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Transcript
Algebra I
Lesson 7.1
Multiplication Properties of Exponents
Multiply Monomials A monomial is a number, a variable, or the product of a number and one
or more variables with nonnegative integer exponents. It has one term. A constant is a
monomial that is a real number.
Example 1: Identify Monomials
Determine whether each expression is a monomial. Write yes or no. Explain your
reasoning.
a. 4
b. X + 6
c. 3x2
d. y
An expression of the form π‘₯ 𝑛 is called a power and represents the product you obtain when x is
used as a factor n times. To multiply two powers that have the same base, add the
exponents.
Product of Powers
For any number a and all integers m and n,
π‘Žπ‘š β‹… π‘Žπ‘› = π‘Žπ‘š+𝑛 .
Example 2: Simplify (–4π’‚πŸ‘ b)(3π’‚πŸ π’ƒπŸ“ ).
(–4π‘Ž3 b)(3π‘Ž2 𝑏 5 ) = (–4)(3)( π‘Ž3 β‹… π‘Ž2 )(b β‹… 𝑏 5 )
= –12(π‘Ž3 + 2 )(𝑏1 + 5 )
= –12π‘Ž5 𝑏 6
The product is –12π‘Ž5 𝑏 6 .
Try these:
a. (–5xy)(4π‘₯ 2 )(𝑦 4 )
c.
(–4π‘₯ 3 )(–5π‘₯ 7 )
b. (10π‘₯ 3 y𝑧 2 )(–2x𝑦 5 z)
d. (–π‘₯ 3 )(– π‘₯ 4 )
An expression of the form (π‘₯ π‘š )𝑛 is called a power of a power and represents the product you
obtain when π‘₯ π‘š is used as a factor n times. To find the power of a power, multiply
exponents.
Power of a
Power
For any number a and any integers m and p,
(π‘Žπ‘š )𝑝 = π‘Žπ‘šπ‘ .
Example 3: Simplify:
(x3)4
(y5)3
(2)3(x5)7
An expression in the form of (xy)m is called the power of a product. To find the power of a
product, find the power of each factor and multiply.
Power of a
Product
For any numbers a and b and any integer m,
(π‘Žπ‘)π‘š = π‘Žπ‘š 𝑏 π‘š .
We can combine and use these properties to simplify expressions involving monomials.
Example 4: Simplify (βˆ’πŸπ’‚π’ƒπŸ )πŸ‘(π’‚πŸ )4.
(βˆ’2π‘Žπ‘ 2 )3 (π‘Ž2 )4 = (βˆ’2π‘Žπ‘ 2 )3 (π‘Ž8 )
Power of a Power
= (βˆ’2)3 (π‘Ž3 ) ( 𝑏2 )3 (π‘Ž8 )
Power of a Product
= (βˆ’2)3 (π‘Ž3 )( π‘Ž8 ) ( 𝑏2 )3
= (βˆ’2)3 (π‘Ž11 ) ( 𝑏 2 )3
= –8π‘Ž11 𝑏 6
Group the coefficients and the variables
Product of Powers
Power of a Power
The product is –8π‘Ž11 𝑏 6 .
Try these:
A. (βˆ’3π‘Žπ‘ 4 )3
𝐛.
(π‘₯ 2 𝑦 4 )5
𝐜. (2π‘Ž3 𝑏 2 )( 𝑏3 )2
Simplifying Monomial Expressions: To simplify a monomial expression, write an equivalent
expression in which:
β€’ Each variable base appears exactly once
β€’ There are no powers of powers, and
β€’ All fractions are in simplest form
Example 5: Simplify:
a. (–3π‘Ž3 𝑛4 )(βˆ’3π‘Ž3 𝑛)4
b. –3(2π‘₯)4 (4π‘₯ 5 𝑦)2
c. (2π‘₯𝑦)2 (–3π‘₯ 2 )(4𝑦 4 )
Algebra 1
Lesson 7.2
Division Properties of Exponents
We can use principles for reducing fractions to find quotients of monomials like 67/62
67
62
Divide Monomials To divide two powers with the same base, subtract the exponents.
For all integers m and n and any nonzero number a,
π‘Žπ‘š βˆ’ 𝑛 .
Quotient of Powers
Example 1: Simplify
π‘Ž4 𝑏7
π‘Žπ‘2
π‘Ž4
𝑏7
= οΏ½ οΏ½ οΏ½ 2οΏ½
π‘Ž
𝑏
= (π‘Ž4 βˆ’ 1 )( 𝑏 7 βˆ’ 2 )
= a3b5
π’‚πŸ’ π’ƒπŸ•
π’‚π’ƒπŸ
. Assume that no denominator equals zero.
