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CHEMISTRY 101 Dr. IsmailFasfous Textbook: Raymond Chang, 10th Edition Office Location: Chemistry Building, Room 212 Office Telephone: 4738 Email: [email protected] & [email protected] Website: http://staff.hu.edu.jo/ismailfasfous 1 Chemistry: The Study of Change Chapter 1 2 The Study of Chemistry Macroscopic We can see, touch and measure Microscopic We cannot without technology 1.2 Steps in the Scientific Method 1. Observations quantitative (water boils at 100 oC) qualitative (the sky is blue) 2. Formulating hypotheses a tentative explanation for the observation 3. Performing experiments gathering new information to decide whether the hypothesis is valid Copyright©2000 by Houghton Mifflin Company. All rights reserved. 4 1.3 Extensive and Intensive Properties An extensive property of a material depends upon how much matter is is being considered. • mass • length • volume An intensive property of a material does not depend upon how much matter is is being considered. • density • temperature • color Matter - anything that occupies space and has mass. mass – measure of the quantity of matter SI unit of mass is the kilogram (kg) 1 kg = 1000 g = 1 x 103 g Weight – force that gravity exerts on an object weight = c x mass A 1 kg bar will weigh on earth, c = 1.0 1 kg on earth on moon, c ~ 0.1 0.1 kg on moon 1.7 Measurement Measurement - quantitative observation consisting of 2 parts Part 1 - number Part 2 - scale (unit) Examples: 20 grams 6.63 Joule seconds Copyright©2000 by Houghton Mifflin Company. All rights reserved. 7 1.7 The Fundamental SI Units 8 9 Measurement of volume 1 L = 1000 mL = 1000 cm3 = 1 dm3 1 mL = 1 cm3 10 1.7 Common types of laboratory equipment used to measure liquid volume. 11 1.7 Density is the mass of substance per unit volume of the substance – SI derived unit for density is kg/m3 1 g/cm3 = 1 g/mL = 1000 kg/m3 density = mass volume m d= V 1.7 A piece of iron metal with a density of 7.87 g/cm3 has a volume of 5.94 cm3. What is its mass?0 m d= V m = d x V = 7.87 g/cm3 x 5.94 cm3 = 46.7 g A cubic piece of a silver metal measures 4.25 cm on each edge. If the density is 10.49 g/cm3, what is the mass of the cube? Mass = d.V. = (4.25cm)3 x 10.49 g/cm3 = 805 g 13 K = 0C + 273.15 273 K = 0 0C 373 K = 100 0C 0F = 9 x 0C + 32 5 32 0F = 0 0C 212 0F = 100 0C 1.7 Convert 172.9 0F to degrees Celsius. 9 = x 0C + 32 5 0F – 32 = 9 x 0C 5 0F 5 x (0F – 32) = 0C 9 0C = 5 x (0F – 32) 9 0C = 5 x (172.9 – 32) = 78.3 9 1.7 Uncertainty in Measurement A digit that must be estimated is called uncertain. A measurement always has some degree of uncertainty. 16 20.16ml 20.17ml 20.15ml 20.18ml ±0.01ml Figure : Measurement of volume using a buret. The volume is read at the bottom of the liquid curve (called the meniscus). 17 Precision and Accuracy Accuracy refers to the agreement of a particular value with the true value. Precision refers to the degree of agreement among several elements of the same quantity. 18 Precision and Accuracy accurate & precise precise but not accurate not accurate & not precise Rules for Counting Significant Figures Overview 1. Nonzero integers (1-9) 2. Zeros leading zeros, before (1-9) captive zeros, between (1-9) trailing zeros, after (1-9) 3. Exact numbers 20 Rules for Counting Significant Figures - Details Nonzero integers always count as significant figures. 3456 has 4 sig figs. 21 Rules for Counting Significant Figures - Details Zeros Leading zeros do not count as significant figures. 0.0486 has 3 sig figs. 22 Rules for Counting Significant Figures - Details Zeros Captive zeros always count as significant figures. 16.07 has 4 sig figs. 23 Rules for Counting Significant Figures - Details Zeros Trailing zeros are significant only if the number contains a decimal point. 9.300 has 4 sig figs. 24 Rules for Counting Significant Figures - Details Exact numbers have an infinite number of significant figures. Independent of measuring device: 1 apple, 10 students, 5 cars…. 