2k−1 (ϕ◦ϕ−1 ) (V x ∂ ) dθLag j 2k−1 ϕ ◦ ϕ−1 X X X ∗ ∂x −1 ∗ 2k−1 = iV x ∂ dj ϕ ◦ ϕX θLag = iV x ∂ 0 = 0, ∂x ∂x by (16) we have ∗ ∗ ij 2k−1 (V ) dθLag = j 2k−1 ϕ ◦ ϕ−1 ij 2k−1 (V )v dθLag j 2k−1 ϕ ◦ ϕ−1 X X ∂L 2k −1 = (−1) Dx,j A j ϕ ◦ ϕX (x) · VjvA ϕ ◦ ϕ−1 X dx. ∂yj A=1 j=0 N k j The result now follows from Lemma 1. Now, we shall prove that the definition (11) of θLag is independent of any coordinate chart on the space J 2k−1 Y of jets and formula (17) of the variation holds for any ϕ ∈ M. Theorem 3. Let the fibration πX,Y : Y → X, with X a one-dimensional k manifold. Let Lag be a Lagrangian defined on J Y , which εis given in a co A A A ordinate chart by Lag = L x, y , y1 , . . . , yk dx and let ηY : Y → Y be a one-parameter group (1) of projetable diffeomrphisms of Y with infinitesimal generator V given by (3). Let ηJε k Y be the extension (2) of ηYε to J k Y and j k (V ) its infinitesimal generator given by (4), (6), (7), (8). Let on J 2k−1 Y the form θLag given locally by (11). Then a) θLag is well defined on J 2k−1 Y ; 366 Viorel Petrehuş 10 b) for ϕ ∈ M, ϕX ([0, 1]) = [a, b], the variation of the action functional (12) is given by ∗ ∂ |ε=0 S (ϕε ) = j 2k−1 ϕ ◦ ϕ−1 ij 2k−1 (V ) dθLag + X ∂ε [a,b] ∗ j 2k−1 ϕ ◦ ϕ−1 ij 2k−1 (V ) θLag ; + X ∂[a,b] c) we have the formula ∗ ∗ −1 2k−1 j k ϕ ◦ ϕ−1 Lag = j θLag ; ϕ ◦ ϕ X X d) in a standard coordinate chart for J 2k−1 Y , θLag only depends at each point j 2k−1 (s)(x) on dx and dyjA , for j ≤ k − 1; e) if W is a vector field on J 2k−1 Y , tangent to the fibers of πY,J 2k−1 Y , ∗ (iW dθLag ) = 0; then j 2k ϕ ◦ ϕ−1 X f) θLag is uniquely defined by b), c), d), e); g) the Euler-Lagrange equations d ∂L j −1 (−1) ϕ ◦ ϕX = 0, A = 1, 2, . . . , N (18) dxj ∂yjA 0≤j≤k are equivalent to (19) ∗ (iW dθLag ) = 0 j 2k−1 ϕ ◦ ϕ−1 X for any vector field W on J 2k−1 Y . Proof. If the image of ϕ is contained into a coordinate chart, then b) is Proposition 2, c) follows from (11), d) is evident from the definition of θLag , e) follows from (16) taking into account that W0A = 0. Assuming again that the image of ϕ is contained into a coordinate chart, let θ be any form with properties b), c), d), e) above. It follows from c) anc d) that θ = Ldx + k−1 j A N k−1 j A FA θj . Let ∆ = θ − θLag . Then ∆ = N A=1 j=0 A=1 j=0 GA θj . From 2k−1 ∗ (s) ij 2k−1 (V ) d∆ = 0 for any projetable vector field V on b) we get [a,b] j Y and any section s = ϕ ◦ ϕ−1 X . From e) we have iW d∆ = 0 for any vertical vector field πY,J 2k−1 Y , whence j 2k−1 (s)∗ iW d∆ = 0 (20) [a,b] for any section s and any vector field W = W x (x) N 2k−1 ∂ ∂ ∂ + W A (x, y) A + WjA A , ∂x ∂y ∂yj A=1 j=1 A generalization of the Cartan form pdq − Hdt 11 367 where WjA are arbitrary functions on J 2k−1 Y . A simple calculation shows that for W x (x) = 0 we have j 2k−1 ∗ (s) (iW d∆) = N k−1 A=1 j=1 − d j j−1 − GA (s (x)) − GA (s(x)) WjA (s(x))dx− dx N N d 0 A Gk−1 GA (s(x))W0A (s(x))dx − A (s(x))Wk (s(x)) dx. dx A=1 A=1 Now, condition (20) implies − d j j−1 G (s(x)) − GA (s(x)) = 0, j = 1, 2, . . . , k − 1, A = 1, 2, . . . , N dx A Gk−1 A (s(x)) = 0, A = 1, 2, . . . , N whence GjA (s(x)) = 0, j = k − 1, k − 2, k − 3, . . . , 1, 0. Consequently, ∆ = 0 and θ = θLag , whence f). We proved b)–f) locally, that is, in the case where the image of ϕ is contained into a coordinate chart. Let η : Y1 = (a1 , b1 ) × D1 → Y2 = (a2 , b2 ) × D2 , D1 , D2 ⊂ RN , be a change of coordinates for the fiber bundle Y , η(x, y) = ofcoordinates for J k Y , k ∈ N, (ηX (x), ηRN (x, y)). Then the associated k change −1 k k (ηX (x)), see is given by ηk : J Y1 → J Y2 , ηk j s(x) = j k ηRN ◦ s ◦ ηX k k (2). Let Lag1 and Lag2 be the Lagrangians on J Y1 , and on J Y2 , respectively, and let θ1 , θ2 be the Cartan forms (11) using local coordinates on J 2k−1 Y1 ∗ and on J 2k−1 Y2 respectively. Then on J 2k−1 Y1 the forms θ1 and η2k−1 θ2 fulfill b), c), d), e) of the theorem with respect to the Lagrangian Lag1 = ηk∗ Lag2 , ∗ θ2 , which proves that θLag whence, by the local form of f) we have θ1 = η2k−1 2k−1 is well defined on J Y , that is, a). Now b)–f) follow from a) and the local forms of b)–f). g) By (16), the Euler-Lagrange equations (18) are equivalent to (19) for the vertical part πX,J 2k−1 Y of W . For the horizontal vector field Dx we have ∗ ∗ (iDx dθLag ) = i ∂ dj 2k−1 ϕ ◦ ϕ−1 θLag = i j 2k−1 ϕ ◦ ϕ−1 X X ∂x ∂ ∂x 0=0 ∗ θLag is a two form on R. Since any vector field is the sum as dj 2k−1 ϕ ◦ ϕ−1 X of Dx and a vertical vector field πX,J 2k−1 Y , g) follows. 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