Group powers with the same base.
Quotient of Powers
Simplify.
The quotient is π‘Ž3 𝑏 5
Try these:
a.
c.
𝑝5 𝑛 4
𝑝2 𝑛
π‘₯5𝑦3
π‘₯5𝑦2
b.
π‘Ž2
d.
βˆ’2y7
π‘Ž
14y5
π‘Žπ‘š
π‘Žπ‘›
=
To find the power of a quotient, find the power of the numerator and the power of the
denominator.
Power of a Quotient
πŸπ’‚πŸ‘ π’ƒπŸ“
Example 2: Simplify οΏ½
2π‘Ž3 𝑏5
οΏ½
3𝑏2
3
οΏ½ =
=
=
=
οΏ½2π‘Ž3 𝑏5 οΏ½
(3𝑏2 )3
3
23 (π‘Ž3) (𝑏5)
(3)3 (𝑏2)
8π‘Ž9 𝑏15
8π‘Ž9 𝑏9
27
2π‘Ž2 𝑏
π‘Ž
4𝑝4 π‘Ÿ 4
The quotient is
3
οΏ½
3
οΏ½
3𝑝2 π‘Ÿ 2
b. οΏ½
3
3
27𝑏6
Try these:
a. οΏ½
3
πŸ‘π’ƒπŸ
For any integer m and any real numbers a and b, b β‰  0,
π‘Ž π‘š
π‘Žπ‘š
�𝑏 οΏ½ = π‘Ž π‘š .
πŸ‘
οΏ½ . Assume that no denominator equals zero.
Power of a Quotient
Power of a Product
Power of a Power
Quotient of Powers
8π‘Ž9 𝑏9
27
Negative Exponents: Any nonzero number raised to the zero power is 1; for example,
(βˆ’0.5)0 = 1. Any nonzero number raised to a negative power is equal to the reciprocal of
the number raised to the opposite power; for example,
1
6βˆ’3 = 3 . These definitions can be used to simplify expressions that have negative exponents..
6
Zero Exponent
Negative
Exponent
Property
For any nonzero number a, π‘Ž0 = 1.
For any nonzero number a and any integer n,
π‘Žβˆ’π‘› =
1
π‘Žπ‘›
n and
1
π‘Žβˆ’π‘›
= π‘Žπ‘› .
The simplified form of an expression containing negative exponents must contain only positive
exponents.
22
b.
c.
π‘βˆ’8
d.
π‘βˆ’4
e.
(π‘Ž2 𝑏3 )2
f.
π‘₯4𝑦0
g.
(6π‘Ž βˆ’1 𝑏)2
a.
2βˆ’3
𝑝3
(π‘Žπ‘)βˆ’2
(𝑏2 )4
π‘š
π‘šβˆ’4
π‘βˆ’5
π‘₯ βˆ’2
4π‘š2 𝑛2
h. οΏ½
8π‘šβˆ’1 β„“
0
οΏ½
Real world example: Order of Magnitude: Darin has $123,456 in his savings account. Tabo
has $156 in his savings account. Determine the order of magnitude of Darin’s account and
Tabo’s account. How many orders of magnitude as great is Darin’s account as Tabo’s account?
Round each number to the nearest power of ten. Then find the ratio of the amount in Darin’s account to the amount in
Tabo’s account.
Algebra 1 Lesson 7.3
Rational Exponents
Rational Exponents For any real numbers a and b and any positive integer n, if π‘Žπ‘› = b, then a
is an nth root of b. Rational exponents can be used to represent nth roots.
Square
Root
1
Cube Root
1
3
𝑏 3 = βˆšπ‘
1
𝑛
𝑏 n = βˆšπ‘
nth Root
𝟏
𝟐
𝑏 2 = βˆšπ‘
Example 1: Write (πŸ”π’™π’š) in radical form.
1
2
(6π‘₯𝑦) = οΏ½6π‘₯𝑦
Definition of b
1
2
𝟏
Example 2: Simplify πŸ”πŸπŸ“πŸ’ .
1
4
6254 = √625
4
= √5 β‹… 5 β‹… 5 β‹… 5
=5
1
𝑛
𝑏 𝑛 = βˆšπ‘
625 = 54
Simplify
Write each expression in radical form, or write each radical in exponential form.
