Download Block 3 Drill Set - PHYS 242, General Physics II

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Quantum potential wikipedia , lookup

Potential energy wikipedia , lookup

Maxwell's equations wikipedia , lookup

Time in physics wikipedia , lookup

Euler equations (fluid dynamics) wikipedia , lookup

Equations of motion wikipedia , lookup

Nordström's theory of gravitation wikipedia , lookup

Perturbation theory wikipedia , lookup

Schrödinger equation wikipedia , lookup

Dirac equation wikipedia , lookup

Lorentz force wikipedia , lookup

Electric charge wikipedia , lookup

Derivation of the Navier–Stokes equations wikipedia , lookup

Equation of state wikipedia , lookup

Aharonov–Bohm effect wikipedia , lookup

Van der Waals equation wikipedia , lookup

Partial differential equation wikipedia , lookup

Relativistic quantum mechanics wikipedia , lookup

Electrostatics wikipedia , lookup

Transcript
PHYSICS 242
BLOCK 3 DRILL SET, SPRING ‘17
NAME _____________________________
Slide this paper under the door of Marteena 308 any time before 7:50 AM Friday, February 3, or give it to me in
Marteena 312 by 8:00 AM that day. Use one different equation from the Block 3 objectives for each problem.
1. An electric field does 9.63 MeV of work in moving a very small charged particle from point a to point b through
a potential difference of –3.21 MV. Find the charge of the particle as a multiple of e.
EQUATION USED
SOLUTION
ANSWER
____e
2. The electric potential is given by (25 V/m7)(xz6 + x 3y4) in the region including the point (x,y,z) = (–4,3,–2) m
exactly. Find the z-component of the electric field at that point. SHOW ALL YOUR STEPS FOR CREDIT.
EQUATION USED (ONE EQUAL SIGN)
SOLUTION
ANSWER
=
3. As shown, one point charge of –4.00 nC is located at y = +5.00 mm and another point charge of +5.00 nC is
located at y = –4.00 mm.. Find the electric potential energy of this system of two point charges.
THE ONE EQUATION USED
SOLUTION
ANSWER
–4.00 nCO
+5.00 nCO
+
4. Calculate their electric potential at y = +1.00 mm on the line between the two point charges of Problem 3 above.
EQUATION USED (ONE EQUAL SIGN)
SOLUTION
ANSWER
=
5. Suppose we move along the +x-axis from xa = 0.0 m (where the potential is 770 V) to xb = 1.5 m. Along the xaxis in this region, the electric field has a magnitude given by (88 V/m4)x3 and makes an angle of 36.87˚ with the
+x-direction. Find the potential at xb = 1.5 m. SHOW ALL YOUR STEPS FOR FULL CREDIT.
EQUATION USED (ONE EQUAL SIGN)
SOLUTION
ANSWER
=