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Quiz Three Calculus A Professor D. Olles Name: There is partial credit awarded for incorrect answes on the multiple choice questions. No formula sheets or calculators are allowed. You have 10 minutes to complete this quiz. Question: 1 2 3 Total Points: 6 2 12 20 Score: 1. Use the given graph of f to state the value of each quantity, if it exists. If it does not, explain why. (a) limx→1 f (x) = 2 (b) limx→3 f (x) DNE The graph of the function does not approach any ONE y-value, in particular, as x approaches 3. From the left, the function approaches 1 and from the right, the function approaches 4. (c) f (3) = 3 2. Is it possible for f (2) = 3 if limx→2 f (x) = 5? Yes. The function could be approaching y = 5 as x tends toward 2, but if there is a hole at this x-value and the function is piecewise defined to give the point (2, 3), the limit would not be equal to the function’s evaluation at that x-value. 3. If a ball is thrown into the air with a velocity of 40 ft/s, its height in feet t seconds later is given by y = 40t − 16t2 . (a) Find the average velocity for the time period beginning when t = 2 and lasting 1 second. s(b) − s(a) s(3) − s(2) = b−a 3−2 40(3) − 16(3)2 − 40(2) − 16(2)2 = 1 = 120 − 16(9) − 80 + 16(4) ms = = 40 − 16(9 − 4) = 40 − 16(5) = 40 − 80 = −40 ft/s (b) Estimate the instantaneous velocity when t = 2. s(t) − s(2) t−2 40t − 16t2 − 40(2) − 16(2)2 = lim t→2 t−2 mt = lim t→2 40t − 16t2 − 80 + 64 t→2 t−2 = lim −16t2 + 40t − 16 t→2 t−2 −8 2t2 − 5t + 2 = lim t→2 t−2 = lim = lim t→2 −8(2t − 1)(t − 2) t−2 = lim [−8(2t − 1)] t→2 = −8(4 − 1) = −24 ft/s