2πr The 2 is exact and 4/3 π r2 the 4 and 3 are exact From Definition: 1 inch = 2.54 cm exactly The 1 and 2.54 do not limit the significant figures Average of certain values 7.64 + 7.68 + 7.70 = 7.67333 = 7.67 = 8 3 Because 3 is an exact number 25 Scientific Notation The number of atoms in 12 g of carbon: 602,200,000,000,000,000,000,000 6.022 x 1023 The mass of a single carbon atom in grams: 0.0000000000000000000000199 1.99 x 10-23 N x 10n N is a number between 1 and 10 n is a positive or negative integer 26 Scientific Notation 568.762 move decimal left n>0 568.762 = 5.68762 x 102 0.00000772 move decimal right n<0 0.00000772 = 7.72 x 10-6 Addition or Subtraction 1. Write each quantity with the same exponent n 2. Combine N1 and N2 3. The exponent, n, remains the same 4.31 x 104 + 3.9 x 103 = 4.31 x 104 + 0.39 x 104 = 4.70 x 104 27 Scientific Notation 100. has 3 sig. fig. = 1.00 x 102 100 has 1 sig. fig. = 1 x 102 28 Rules For Rounding 1. In a series of calculations, carry the extra digits through to the final result, then round. 2. If the digit to be removed: A. Is less than 5, then no change e.g. 1.33 rounded to 2 sig. fig = 1.3 B. Is equal or greater than 5, the preceding digit increase by 1 e.g. 1.36 rounded to 2 sig. fig = 1.4 29 Rules for Significant Figures in Mathematical Operations Multiplication and Division: # Sig figs in the result equals the number in the least precise measurement used in the calculation. 6.38 2.0 = 12.76 13 (2 sig figs) 30 Rules for Significant Figures in Mathematical Operations Multiplication and Division: 4.51 x 3.6666 = 16.536366= 16.5 3 sig figs round to 3 sig figs 6.8 ÷ 112.04 = 0.0606926= 0.061 2 sig figs round to 2 sig figs 31 Rules for Significant Figures in Mathematical Operations Addition and Subtraction: # decimal places in the result equals the number of decimal places in the least precise measurement. 6.8 + 11.934 = 18.734 18.7 (3 sig figs) 32 Rules for Significant Figures in Mathematical Operations Addition and Subtraction: 89.332 +1.1 90.432 3.70 -2.9133 0.7867 one significant figure after decimal point round off to 90.4 two significant figures after decimal point round off to 0.79 33 Practice Determine the number of significant figures in each of the following measured quantities? a)0.000387 m (3) b) 2.90x108 g (3) c) 905.040 cm (6) d) 6.065 L (4) 34 Practice Round off the following to three significant figures: a)264.89 m = 265 m b) 30 g = 30.0 g c) 3275 ml = 3.28 x 103 ml d) 2.2x10-5 mm = 2.20 x10-5 mm 35 Practice Perform the following calculations and round off the answer to the proper significant figures: 1. 1.25 m + 6.2 m – 8.01 m + 0.899 m = 0.3m 2. 78.8680 g/ (23.5ml + 10 ml) = 2.4g/ml 3. 50.0g x (11.9ml - 7 ml) = 245g/ml=200g/ml 4. 50.0g x (12.1ml-7ml)=255g/ml=300g/ml 36 Dimensional Analysis Method of Solving Problems Proper use of “unit factors” leads to proper units in your answer: 2.54 cm = 1 inch 1 inch/2.54 cm = 1 Unit factor What is the length in inch of 2.85 cm pencil 2.85 (cm) x 1 (inch)/2.54(cm) = 2.85/2.54 = 1.12 in 37 Dimensional Analysis Method of Solving Problems 1. Determine which unit conversion factor(s) are needed 2. Carry units through calculation 3. If all units cancel except for the desired unit(s), then the problem was solved correctly. How many mL are in 1.63 L? 1 L = 1000 mL 1000 mL 1.63 L x = 1630 mL 1L 2 1L L 1.63 L x = 0.001630 1000 mL mL 38 Practice Perform the following conversions: a)0.0033 mm to nm (0.0033mm)(1m/1000mm)(109 nm/1m) = 3300nm b) 0.67 pm to cm (0.67pm)(1m/ 1012 pm)(100cm/1m) = 6.7 x10-11 cm c) 4.60x10-6 kg/L to mg/ ml (4.60x10-6kg/L)(1000g/1kg)(1000mg/1g)(1L/1000ml) = 4.60 x 10-3 mg/ml 39 Practice The speed of sound in water is about 1482 m/s. What is this speed in miles per hour? conversion units meters to miles seconds to hours 1 mi = 1609 m 1 min = 60 s 1 hour = 60 min 1 mi 60 s 60 min m mi x x 1482 s x = 3316 hour 1609 m 1 min 1 hour 1.9 Practice Convert the density 0.808 g/cm3 to units of kg/m3? conversion units 1 kg = 1000g 1 cm3 = 1 x 10-6 m3 g 1 kg 1 cm3 kg x 0.808 cm3x = 808 3 -6 3 m 1000 g 1x10 m