1
1
a. 5π‘₯ 2
1
d. 19π‘Žπ‘ 2
1
3
g. 512
b. 17𝑦 2
e. √17
4
h. √2401
1
c. 122
f. √12𝑛
6
i. √64
For any positive real number b and any integers m and n > 1,
π‘š
π‘š
𝑛
𝑏 𝑛 = οΏ½ βˆšπ‘οΏ½ or
2
Example: 83 =
Examples:
2
3
2
�√8 �
𝑛
βˆšπ‘ π‘š
= 22 or 4
2
5
a. 325
b. 812
c. 273
3
d. 812
Solve Exponential Equations: In an exponential equation, variables occur as exponents.
Use the Power Property of Equality and the other properties of exponents to solve exponential
equations.
The Power Property of Equality states for any real number b > 0, and b β‰  1,
bx = by if and only if x = y.
Example: If 8x = 85 , then x = 5.
1
If p = 1/3, then 5p = 53
Example: Solve πŸπŸŽπŸπŸ’π’™βˆ’πŸ = 4.
1024π‘₯βˆ’1 = 4
(45 )π‘₯βˆ’1 = 4
45π‘₯βˆ’5 = 41
5x βˆ’ 5 = 1
5x = 6
x=
6
5
Original equation
Rewrite 1024 as 45 .
Power of a Power, Distributive Property
Power Property of Equality
Add 5 to each side.
Divide each side by 5.
Examples:
a. 2π‘₯ = 128
b. 33π‘₯ + 1 = 81
c. 4π‘₯ βˆ’ 3 = 32
d. 5π‘₯ = 15,625
The population p of a culture that begins with 40 bacteria and doubles every 8 hours can be
𝑑
modeled by p = 40(2)8 , where t is time in hours. Find t if p = 20,480.
Algebra 1
Lesson 7.4
Scientific Notation
Scientific Notation Very large and very small numbers are often best represented using a
method known as scientific notation. Numbers written in scientific notation take the form
a × 10𝑛 , where 1 ≀ a < 10 and n is an integer. Any number can be written in scientific notation.
Example 1: Express 34,020,000,000 in scientific notation.
Step 1 Move the decimal point until it is to the right of the first nonzero digit. The result is a real number a. Here, a =
3.402.
Step 2 Note the number of places n and the direction that you moved the decimal point. The decimal point moved 10
places to the left, so n = 10.
Step 3 Because the decimal moved to the left, write the number as a × 10𝑛 .
34,020,000,000 = 3.4020000000 × 1010
Step 4 Remove the extra zeros. 3.402 × 1010
Example 2: Express 4.11 × πŸπŸŽβˆ’πŸ” in standard notation.
Step 1 The exponent is –6, so n = –6.
Step 2 Because n < 0, move the decimal point 6 places to the left.
4.11 × 10βˆ’6 β‡’ .00000411
Step 3 4.11 × 10βˆ’6 β‡’ 0.00000411
Rewrite; insert a 0 before the decimal point.
Try these:
Express each number in scientific notation.
a. 5,100,000
b. 80,300,000,000
c. 0.000301
d. 0.0000000519
Products and Quotients in Scientific Notation You can use scientific notation to simplify
multiplying and dividing very large and very small numbers.
Example 3: Evaluate (9.2 × πŸπŸŽβˆ’πŸ‘) × (4 × πŸπŸŽπŸ–). Express the result in both scientific notation and standard form.
(9.2 × 10βˆ’3)(4 × 108 )
= (9.2 × 4)( 10
= 36.8 × 105
βˆ’3
Original expression
8
× 10 )
= (3.68 × 101 ) × 105
Product of Powers
36.8 = 3.68 × 10
= 3.68 × 106
Product of Powers
= 3,680,000
Standard Form
Example 4: Evaluate
(2.76 × 107 )
(6.9 × 105 )
Commutative and Associative Properties
(𝟐.πŸ•πŸ” × πŸπŸŽπŸ• )
(πŸ”.πŸ— × πŸπŸŽπŸ“ )
2.76
107
οΏ½ οΏ½105 οΏ½
6.9
=οΏ½
= 0.4 × 102
βˆ’1
= 4.0 × 10 × 10
= 4.0 × 101
. Express the result in both scientific notation and standard form.
Product rule for fractions
Quotient of Powers
2
= 40
0.4 = 4.0 × 10
--1
Product of Powers
Standard
Try these: Evaluate each product or quotient. Express the results in both scientific
notation and standard form.
1. (3.4 × 103 )(5 × 104 )
7.
(4.9 × 10βˆ’3 )
9.
(1.6 × 105 )
(2.5 × 10βˆ’4 )
(4 × 10βˆ’4 )
3. (6.7 × 10βˆ’7 )(3 × 103 )
8.
5.8 × 104
5 × 10βˆ’2
5. (1.2 × 10βˆ’4 )2
Example 5: Watercraft: Last year Molly’s state registered over 400 thousand watercraft.
