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polynomials polynomials Distributive Law MPM2D: Principles of Mathematics Recap Expand and simplify 2x(x 2 − 4x + 5). Factoring Polynomials 2x(x 2 − 4x + 5) = 2x · x 2 − 2x · 4x + 2x · 5 Part 1: Common Factoring = 2x 3 − 8x 2 + 10x J. Garvin J. Garvin — Factoring Polynomials Slide 2/11 Slide 1/11 polynomials polynomials Common Factoring Common Factoring Recall that the Greatest Common Factor (GCF) of two or more numbers is the greatest value that divides evenly into those numbers. Consider the polynomial expression 6x + 15. For example, the GCF of 6 and 9 is 3, since both 6 and 9 are divisible by 3, but not by a greater number. Similarly, the GCF of x 3 and x 5 is x 3 , since x 3 is divisible by x5 x 3 (obviously), as is x 5 : 3 = x 2 . x The process of rewriting a polynomial expression as a product of two or more factors is called factoring. To rewrite the expression in factored form, express it as a product of 3 and some other polynomial. This polynomial is determined by dividing each term by the GCF. 6x 15 6x + 15 = 3 + 3 3 = 3(2x + 5) If a factor is common to all terms, then we can common factor the expression. Note that the common factor is never discarded. It remains as part of the factored expression. The GCF of both 6x and 15 is 3, since both 6x and 15 are evenly divisible by 3, but not by a greater number. The Distributive Law can be used to validate the solution. J. Garvin — Factoring Polynomials Slide 3/11 J. Garvin — Factoring Polynomials Slide 4/11 polynomials polynomials Common Factoring Common Factoring Example A common factor must apply to all terms in a polynomial expression. Factor 8x − 12. The GCF of 8x and −12 is 4, so the factored expression will be the product of 4 and another polynomial. 8x 12 8x − 12 = 4 − 4 4 = 4(2x − 3) Again, note that the common factor, 4, remains as part of the factored expression. J. Garvin — Factoring Polynomials Slide 5/11 Example Factor 3x 2 − 15x + 21. The GCF of 3x 2 , −15x and 21 is 3, so the factored expression will be the product of 3 and another polynomial. 2 3x 15x 21 3x 2 − 15x + 21 = 3 − + 3 3 3 = 3(x 2 − 5x + 7) J. Garvin — Factoring Polynomials Slide 6/11 polynomials polynomials Common Factoring Common Factoring Sometimes it is possible to factor a variable from each term of a polynomial. In other cases, both a variable and a constant make up the GCF. Example Example Factor 5x 3 − 2x 2 Factor 15x 4 + 25x 3 − 30x. + 3x. The GCF of the three terms is x, so the factored expression will be the product of x and another polynomial. 3 5x 2x 2 3x 5x 3 − 2x 2 + 3x = x − + x x x The GCF of the three terms is 5x. Note that only a single x can be factored, since the exponent on the last term is 1. 15x 4 25x 3 30x + − 15x 4 + 25x 3 − 30x = 5x 5x 5x 5x J. Garvin — Factoring Polynomials Slide 7/11 J. Garvin — Factoring Polynomials Slide 8/11 = x(5x 2 − 2x + 3) = 5x(3x 3 + 5x 2 − 6) polynomials polynomials Common Factoring Common Factoring Expressions involving multiple variables can be handled in the same way. Example Example The GCF of the three terms is 1. Therefore, the expression cannot be common factored. Factor 16x 3 y 2 + 24x 5 y 2 . While it is not always possible to find a common factor for the three terms, there are other ways in which polynomials like the one above can be factored. The GCF of the two terms is 8x 3 y 2 . Again, the factor is limited by the lowest exponent on a given variable. 16x 3 y 2 24x 5 y 2 16x 3 y 2 + 24x 5 y 2 = 8x 3 y 2 + 3 2 3 2 8x y 8x y For example, note that the expression can be factored as (2x − 1)(x + 3) = 2x 2 + 6x − x − 3 = 2x 2 + 5x − 3. = 8x 3 y 2 (2 + 3x 2 ) Note that there are no terms containing y inside of the brackets, since y 2 was completely factored out of all terms. J. Garvin — Factoring Polynomials Slide 9/11 J. Garvin — Factoring Polynomials Slide 11/11 We will explore some of these other methods over the next few lessons. J. Garvin — Factoring Polynomials Slide 10/11 polynomials Questions? Factor 2x 2 + 5x − 3.