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AP Physics End Slide Current (I) • The rate at which charge is flowing through a circuit • Units = Coulombs/sec = Amperes (A) • Since each electron has a specifically set amount of charge, you can think of current as the number of electrons that pass a single point (but not how fast an electron is moving) End Slide Current (cont.) • Each electron does not move from beginning to end at the rate of electricity; the speed of the electricity is actually a measure of how fast the energy is moving • Example with Newton’s Cradle End Slide Junction Rule • Kirchhoff’s 1st Law: Junction Rule – Current is conserved in a circuit 𝑰𝟐 𝑰𝟏 𝑰𝟐 𝑰𝟏 𝑰𝟑 𝑰𝟏 = 𝑰𝟐 𝑰𝟏 = 𝑰𝟐 + 𝑰𝟑 End Slide Voltage (V) • The average amount of Potential Energy per unit of charge in a circuit • Unit = Joules/Coulomb = Volts (V) • Also called “potential difference” End Slide Voltage (cont.) • Again, since each electron has a specifically set amount of charge, you can think of voltage as the amount of energy per electron • This energy is caused by the negative end of the battery pushing the charge out and the positive end pulling it in • Since the voltage difference between the positive and negative ends of a 9-V battery is 9 Volts, then the electrons will use 9 Volts to get from the negative to positive ends End Slide Resistance (R) • The amount in which flow is hindered • Units = Ohms (W) End Slide Flow of Electricity • Superconductors – allow electricity to pass through very easily. • Conductors – allow most electricity to pass through easily. • Semiconductors – allow only some electricity to pass through. • Insulators – allow little or no electricity to pass through. End Slide Ohm’s Law • Current is the balance between Voltage forcing the flow and Resistance hindering the flow • What will Voltage do to Current? • What will Resistance do to Current? V I= V R more commonly written as V = IR End Slide Ohm’s Law • Suppose a 9.0 V battery was lighting a bulb with a resistance of 3.0 W. What is the current? I = V = 9.0 V = 3.0 A R 3.0 W End Slide Ohm’s Law • Suppose a 3.5 V power source produced a current of 0.50 A through a resistor. What is the resistance? R = V = 3.5 V = 7.0 W I 0.50 A End Slide Ohm’s Law • Suppose a 2.5 W resistor has a current of 1.5 A through it. How much voltage is the resistor using? V = IR = (2.5 W) (1.5 A) = 3.75 V End Slide Loop Rule • Kirchhoff’s 2nd Law: Loop Rule – Energy is conserved in a circuit Voltage Supply 𝑹𝟏 𝑹𝟐 Voltage (V) 𝑹𝟑 𝑹𝟏 Voltage Supply 𝑹𝟐 𝑹𝟑 Measuring Current & Voltage End Slide • Current is measured in Series with an Ammeter • Voltage is measured in Parallel with a Voltmeter A 𝑹𝟏 𝑽 𝑹𝟑 𝑹𝟐 V End Slide Power Power – the rate at which energy is used P = IV C/ sec * J/C = J/sec With a light bulb, this relates to how bright it shines (a.k.a. Wattage). End Slide Power • What is the current through a 60Watt light bulb if your house receives 120 Volts? P = IV 60 W = I * (120 V) I = 60 W/120 V = 0.50 A End Slide Power • Why is a light bulb with more resistance brighter when in series with a bulb of less resistance? P = IV P = I2 R V = IR Since current is the same through a series circuit, higher resistance means more power; thus, brighter. End Slide Equations for Circuits Series 𝑽𝑻𝒐𝒕 = 𝑽𝟏 + 𝑽𝟐 + 𝑽𝟑 + ⋯ 𝑰𝑻𝒐𝒕 = 𝑰𝟏 = 𝑰𝟐 = 𝑰𝟑 = ⋯ 𝑹𝑻𝒐𝒕 = 𝑹𝟏 + 𝑹𝟐 + 𝑹𝟑 + ⋯ Parallel 𝑽𝑻𝒐𝒕 = 𝑽𝟏 = 𝑽𝟐 = 𝑽𝟑 = ⋯ 𝑰𝑻𝒐𝒕 = 𝑰𝟏 + 𝑰𝟐 + 𝑰𝟑 + ⋯ 𝟏 𝟏 𝟏 𝟏 = + + +⋯ 𝑹𝑻𝒐𝒕 𝑹𝟏 𝑹𝟐 𝑹𝟑