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Dept. of Education and Science – Physics Higher Level - 2002. Question 8. Define (i) power, (ii) resistivity. Describe an experiment that demonstrates the heating effect of an electric current. The ESB supplies electrical energy at a rate of 2 MW to an industrial park from a local power station, whose output voltage is 10 kV. The total length of the cables connecting the industrial park to the power station is 15 km. The cables have a diameter of 10 mm and are made from a material of resistivity 5.0 × 10–8 . m. (i) the total resistance of the cables (ii) the current flowing in the cables; (iii) the rate at which energy is “lost” in the cables. Suggest a method of reducing the energy “lost” in the cables. __________________________________________________ Define (i) power, (ii) resistivity. Power is the rate at which work is done or at which energy is converted. Its is measured in Watts (W) where 1 W = 1Js -1 . The resistivity of a substance is the resistance of a piece of unit length and unit cross-section area of the substance. ρ= RA . It is measured in Ωm. l Describe an experiment that demonstrates the heating effect of an electric current. + 12 V - Steel wool strand Starting from V = 0, increase the voltage across the strand of steel wool. As the current increases the strand will start to warm and eventually glow and then snap. Calculate (i) R= (ii) the total resistance of the cables; ρl 5 .0 x10 −8 x15 ,000 = = 9. 5Ω A πx( 5.0 x10 −3 ) 2 the current flowing in the cables; W = VI ⇒ I = (iii) W 2 x10 6 = = 200 A V 1x10 4 the rate at which energy is “lost” in the cables. P = RI 2 = 9 .5 x200 2 = 3. 8 x10 5W Suggest a method of reducing the energy “lost” in the cables. Increasing the transmission voltage or using thicker cables would reduce energy loss.