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Circular motion For uniform circular motion the ACCELERATION is directed toward the center of the circle at all times. The magnitude of the radial acceleration is given by Dynamics of circular motion For uniform circular motion the NET FORCE is directed toward the center of the circle at all times. The net force in the radial direction is given by When a ball on the end of a string swings in a vertical circle with uniform circular motion, the ball is accelerating because A. B. C. D. the speed is changing. the direction is changing. the speed and the direction are changing. the ball is not accelerating. When a ball on the end of a string is swung in a vertical circle with uniform motion: What is the direction of the acceleration of the ball? A. B. Tangent to the circle, in the direction of the ball’s motion Toward the center of the circle For the ball on the end of a string moving in a vertical circle: What force is producing the centripetal acceleration of the ball? A. B. C. D. gravity air resistance normal force tension in the string For the ball on the end of a string moving in a vertical circle: What is the direction of the net force on the ball? A. tangent to the circle B. toward the center of the circle C. there is no net force A 0.150 kg ball on the end of a 1.10 m long, lightweight cord is swung in a vertical circle. Determine the minimum speed the ball must have at the top of its arc so that the ball continues moving in a circle. Circular motion and vehicles The road exerts an inward force (friction against the tires) on a car to make it move in a circle. The car exerts an inward force on the passenger. When a car turns a corner on a level road, which force provides the necessary centripetal acceleration? A. B. C. D. E. Friction Tension Normal force Air resistance Gravity A coin sits on a rotating turntable. 1. At the time shown in the figure, which arrow gives the direction of the coin’s velocity? Additional Questions A coin sits on a rotating turntable. 2. At the time shown in the figure, which arrow gives the direction of the frictional force on the coin? Additional Questions A coin sits on a rotating turntable. 3. At the instant shown, suppose the frictional force disappeared. In what direction would the coin move? When the ball reaches the break in the circle, which path will it follow? A 1000 kg car rounds a curve on a flat road of radius 50 m at a speed of 15 m/s. (a) Will the car skid when the pavement is dry and the coefficient of static friction is 0.60? (b) Will the car skid when the pavement is slick and the coefficient of static friction is 0.25? A ball is rolled along the inside of a partial cardboard hoop lying flat on a table. Which path will the ball follow when it gets to the end of the hoop? A car is rolling over the top of a hill at speed v. At this instant, A. n > w. B. n < w. C. n = w. D.We can’t tell about n without knowing v. A car of mass 1500 kg goes over a hill at a speed of 20 m/s. The shape of the hill is approximately circular, with a radius of 60 m, as in the figure at right. When the car is at the highest point of the hill, a. What is the force of gravity on the car? b. What is the normal force of the road on the car at this point? A rider in a “gravitron” finds herself stuck with her back to the wall. Which diagram correctly shows the forces acting on her? Newton’s Law of Universal Gravitation Every particle in the universe attracts every other particle with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between them. This force acts along the line joining the two particles. The magnitude of the gravitational force is given by Where and are the masses of the two particles, is the distance between them, and G is a gravitational constant. Acceleration due to gravity at the surface of Earth • We substitute in the known values below Earth • 2RE The value for the acceleration due to gravity decreases as we move further from the surface of the Earth. RE Newton’s Law of Universal Gravitation How do the gravities compare (assuming equal masses)? 1. FA = FB 2. FA = 2 FB 3. FA = 4FB 4. 2 FA = FB 5. 4 FA = FB Earth A B 2RE RE Newton’s law of gravity describes the gravitational force between A. B. C. D. E. the earth and the moon. a person and the earth. the earth and the sun. the sun and the planets. all of the above. A 60 kg person stands on each of the following planets. Rank order her weight on the three bodies, from highest to lowest. A. B. C. D. E. A> B>C B>A>C B>C>A C>B>A C>A>B Calculate the acceleration due to gravity on the Moon, which has a radius of 1.74×106 m and a mass of 7.35×1022 kg. Geosynchronous orbit A satellite is in geosynchronous orbit. Geosynchronous orbit is when the satellite orbits at a radius that allows the period of orbit to be 1 day (24 hrs). - Remember that centripetal acceleration is - The magnitude of the force is which gives - Newtons law of gravity is - Determine the sum of the forces, - The only acceleration is , so A - We know the circumference of a circle and that constant velocity, therefore is a B - Find the radius of orbit by plugging in B into A and solving for radius of geosynchronous orbit, where gives the According to Newton’s law of gravity, if the Earth’s mass were suddenly doubled, with its distance to the sun and its speed relative to the sun unchanged, what would happen to its orbit? 1. 2. 3. 4. It would fly off to the stars It would spiral into the sun It would just say ho hum (nothing changes). We don’t know without more information. A satellite orbits the earth. A Space Shuttle crew is sent to boost the satellite into a higher orbit. Which of these quantities increases? A. B. C. D. E. Speed Angular speed Period Centripetal acceleration Gravitational force of the earth The Moon does not fall to Earth because A. It is in Earth’s gravitational field. B. The net force on it is zero. C. It is beyond the main pull of Earth’s gravity. D. It is being pulled by the Sun and planets as well as by Earth. E. none of the above F. all of the above Kepler’s Laws 1. The orbits of planets are ellipses; and the center of sun is at one focus 2. The radius vector sweeps out equal areas in equal time 3. The period T is proportional to the mean radius to the 3/2 power