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Math 1314 Section1.7 Notes Absolute Value Equations and Inequalities Interval Notations Absolute Value Equations Recall: Definition: The absolute value of x denoted |x| and read “Absolute value of x” is defined as follow: if x 0 x x if x 0 x Remark: Absolute value of x is also considered the distance from zero to x on the real number line. Examples: If x = 7 then | x | = | 7 | = 7. If x = - 7 then | x | = | -7 | = 7. The opposite numbers have the same absolute value i.e. | x | = | -x |. If | y | = 7 then y = 7 or y = - 7. Absolute value of a real number is nonnegative or | x | ≥ 0 where x is a real number. Absolute Value Equations. | A | = B and | A | = | B | where A and B are algebraic expressions. Formulas: Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) A B and B 0 then A B or A - B A B and B 0 No solutions A B A B or A - B Steps for Solving Absolute Value Equations | A | = B. 1. Isolate the absolute value expression. 2. There are two special cases: - If B < 0 --- NO solution. - If B ≥ 0, remove the absolute value sign by writing as 2 equations A = B or A = - B. 3. Solve for the variable. Examples: Sole the following equations. 1. | x – 4 | = 9 2. | 4x + 1 | + 5 = 6 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) 3. | 3x + 8 | = – 3 4. 3| 3x + 8 | + 2 = 8 5. 4| x – 2 | + 7 = 3 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) 6. 15 – |2x – 3| = 7 7. | 2x + 5 | = | x + 4| Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) Absolute Value Inequalities: Formulas: For B is positive. A B A B or A B A B B A B A B all real numbers or S , A B no solution or S For B is zero A 0 all real numbers or S , A 0 A 0 or all real numbers except A 0 A 0 A0 A 0 no solution or S Examples: Solve the following inequalities. Graph the solutions on the number line and write the solutions set in interval notation. 1. x 2 -2 0 2 Closer: that means the distance from zero to x is either LESS THANor EQUAL to 2 units. -2 ≤ x ≤ 2 (Compound inequality) Thus S = [-2, 2] 2. x 5 Further away: that means the distance from zero to x is GREATER THAN 5 units. x < -5(to the left) x > 5 (to the right) Thus S = (-∞, -5) U ( 5, ∞) . Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) 3. x 8 4. x 11 5. 3 x 12 6. 2x 1 7 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) 7. 3x 2 3 9 8. 3 9 5 x 5 8 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) 9. 2 3x 5 5 7 10. 3 x 2 0 11. 3 x 7 0 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/) 12. 5 x 1 4 4 13. 5 3 4 x 1 5 14. x 5 7 Print to PDF without this message by purchasing novaPDF (http://www.novapdf.com/)