Boat sales in her state generated more than $15.4 million in state sales taxes that same year.
a. Express the number of watercraft registered and the state sales tax generated from boat
sales last year in Molly’s state in standard notation.
b. Write each number in scientific notation.
c. How many watercraft have been registered in Molly’s state if 12 times the number
registered last year have been registered in all? Write your answer in scientific notation
and in standard form.
Algebra 1
Lesson 7.5
Exponential Functions
Graph Exponential Functions
Exponential
Function
a function defined by an equation of the form y = a𝑏 π‘₯ , where a β‰ 
0, b > 0, and b β‰  1
You can use values of x to find ordered pairs that satisfy an exponential function. Then you can
use the ordered pairs to graph the function.
Example: Graph y = πŸ‘π’™ . Find the y-intercept and state the domain and range.
x
y
–2
1
9
–1
1
0
1
1
3
2
9
3
The y-intercept is 1.
The domain is all real numbers, and the range is all positive numbers.
Graph each function. Find the y-intercept and state the domain and range.
a. y = 0.3x
1 π‘₯
b. y = οΏ½ οΏ½ + 1
3
Identify Exponential Behavior It is sometimes useful to know if a set of data is exponential.
One way to tell is to observe the shape of the graph. Another way is to observe the pattern in the
set of data.
Example : Determine whether the set of data shown below displays exponential behavior.
Write yes or no. Explain why or why not.
x
0
2
4
6
8 10
y 64 32 16 8
4
2
Method 1: Look for a Pattern
1
The domain values increase by regular intervals of 2, while the range values have a common factor of . Since the domain
2
values increase by regular intervals and the range values have a common factor, the data are probably exponential.
Method 2: Graph the Data
The graph shows rapidly decreasing values of
y as x increases. This is characteristic of exponential
behavior.
Determine whether the set of data shown below displays exponential behavior. Write yes
or no. Explain why or why not.
x 0
1
2
3
x 0
1
y 5 10 15 20
y 3
9 27 81
2
3
Example: Some people say that the value of a new care decreases as soon as it is
driven off the lot. The function V = 25,000 (0.82)t models the depreciation in
the value of a new care that originally cost $25,000. V represents the value of the
care and t represents the time in years from the time of purchase.
a. Graph the function. What values of V and t are meaningful in the context of
the problem?
b. What is the car’s value after 5 years?
Algebra 1
Lesson 7.6
Growth and Decay
Exponential Growth Population increases and growth of monetary investments are examples of
exponential growth. This means that an initial amount increases at a steady rate over time.
The general equation for exponential growth is y = a(1 + π‘Ÿ )𝑑 .
β€’ y represents the final amount.
β€’ a represents the initial amount.
β€’ r represents the rate of change expressed as a decimal.
β€’ t represents time.
Exponential Growth
Example 1: POPULATION The population of the United States has been increasing at an
average rate of 0.91%. If the population was about 303,146,000 in 2008, predict the population
in 2012.
Example 2: INVESTMENT The Garcias have $12,000 in a savings account. The bank pays
3.5% interest on savings accounts, compounded monthly. Find the balance in 3 years.
The rate 3.5% can be written as 0.035. The special equation for compound interest is
𝒓 𝒏𝒕
A = P �𝟏 + 𝒏� , where A represents the balance, P is the initial amount, r represents the annual
rate expressed as a decimal, n represents the number of times the interest is compounded each
year, and t represents the number
of years the money is invested.
π‘Ÿ
A = P (1 + 𝑛)𝑛𝑑
= 12,000 οΏ½1 +
β‰ˆ 13,326.49
0.035 3(12)
12
οΏ½
In three years, the balance of the account
will be $13,326.49.
INVESTMENT Determine the value of an investment of $2500 if it is invested at an interest
rate of 5.25% compounded monthly for 4 years.
Exponential Decay
The general equation for exponential decay is y = a(1 βˆ’ π‘Ÿ)𝑑 .
β€’ y represents the final amount.
β€’ a represents the initial amount.
β€’ r represents the rate of decay expressed as a decimal.
β€’ t represents time.
DEPRECIATION Mr. Gossell is a machinist. He bought some new machinery for about
$125,000. He wants to calculate the value of the machinery over the next 10 years for tax
purposes. If the machinery depreciates at the rate of 15% per year, what is the value of the
machinery (to the nearest $100) at the end of 10 years?
DEPRECIATION A new car costs $32,000. It is expected to depreciate 12% each year for 4
years and then depreciate 8% each year thereafter. Find the value of the car in 6 years.